What is the best or simplest way to query the following
I need help with this problem.
Question: Write an SQL query that lists all the species found in the oldest zoo in America.
I tried the following, which worked, but I would like to know if there is a simpler way to do this. I spent hours on this question.
In the first block I created a new table I called "usaT", using the INTO clause, which only hold zoos with country USA. Click data base link to see image, please. Then i query this "usaT" table in the 2nd block of code.
Thanks for the help
SELECT * INTO usaT FROM zoos WHERE country='USA'; SELECT species FROM animals, usaT WHERE year_founded = (SELECT MIN(year_founded) FROM usaT) AND animals.zoo=usaT.city;
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Query would be:
Select s.* from animals a join zoos z on z.yearFounded=(Select min(year_founded) from zoos) and z.city=a.animals Join Species s on a.species=s.species
You should assign the unique identification number to each row of the all table for simplicity and use that as primary key & foreign key relation for joins.
More efficient SQL with query planning and optimization (article , Read and learn for free about the following article: More efficient SQL with query planning and optimization. For example, let's say we had this simple query: For this query, these are 2 different ways that SQL could find the results: out of place) and semantically correct (i.e. the tables exist), and returns errors if not. The way you structure your query and the way you write it goes a long way to communicate your intent to the fellow developer. When I see SQL queries on emails from multiple developers, I can see
select distinct species from animals a join zoos z on z.year_founded in (select min(year_founded) from zoos where country = 'USA') and a.zoo = z.city;
Hope this helps.
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