How do i crack this SQL Soccer Matches assignment?
I came across this problem recently, i'm a sql newbie preparing for an interview and i need some help understanding how to connect the tables without using joins (since there is no common column)to get the desired result
create table teams (team_id integer not null, team_name varchar(30) not null, unique(team_id) ); Team_id . Team_name 10 . Give 20 . Never 30 . You 40 . up 50 . Gonna create table matches (match_id integer not null, host_team integer not null, guest_team integer not null, host_goals integer not null, guest_goals integer not null, unique(match_id) ); Match_id Host_team Guest_team Host_goals Guest_goals 1 . 30 . 20 . 1 . 0 2 . 10 . 20 . 1 . 2 3 . 20 . 50 . 2 . 2 4 . 10 . 30 . 1 . 0 5 . 30 . 50 . 0 . 1
Compute the total number of points each team has scored after all the matches the rules are as follows
if a team wins a match(scores more goals than the other team) it gets 3 points.
if a team draws a match(scores exactly same number of goals as other team) it gets one point
if a team loses a match(scores fewer goals than other team) it gets no points.
write a query that returns a ranking of all teams(team_id) described in the table teams. for each team provide its name and number of points it received after all the matches(num_points). The table should be ordered by num_points in desc order. in case of a tie order the rows by team_id
Saw a solution that uses union all but it doesn't provide the answer, tried modifying it myself too.
select a.team_id,a.team_name,3*count(1) from teams a, matches b where a.team_id = b.host_team and b.host_goals > b.guest_goals group by a.team_id,a.team_name union all select a.team_id,a.team_name,count(1) from teams a, matches b where a.team_id = b.host_team and b.host_goals = b.guest_goals group by a.team_id,a.team_name union all select a.team_id,a.team_name,3*count(1) from teams a, matches b where a.team_id = b.guest_team and b.host_goals < b.guest_goals group by a.team_id,a.team_name union all select a.team_id,a.team_name,count(1) from teams a, matches b where a.team_id = b.guest_team and b.host_goals = b.guest_goals group by a.team_id,a.team_name; Solution should look like team_id team_name num_points 20 Never 4 50 Gonna 4 10 Give 3 30 You 3 40 Up 0
I suggest the following:
WITH cteHostPoints AS (SELECT HOST_TEAM AS TEAM, CASE WHEN HOST_GOALS > GUEST_GOALS THEN 3 WHEN HOST_GOALS = GUEST_GOALS THEN 1 ELSE 0 END AS POINTS FROM MATCHES), cteGuestPoints AS (SELECT GUEST_TEAM AS TEAM, CASE WHEN GUEST_GOALS > HOST_GOALS THEN 3 WHEN GUEST_GOALS = HOST_GOALS THEN 1 ELSE 0 END AS POINTS FROM MATCHES), cteAllPoints AS (SELECT TEAM, POINTS FROM cteHostPoints UNION ALL SELECT TEAM, POINTS FROM cteGuestPoints) SELECT t.TEAM_ID, t.TEAM_NAME, COALESCE(SUM(ap.POINTS), 0) AS TOTAL_POINTS FROM TEAMS t LEFT OUTER JOIN cteAllPoints ap ON ap.TEAM = t.TEAM_ID GROUP BY t.TEAM_ID, t.TEAM_NAME ORDER BY COALESCE(SUM(POINTS), 0) DESC, t.TEAM_ID
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select a.team_id, b.team_name, a.num_points from ( select a.team_id , sum(a.wins_point) as sum_wins_point , sum(a.draws_point) as sum_draws_point , sum(a.wins_point + a.draws_point) as num_points from ( select b.team_type , a.match_id , ( case when b.team_type = 'host' then a.host_team else a.guest_team end ) as team_id , ( case when b.team_type = 'host' then case when a.host_goals > a.guest_goals then 3 else 0 end else case when a.host_goals < a.guest_goals then 3 else 0 end end ) as wins_point , ( case when b.team_type = 'host' then case when a.host_goals = a.guest_goals then 1 else 0 end else case when a.host_goals = a.guest_goals then 1 else 0 end end ) as draws_point from matches a cross join ( select 'host' as team_type union all select 'guest' as team_type ) b ) a group by a.team_id ) a inner join teams b on a.team_id = b.team_id
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create table #teams (team_id integer not null, team_name varchar(30) not null, unique(team_id) ); insert #teams ( team_id , team_name ) values ( 10 , 'Give'), ( 20 , 'Never'), ( 30 , 'You' ), ( 40 , 'up' ), ( 50 , 'Gonna'); create table #matches (match_id integer not null, host_team integer not null, guest_team integer not null, host_goals integer not null, guest_goals integer not null, unique(match_id) ); insert #matches ( match_id , host_team , guest_team , host_goals , guest_goals ) values ( 1 , 30 , 20 , 1 , 0 ), ( 2 , 10 , 20 , 1 , 2 ), ( 3 , 20 , 50 , 2 , 2 ), ( 4 , 10 , 30 , 1 , 0 ), ( 5 , 30 , 50 , 0 , 1 ); with cte_1 as ( select match_id , host_team as team_id , host_goals as score , case when host_goals > guest_goals then 3 when host_goals = guest_goals then 1 else 0 end as points from #matches union all select match_id , guest_team as team_id , guest_goals as score , case when guest_goals > host_goals then 3 when host_goals = guest_goals then 1 else 0 end as points from #matches) , cte_2 as ( select team_id, sum(points) as points from cte_1 group by cte_1.team_id ) select * from #teams t left outer join cte_2 p on t.team_id = p.team_id order by p.points desc drop table #matches drop table #teams```
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You can try the query below:
SELECT T.team_id, T.Team_name, IFNULL( h_points, 0 ) + IFNULL( g_points, 0 ) AS 'Total Points' FROM teams T LEFT JOIN --- first sub-query calculating host_team points ( SELECT host_team, SUM( CASE WHEN Host_goals > Guest_goals THEN 3 WHEN Host_goals = Guest_goals THEN 1 WHEN Host_goals < Guest_goals THEN 0 END ) AS h_points FROM matches GROUP BY host_team ) H ON T.Team_id=H.host_team LEFT JOIN --- second sub-query calculating guest_team points ( SELECT guest_team, SUM( CASE WHEN Host_goals < Guest_goals THEN 3 WHEN Host_goals = Guest_goals THEN 1 WHEN Host_goals > Guest_goals THEN 0 END ) AS g_points FROM matches GROUP BY guest_team ) G ON T.Team_id=G.guest_team ORDER BY IFNULL( h_points, 0 ) + IFNULL( g_points, 0 ) DESC, t.team_id ASC;;
I took the approach of calculating host and guest points separately then being in a
LEFT JOIN from
teams table. On the outer query, I perform this formula
IFNULL( h_points, 0 ) + IFNULL( g_points, 0 ) to add up the host+guest teams points. The
IFNULL is to replace any
NULL value with 0 and the same formula I use for the
ORDER BY ... DESCENDING
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- " how to connect the tables without using joins" - but
JOINis the only way to connect tables. (The
FROM x, y WHERE x.z = y.zsyntax is the pre-SQL-92 syntax for trivial JOINs, it's obsolete and you should not use that syntax today).
- "since there is no common column" - what do you mean by "common column"? The
teams.team_idprimary-key column corresponds to the
matches.guest_teamforeign-key columns. You can
JOINon those (which is what your query is doing right now anyway - just using obsolete syntax instead of an explicit
- It seems like you'll only need the
teamstable to return the team name. Other than that, all of the other data are coming from
matchestable. In my opinion, you should work with
matchestable first to get the points tally.
- Works perfectly. Thanks
- Thanks for taking the time to give a step by step approach
- @NeverQuit101 No problem. I've updated my answer to fix some bugs btw.
- this works perfectly it just gets the order wrong at the end. The table should be ordered by num_points in desc order. in case of a tie order the rows by team_id. Trying to figure out the 2nd part of the order by clause.
- Then you just need to add
t.team_id ASC. I've updated my query ;)