Cannot get the length of arr[] : Implicit conversion loses integer precision: 'unsigned long' to 'int' for strlen(arr)

implicit conversion loses integer precision: 'unsigned long' to 'int c
implicit conversion loses integer precision size_t' (aka 'unsigned long') to 'int
single-precision operand implicitly converted to double-precision
0 is an integer 0 can be implicitly converted to every pointer type it is known as
usual arithmetic conversions
loss of sign in promotion from int to unsigned int
c integer promotion rules
c integer promotion
Implicit conversion loses integer precision: 'unsigned long' to 'int'

I want to get the length of words[] but it shows me this. How can I fix it?

int main(int argc, const char * argv[]) {

    char test[] = "ls test";
    f_sparce_arg(test);
    return 0;
}
char * f_sparce_arg(char words[]){
    int words_length;
    words_length = strlen(words);   /* warning: Implicit conversion 
                                       integer precision: 'unsigned 
                                       long' to 'int' */

    printf("%d", words_length);
    return "";
}
// warning: Implicit conversion integer precision: 'unsigned long' to 'int'

What strlen function returns is size_t, so you should use it to store its return value.

char * f_sparce_arg(char words[]){
    size_t words_length; /* use proper type */
    words_length = strlen(words);

    printf("%zu",words_length); /* the format to print size_t value is %zu */
    return "";
}

Unfortunately, %zu format is not supported in some compilers or libraries. Another way is, if the string won't be so long, to cast the return value to int.

char * f_sparce_arg(char words[]){
    int words_length;
    words_length = (int)strlen(words); /* explicitly cast the result to avoid warnings */

    printf("%d",words_length);
    return "";
}

C++ help, The error message is Implicit conversion loses integer precision: 'size_type' (aka If you are basing all of that logic on string length, then why not make the type  Implicit conversions are automatically performed when a value is copied to a compatible type. In your case, trying int to size_t is also an implicit conversion. The reason why the warning mentions about the precision: size_t is always able to store more numbers than int. While size_t holds always a positive value, int can hold also negatives.


This is not an error and the code will work absolutely fine given you have added a function declaration and the preprocessor directives. it is a warning that your complier gives you that there might be some data altering in conversion as the conversion of unsigned to signed is specific to compiler and not language.

C have a data type size_t which is capable of storing the largest possible data size in C and is defined in several preprocessor like <stddef.h>, <stdio.h>, <stdlib.h>, <string.h>, <time.h>, <wchar.h> and is an alias for unsigned int in 32 bit compiler and is an alias for unsigned long long in a 64 bit compiler. It is a good practice to add additional information like unsigned and size_t for cross platform performance which is require while building a project.

INT31-C. Ensure that integer conversions do not result in lost or , Integer conversions, both implicit and explicit (using a cast), must be guaranteed not of a variable length array; The postfix expression preceding square brackets [] or the Otherwise, the new type is signed and the value cannot be represented in it; either the Noncompliant Code Example (Unsigned, Loss of Precision). - [NSData length] returns an NSUInteger, which is either an unsigned int (on 32 bit systems) or an unsigned long (on 64 bit systems). This value is being passed to a libxml function that is expecting an int , which I believe is always a 32 bit number.


I think you could just fix it by swap int into unsigned int. (Not perfect solution) An int variable may be a negative value, so it's not safe to assign any value to this variable. If you assign unsigned value to int, it may cause overflow, which is very dangerous.

Implicit conversions, Each argument of integer type undergoes integer promotion (see below), and each Otherwise: Both operands undergo implicit conversion to the unsigned If sizeof(long) == sizeof(long long), signed cannot represent all Any lvalue expression of any non-array type, when used in any context other than. I have a very latest checkout/clone of the repository. My target OS is iOS, which I managed to configure. I am getting about 72 compile warnings and I am concerned and doubtful about my steps in configuring to produce static lib.


Diagnostic flags in Clang, warning: no avr-gcc installation can be found on the system, cannot link standard libraries warning: implicit conversion loses integer precision: A to B  Implicit conversion loses floating-point precision&colon; "double" to "float"&semi; to repair&quest; advertisements I've downloaded the CMUnistrokeGestureRecognizer which appears to have a few errors, and Im trying to fix them, one of the errors is Implicit conversion loses floating point precision: 'double' to 'float' during this line of code;


4. Type Conversions - C in a Nutshell [Book], In the following example, the cast operator causes the division of one integer of losing information, as in a conversion from int to unsigned int , for example. fraction from type double to the type int , the new type simply cannot represent the When arithmetic operands have different types, the implicit type conversion is  Conversions. 07/01/2017; 47 minutes to read +1; In this article. A conversion enables an expression to be treated as being of a particular type. A conversion may cause an expression of a given type to be treated as having a different type, or it may cause an expression without a type to get a type.


Source/WTF/ChangeLog - chromium/blink, Make sure those three headers are copied with the rest of the WTF headers. heap entropy manually as the introspection process can't use the DateMath.​cpp:1005:40: error: implicit conversion loses integer precision: 'long' to 'int' [-​Werror,-Wshorten-64-to-32] MSVC will not compile array declarations of zero size. Implicit Conversion with the Implicit Operator. Widening conversions involve the creation of a new value from the value of an existing type that has either a more restrictive range or a more restricted member list than the target type. Widening conversions cannot result in data loss (although they may result in a loss of precision).