System.out.println(dog1.getName()); returning null


In short your "getter" is returning what the variable value you are giving it -> string(type) variable name = "unassigned". You will always tell it to set the variable named "name" to the String unassigned. try this

public void setName(String name) {
    this.name = name;
}

Additionally you would want to create a constructor and make it overall more efficient (constructors can get rid of the setters and what not). In full:

public class Main {
    public static void main(String[] args){

    Program3a testClass = new Program3a();

    testClass.setName("Rex");
        System.out.println(testClass.getName());
    }
}

public  class Program3a {
    private  String name;


    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }
}

Or the better looking constructor

public Program3a(String name) {
    this.name = name;
}

this will require you to update your tester class of course (I use main).

    Program3a testClass = new Program3a("Rex");

    System.out.println(testClass.getName());

Constructors are automatically created as a ghost. This being overridden can take in the parameters of variables and reduce un-needed coding. Once this is created you use line Program3a testClass = new Program3a("Rex"); to create a new class. The Rex now auto fills the variable Named and continues to use this value when testClass.getName() is called until altered.

Receive null when calling on a class, The problem is that dog1 object is created with the first Dog constructor public Dog(String name, String breed, char sex, int age, double weight){  System.out.println(dog1.getName()); returning null [duplicate] Ask Question Asked 1 month ago. Active 1 month ago. Viewed 48 times 0. This question


You made a mistake in setting the name in class Program3a. There should be this.name = name instead of name = "unassigned". So kindly replace this statement. Because the initial value of name is null set by the constructor by default. You have to assign it to the parameter name which is an input from Program3aTest class. Here is your code displaying "rex".

public class Program3a {
    private  String name;

   /* public Program3a(String name) {
        setName(name);
    }*/

    public  String getName() {
        return name;
    }      

    public void setName(String name) {
        this.name = name;      // change this statement in your code
    }



}

public class Program3aTest extends Program3a{
    public static void main(String[]args) {
        Program3aTest dog1 = new Program3aTest();
        dog1.setName("rex");

        System.out.println(dog1.getName());

    }
}

Assignment5.java, Getname() + " is " + dog1.Getage() + if (!dog1.Getadopt()) { System.out.print(" and is not adopted. n"); } //dog 3 maybe if((dog3!=null)){ System.out.print(dog3. Dog dog1 = new Dog("Pun"); System.out.println("Before modify: " + dog1.getName()); modifyReference(dog1); System.out.println("After modify: " + dog1.getName()); The method argument points to the same Dog object as the passed-in reference variable, thus the following output: Before modify: Pun After modify: Rex


Change the Program3a class like so:

public class Program3a {
    private  String name = "unassigned";

    public  String getName() {
        return name;
    }      

    public void setName(String name) {
        this.name = name;
    }
}

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