Querying the Team names with more than a half wins (Database contains Home and Away Column for results)
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I have a table (Meetings) which contains the following columns:
For the scores (Example: 3:2).
My problem is that I need to output all teams which have more than a half wins.
The code provided is working perfect, but it is only for the Home Wins and I need a sum of both Home and Away, because for example, 'Liverpool' has three Home games and two Away games and I need from both sides scores.
SELECT Team, COUNT(*) AS HomeWins FROM Teams JOIN Meetings ON Team = Meetings.HomeTeam AND Meetings.Home > Meetings.Away GROUP BY Team
The expected output is (from 6 teams I have two teams which have 3 wins and the other one - 4) to output the teams with more than a half wins and their wins total.
Team Wins Liverpool 4 PSG 3
If you just want wins, you can use:
select t.*, (select count(*) from meetings m where (m.hometeam = t.team and m.home > m.away) or (m.awayteam = t.team and m.away > m.away) ) as num_wins from team t;
Note: This returns all teams, even those who have not won any games.
SQL exercises on soccer Database, Practice with solution of exercises on SQL soccer database, INNER JOIN, NON EQUI JOIN, subqueries on soccer database, and more from w3resource. column of soccer_country table; team_group – the name of the group in decided_by – how the result of the match has been decided, either N for by Data is being gathered and created at rates unprecedented in history. Much of this data is intended to drive business outcomes but, according to the Harvard Business Review, “…on average, less than half of an organization’s structured data is actively used in making decisions…” The root of the problem is that data is typically spread […]
You just need to query the results twice, inverting the query and using UNION to create a combined view.
create table #meetings (HomeTeam varchar(20), AwayTeam varchar(20), Home int, Away int); insert into #meetings (HomeTeam, AwayTeam, Home, Away) values ('Trumpton', 'Camberwick Green', 1, 0), -- Trumpton win ('Chigley', 'Camberwick Green', 3, 2), -- Chigley win ('Trumpton', 'Chigley', 3, 1), -- Trumpton win ('Camberwick Green', 'Trumpton', 0, 2), -- Trumpton win ('Camberwick Green', 'Chigley', 1, 2) -- Chigley win /* Trumpton - played 3, won 3 Camberwick Green - played 4, won 0 Chigley - played 3, won 2 */ select Team ,count(*) as Played ,sum(Win) as Wins from ( select HomeTeam as Team ,case when Home > Away then 1 else 0 end as Win from #meetings union all select AwayTeam as Team ,case when Away > Home then 1 else 0 end as Win from #meetings ) results
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From what I understand, you want to return info for teams that have more wins than losses. If that's correct here is one way to do it:
-- Build cte to re-use query WITH meetings(WinningTeam, LosingTeam) AS ( SELECT CASE WHEN Home > Away THEN HomeTeam ELSE AwayTeam END AS WinningTeam, CASE WHEN Home > Away THEN AwayTeam ELSE HomeTeam END AS LosingTeam FROM Meetings ) SELECT teams.Team, wins.win_count AS Wins FROM teams LEFT JOIN ( SELECT WinningTeam, COUNT(*) AS win_count FROM Meetings GROUP BY 1 ) wins ON teams.team = wins.WinningTeam -- Get wins per team LEFT JOIN ( SELECT LosingTeam, count(*) AS loss_count FROM Meetings GROUP BY 1 ) losses ON teams.team = wins.LosingTeam -- Get wins per team WHERE win_count > loss_count -- Only return teams with winning records
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- See Why should I provide a Minimal Reproducible Example for a very simple SQL query? ... Also you need to tag a RDMS product, the sql tag on this website does not mean a RDMS product but the ANSI/ISO SQL standard..
- Tag your question with the database you are using.
- Thanks man, this works perfectly, but I need to filter the teams which from 5 games have less than 3 won games. For example: Barcelona 1W, Bayern 3W, Juventus 1W, Liverpool 4W, ManUnited 2W, PSG 3W. I want to get only Bayern, Liverpool and PSG.
- @S1C4R10 . . . I would suggest that you ask a new question, which is more specific on your actual needs.