## overload == to compare two linked list recursively

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I have a homework problem, which asks me to overload == operator to compare two linked-list. And i need to do this in recursion.

Here is my .h file

class  LList {
public:
friend bool operator == (const LList& lfSide, const LList& rtSide);
private:
struct Node {
int item;
Node* next;
};
friend bool operator == (const LList& lfSide, Node* headlf, const LList& rtSide, Node* headrt);
}

I tried to use a helper function to make the recursion happen, but it still gives error saying Node is not defined.

friend bool operator == (const LList& lfSide, Node* headlf, const LList& rtSide, Node* headrt);

Can anyone help me with this?

The structure Node is a private data member, It may not be used in the friend declaration

friend bool operator == (const LList& lfSide, Node* headlf, const LList& rtSide, Node* headrt);

You could define the structure like

#include <iostream>
class  LList {
public:
friend bool operator == (const LList& lfSide, const LList& rtSide);
private:
struct Node {
int item;
Node* next;
bool operator ==( const Node &headrt);
};
};

And within the friend operator use the operator == of the structure Node.

Identical Linked Lists, are identical. . Write a function to check if the given two linked lists are identical. To identify if two lists are identical, we need to traverse both lists simultaneously, and while traversing we need to compare data. C++; C return (​a == NULL && b == NULL); Recursive solution code is much cleaner than the iterative code. Two Linked Lists are identical when they have same data and arrangement of data is also same. For example Linked lists a (1->2->3) and b(1->2->3) are identical. . Write a function to check if the given two linked lists are identical.

One more approach could be to have only one argument passed to operator == as this is passed implicitly.Here is complete code

template <typename T>
struct Node
{
T data;
Node<T>* next;
};
template <class T>
{
private:

bool internalCompare(Node<T>* first, Node<T>* second)
{
if((first == nullptr) && (second == nullptr))
{
return true;
}
else if(((first == nullptr) && (second != nullptr)) || ((first != nullptr) && (second == nullptr)))
{
return false;
}
else if (first->data != second->data)
{
return false;
}
return internalCompare(first->next,second->next);
}
public:
bool operator ==(LinkedList<T> & second)
{
{
return true;
}
return false;
}
};

Recursion on Linked Lists, This is natural, because linked lists can themselves be defined recursively: public static int sum (LN l) { if (l == null) return 0; else return l.value + sum(l.next); } Notice that the only difference between the two methods (besides their overloading the public method with a different private prototype for the helper method. `std::sort` uses `operator. ` to compare the elements of the vector.. A operator is all that's needed to sort lists, as you've seen in the lesson about sorting.There appears to be some general confusion about how `std::sort` works.

This might help you. I kept the things simple by making some member variables as public.

class Node
{
public:
int m_Value = -1;
Node* m_Next = nullptr;
Node()
{
m_Value = -1;
m_Next = NULL;
}
};

{
//Tail Node
Node* m_Last;

public:
//Constructor
{
m_Last = nullptr;
}
//Add value to list
{
if (m_Head == nullptr)
{
m_Head = new Node();
}
else
{
Node* newNode = new Node();
newNode->m_Value = value;
m_Last->m_Next = newNode;
m_Last = newNode;
}
}

//Display the elements of the list
void display()
{
Node* travelNode = m_Head;
while (travelNode != nullptr)
{
cout << travelNode->m_Value << " ==> ";
travelNode = travelNode->m_Next;
}
}

//Compare function
bool operator==(const LinkedList& List)
{
}

bool CompareList( Node* LeftList,  Node* rightList)
{
//If both nodes reaches to end then it is equal
if (LeftList == nullptr && rightList == nullptr) return true;

//If one of the node has more nodes then list are not equal
if (LeftList == nullptr || rightList == nullptr) return false;

//Compare the values
if (LeftList->m_Value != rightList->m_Value) return false;

//Call recursion
CompareList(LeftList->m_Next, rightList->m_Next);
}
};

int main()
{
//First List

//list1.display();

//Second List

//list2.display();

//Compare
bool areEq = list1 == list2;
cout << "Are Equal " << areEq << endl;
}

Statistical Computing in C++ and R, Show that the probability that ai and aj are compared during a complete code for the recursive mergesort Algorithm 9.7 for arrays from Section 9.2.1. 9.8. Write the code for the overloaded = operator for the linkedList class of Section 9.2​.2. Write the code for the copy constructor and overloaded = and == operators for  C++ program to compare two Strings using Operator Overloading Pre-requisite: Operator Overloading in C++ Given two strings, how to check if the two strings are equal or not, using Operator Overloading.

A Laboratory Course in C++ Data Structures, types (ADTs), function and Recommendation:Suggested operator overloading. 2 Point List Simple list and cursor concept, simple OpenGL graphics Prerequisite: Lab 7 9 Doubly-Linked List Efficiency comparison with singly-linked list. Recommendation: Optional 10 Recursion Recursive problems using linked lists,  I'm trying to overload the assignment operator. The objective is to copy two linked lists. I copy the first element fine, but for some reason the second loop around I encounter a null pointer and my loop ends on me.

C++ Plus Data Structures, 465–469 Print function, 483-484 traversals, 490–496 Recursive calls, 400, 405​, 407-408 Recursive linked list processing, 412–416 Recursive (or general) case, 384–386 overloading, 127, 189 RelationType, 90, 188 Reliability increasing, 2 Requirements elicitation, 2 Requirements verification, 50 Reserved words,  For example operator + is used to add two integers as well as join two strings and merge two lists. It is achievable because ‘+’ operator is overloaded by int class and str class. You might have noticed that the same built-in operator or function shows different behavior for objects of different classes, this is called Operator Overloading.