How do i crack this SQL Soccer Matches assignment?

I came across this problem recently, i'm a sql newbie preparing for an interview and i need some help understanding how to connect the tables without using joins (since there is no common column)to get the desired result

create table teams
(team_id integer not null,
team_name varchar(30) not null,
unique(team_id)
);

Team_id .  Team_name
10 .       Give
20 .       Never
30 .       You
40 .       up
50 .       Gonna



create table matches 
(match_id integer not null,
host_team integer not null,
guest_team integer not null,
host_goals integer not null,
guest_goals integer not null,
unique(match_id)
);


Match_id   Host_team  Guest_team   Host_goals  Guest_goals
1 .        30 .       20 .         1 .         0 
2 .        10 .       20 .         1 .         2
3 .        20 .       50 .         2 .         2
4 .        10 .       30 .         1 .         0
5 .        30 .       50 .         0 .         1

Compute the total number of points each team has scored after all the matches the rules are as follows

if a team wins a match(scores more goals than the other team) it gets 3 points.

if a team draws a match(scores exactly same number of goals as other team) it gets one point

if a team loses a match(scores fewer goals than other team) it gets no points.

write a query that returns a ranking of all teams(team_id) described in the table teams. for each team provide its name and number of points it received after all the matches(num_points). The table should be ordered by num_points in desc order. in case of a tie order the rows by team_id

Saw a solution that uses union all but it doesn't provide the answer, tried modifying it myself too.

select a.team_id,a.team_name,3*count(1) from teams a, matches b
where a.team_id = b.host_team
and b.host_goals > b.guest_goals
group by a.team_id,a.team_name

union all

select a.team_id,a.team_name,count(1) from teams a, matches b
where a.team_id = b.host_team
and b.host_goals = b.guest_goals
group by a.team_id,a.team_name

union all

select a.team_id,a.team_name,3*count(1) from teams a, matches b
where a.team_id = b.guest_team
and b.host_goals < b.guest_goals
group by a.team_id,a.team_name

union all

select a.team_id,a.team_name,count(1) from teams a, matches b
where a.team_id = b.guest_team
and b.host_goals = b.guest_goals
group by a.team_id,a.team_name;






Solution should look like
team_id    team_name    num_points
20         Never        4
50         Gonna        4
10         Give         3
30         You          3
40         Up           0

I suggest the following:

WITH cteHostPoints AS (SELECT HOST_TEAM AS TEAM,
                              CASE
                                WHEN HOST_GOALS > GUEST_GOALS THEN 3
                                WHEN HOST_GOALS = GUEST_GOALS THEN 1
                                ELSE 0
                              END AS POINTS
                         FROM MATCHES),
     cteGuestPoints AS (SELECT GUEST_TEAM AS TEAM,
                               CASE
                                 WHEN GUEST_GOALS > HOST_GOALS THEN 3
                                 WHEN GUEST_GOALS = HOST_GOALS THEN 1
                                 ELSE 0
                               END AS POINTS
                          FROM MATCHES),
     cteAllPoints AS (SELECT TEAM, POINTS FROM cteHostPoints
                      UNION ALL
                      SELECT TEAM, POINTS FROM cteGuestPoints)
SELECT t.TEAM_ID, t.TEAM_NAME, COALESCE(SUM(ap.POINTS), 0) AS TOTAL_POINTS
  FROM TEAMS t
  LEFT OUTER JOIN cteAllPoints ap
    ON ap.TEAM = t.TEAM_ID
  GROUP BY t.TEAM_ID, t.TEAM_NAME
  ORDER BY COALESCE(SUM(POINTS), 0) DESC, t.TEAM_ID

dbfiddle here

sql - Modelling database for a small soccer league, you fetch 2 rows for every matches played but team_id and team_name are Using the match table as you describe captures the logic of a game simply and  SQL [61 exercises with solution] Sample Database: soccer. 1. Write a query in SQL to find the name of the venue with city where the EURO cup 2016 final match was played.

MySql Query.

select a.team_id, b.team_name, a.num_points
from (
select a.team_id
  , sum(a.wins_point) as sum_wins_point
  , sum(a.draws_point) as sum_draws_point
  , sum(a.wins_point + a.draws_point) as num_points
from (
select b.team_type
  , a.match_id
  , (
    case when b.team_type = 'host' then a.host_team else a.guest_team end 
  ) as team_id
  , (
    case when b.team_type = 'host' then
      case when a.host_goals > a.guest_goals then 3 else 0 end
    else 
      case when a.host_goals < a.guest_goals then 3 else 0 end
    end 
  ) as wins_point
  , (
    case when b.team_type = 'host' then
      case when a.host_goals = a.guest_goals then 1 else 0 end
    else 
      case when a.host_goals = a.guest_goals then 1 else 0 end
    end 
  ) as draws_point
from matches a
cross join (
  select 'host' as team_type 
  union all
  select 'guest' as team_type 
) b
) a
group by a.team_id
) a
inner join teams b on a.team_id = b.team_id

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create table #teams
(team_id integer not null,
team_name varchar(30) not null,
unique(team_id)
);

insert #teams (
   team_id
 , team_name
)
values
(  10 , 'Give'),
(  20 , 'Never'),
(  30 ,  'You' ),
(  40 ,  'up'  ),
(  50 ,  'Gonna');



create table #matches 
(match_id integer not null,
host_team integer not null,
guest_team integer not null,
host_goals integer not null,
guest_goals integer not null,
unique(match_id)
);

insert #matches (
   match_id
 , host_team
 , guest_team
 , host_goals
 , guest_goals
)
values
(  1 , 30 , 20 , 1 , 0 ),
(  2 , 10 , 20 , 1 , 2 ),
(  3 , 20 , 50 , 2 , 2 ),
(  4 , 10 , 30 , 1 , 0 ),
(  5 , 30 , 50 , 0 , 1 );

with
      cte_1 as (
         select match_id
            ,  host_team as team_id
            ,  host_goals as score
            ,  case
                  when host_goals > guest_goals then 3
                  when host_goals = guest_goals then 1
                  else 0
               end as points
            from #matches 
         union all
         select match_id
            ,  guest_team as team_id
            ,  guest_goals as score
            ,  case
                  when guest_goals > host_goals then 3
                  when host_goals = guest_goals then 1
                  else 0
               end as points
            from #matches)
   ,  cte_2 as (
         select 
            team_id,
            sum(points) as points
            from cte_1
            group by cte_1.team_id
      )
select * 
   from #teams t
   left outer join cte_2 p on t.team_id = p.team_id
   order by p.points desc


drop table #matches
drop table #teams```

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You can try the query below:

SELECT
    T.team_id,
    T.Team_name,
    IFNULL( h_points, 0 ) + IFNULL( g_points, 0 ) AS 'Total Points' 
FROM
    teams T 
    LEFT JOIN
    --- first sub-query calculating host_team points
    (
        SELECT
            host_team,
            SUM(
                CASE
                    WHEN Host_goals > Guest_goals THEN 3
                    WHEN Host_goals = Guest_goals THEN 1
                    WHEN Host_goals < Guest_goals THEN 0
                END
            ) AS h_points 
        FROM
            matches 
        GROUP BY
            host_team
    ) H ON T.Team_id=H.host_team 
    LEFT JOIN
    --- second sub-query calculating guest_team points
    (
        SELECT
            guest_team,
            SUM(
                CASE
                    WHEN Host_goals < Guest_goals THEN 3
                    WHEN Host_goals = Guest_goals THEN 1
                    WHEN Host_goals > Guest_goals THEN 0
                END
            ) AS g_points 
        FROM
            matches 
        GROUP BY
            guest_team
    ) G ON T.Team_id=G.guest_team 
ORDER BY
    IFNULL( h_points, 0 ) + IFNULL( g_points, 0 ) DESC, t.team_id ASC;;

I took the approach of calculating host and guest points separately then being in a LEFT JOIN from teams table. On the outer query, I perform this formula IFNULL( h_points, 0 ) + IFNULL( g_points, 0 ) to add up the host+guest teams points. The IFNULL is to replace any NULL value with 0 and the same formula I use for the ORDER BY ... DESCENDING

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Comments
  • " how to connect the tables without using joins" - but JOIN is the only way to connect tables. (The FROM x, y WHERE x.z = y.z syntax is the pre-SQL-92 syntax for trivial JOINs, it's obsolete and you should not use that syntax today).
  • "since there is no common column" - what do you mean by "common column"? The teams.team_id primary-key column corresponds to the matches.host_team and matches.guest_team foreign-key columns. You can JOIN on those (which is what your query is doing right now anyway - just using obsolete syntax instead of an explicit JOIN).
  • It seems like you'll only need the teams table to return the team name. Other than that, all of the other data are coming from matches table. In my opinion, you should work with matches table first to get the points tally.
  • Works perfectly. Thanks
  • Thanks for taking the time to give a step by step approach
  • @NeverQuit101 No problem. I've updated my answer to fix some bugs btw.
  • this works perfectly it just gets the order wrong at the end. The table should be ordered by num_points in desc order. in case of a tie order the rows by team_id. Trying to figure out the 2nd part of the order by clause.
  • Then you just need to add t.team_id ASC. I've updated my query ;)