overload == to compare two linked list recursively

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I have a homework problem, which asks me to overload == operator to compare two linked-list. And i need to do this in recursion.

Here is my .h file

class  LList {
   public:
      friend bool operator == (const LList& lfSide, const LList& rtSide);
   private:
      struct Node {
         int item;
         Node* next;
      };
      friend bool operator == (const LList& lfSide, Node* headlf, const LList& rtSide, Node* headrt);
      Node* head;
}

I tried to use a helper function to make the recursion happen, but it still gives error saying Node is not defined.

friend bool operator == (const LList& lfSide, Node* headlf, const LList& rtSide, Node* headrt);

Can anyone help me with this?


The structure Node is a private data member, It may not be used in the friend declaration

friend bool operator == (const LList& lfSide, Node* headlf, const LList& rtSide, Node* headrt);

You could define the structure like

#include <iostream>
class  LList {
   public:
      friend bool operator == (const LList& lfSide, const LList& rtSide);
   private:
      struct Node {
         int item;
         Node* next;
         bool operator ==( const Node &headrt);
      };
      Node* head;
};

And within the friend operator use the operator == of the structure Node.

Identical Linked Lists, are identical. . Write a function to check if the given two linked lists are identical. To identify if two lists are identical, we need to traverse both lists simultaneously, and while traversing we need to compare data. C++; C return (​a == NULL && b == NULL); Recursive solution code is much cleaner than the iterative code. Two Linked Lists are identical when they have same data and arrangement of data is also same. For example Linked lists a (1->2->3) and b(1->2->3) are identical. . Write a function to check if the given two linked lists are identical.


One more approach could be to have only one argument passed to operator == as this is passed implicitly.Here is complete code

template <typename T>
struct Node
{
    T data;
    Node<T>* next;
};
template <class T>
class LinkedList
{
private:
    Node<T>* head;  

    bool internalCompare(Node<T>* first, Node<T>* second)
    {
        if((first == nullptr) && (second == nullptr))
        {
            return true;
        }
        else if(((first == nullptr) && (second != nullptr)) || ((first != nullptr) && (second == nullptr)))
        {
            return false;
        }
        else if (first->data != second->data)
        {
            return false;
        }
        return internalCompare(first->next,second->next);
    }
public:
    LinkedList() :head(nullptr) {}      
    bool operator ==(LinkedList<T> & second)
    {
        if(internalCompare(head,second.head))
        {
            return true;
        }
        return false;
    }
};

Recursion on Linked Lists, This is natural, because linked lists can themselves be defined recursively: public static int sum (LN l) { if (l == null) return 0; else return l.value + sum(l.next); } Notice that the only difference between the two methods (besides their overloading the public method with a different private prototype for the helper method. `std::sort` uses `operator. ` to compare the elements of the vector.. A operator is all that's needed to sort lists, as you've seen in the lesson about sorting.There appears to be some general confusion about how `std::sort` works.


This might help you. I kept the things simple by making some member variables as public.

class Node
{
public:
    int m_Value = -1;
    Node* m_Next = nullptr;
    Node()
    {
        m_Value = -1;
        m_Next = NULL;
    }
};

//Linked List class
class LinkedList
{
    //Head Node
    Node* m_Head;
    //Tail Node
    Node* m_Last;

public:
    //Constructor
    LinkedList()
    {
        m_Head = nullptr;
        m_Last = nullptr;
    }
    //Add value to list
    void AddValue(int value)
    {
        if (m_Head == nullptr)
        {
            m_Head = new Node();
            m_Head->m_Value = value;
            m_Last = m_Head;
        }
        else
        {
            Node* newNode = new Node();
            newNode->m_Value = value;
            m_Last->m_Next = newNode;
            m_Last = newNode;
        }
    }

    //Display the elements of the list
    void display()
    {
        Node* travelNode = m_Head;
        while (travelNode != nullptr)
        {
            cout << travelNode->m_Value << " ==> ";
            travelNode = travelNode->m_Next;
        }
    }

    //Compare function
    bool operator==(const LinkedList& List)
    {
        return CompareList(this->m_Head, List.m_Head);
    }

    bool CompareList( Node* LeftList,  Node* rightList)
    {
        //If both nodes reaches to end then it is equal
        if (LeftList == nullptr && rightList == nullptr) return true;

        //If one of the node has more nodes then list are not equal
        if (LeftList == nullptr || rightList == nullptr) return false;

        //Compare the values
        if (LeftList->m_Value != rightList->m_Value) return false;

        //Call recursion
        CompareList(LeftList->m_Next, rightList->m_Next);
    }
};

int main()
{
    //First List
    LinkedList list1;
    list1.AddValue(1);
    list1.AddValue(2);
    list1.AddValue(3);
    list1.AddValue(4);
    list1.AddValue(5);

    //list1.display();

    //Second List
    LinkedList list2;
    list2.AddValue(1);
    list2.AddValue(2);
    list2.AddValue(3);
    list2.AddValue(4);
    list2.AddValue(5);

    //list2.display();

    //Compare
    bool areEq = list1 == list2;
    cout << "Are Equal " << areEq << endl;
}

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