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This has been bugging me a lot. It is a simple function to detect a prime number but I'm not getting any output on my console, despite there being no compilation errors. Can someone please detect what is wrong with this code?

#include<stdio.h>
int isprime(int);

int main()
{
    int n;
    scanf("%d", &n);

    if (isprime(n))
        printf("Yes");
    else
        printf("No");

    return 0;
}

int isprime(int num)
{
    int flag = 1;

    for(int i = 2; i <= num/2; i++)
    {
        if(num % i == 0)
        {
            flag = 0;
            break;
        }
    }

    return flag;
}

There's nothing wrong with the program. The output is not formatted well due to missing new lines, so perhaps by adding them you'd be able to see something as the output may be right at the beginning of the console prompt.

int n;
printf("Input a number: ");
scanf("%d", &n);

if (isprime(n))
    printf("Yes\n");
else
    printf("No\n");

showing no compile errors but no output, C program with arrays - showing no compile errors but no output EPL*/ #define NAME_LENGTH 12 /*Maximum length for any team name*/ #define EOF){ /*If name inputted is not an EPL team name from the first dataset  I do get some output. How are you compiling this code? – dasblinkenlight Dec 16 '15 at 17:36 Are you linking in max_subarray_data.o (compilation of max_subarray_data.c )?

For starters the function isprime is invalid. It returns 1 for the non-prime number 1.:)

And the function should be declared at least like

int isprime( unsigned int num );

As for your question then the output buffer is not flushed until the new line character is not encountered.

Write instead

if (isprime(n))
    printf("Yes\n");
else
    printf("No\n");

or

if (isprime(n))
    puts("Yes");
else
    puts("No");

My C program is correct, with no errors or warnings, but the compiler , My C program is correct, with no errors or warnings, but the compiler (after inputting everything) is showing "Standard output is empty". Why? aGsmdns Is it possible to write a C compiler in Java if you know Java but not C? 9,809 Views You dont need to put any ', ' in between the %d in scanf statement. I think the only  Logical Errors : On compilation and execution of a program, desired output is not obtained when certain input values are given. These types of errors which provide incorrect output but appears to be error free are called logical errors. These are one of the most common errors done by beginners of programming.

I bet you don't see the output but it is shown. There is no new line and command prompt follows the answer like NoC:\> instead of C:\>.

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Comments
  • How did you run the program? What input did you provide? Note that you program starts by requiring some user input without printing any prompt beforehand.
  • Your output does not contain a newline. If your PS1 moves the cursor to beginning of line, then your prompt very likely overwrites the output.
  • It works for me. Note that since you didn't end your printf with a newline, the output will be on same line as your next shell prompt, so you might not see it.
  • It seems you are having problems understanding the behavior of the program. As mentioned by @uneven_mark, we need to know how you are running the program (e.g., what command you use to run the program, what input are you providing to the program) to gain more understanding into what behavior you are encountering. And, it might also matter what your environment is (operating system, and compiler).
  • Yeah, it was a noob move. Thanks for the clarification though!