Powershell posh-ssh: How to store results of Invoke-SSHCommand?
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How can I store the result of
Invoke-SSHCommand for use after I close the connection?
I've tried 2 different ways:
#method 1 $result = Invoke-SSHCommand -Index 0 -Command "ls /somepath" #method 2 Invoke-SSHCommand -Index 0 -Command "ls /somepath" -OutVariable $result
$result is empty after both methods
This worked well for me :
# Create SSH Session $ssh = New-SSHSession -ComputerName $PC01 -Credential $credential -AcceptKey 1 # Invoke SSH command and capture output as string (you can return the full object if you like, I just needed the string Out) $ret = $(Invoke-SSHCommand -SSHSession $ssh -Command "racadm getconfig -g cfgUserAdmin -i 2").Output # return object is a String - if you want it as an array of strings for each row returned $ret = $ret.split("`n")
how to convert output from invoke-sshcommand to table? · Issue , Hi Guru, using invoke-sshcommand I was issuing such as lsblk to linux, the output looks like the below, it has multi ple lines of darkoperator / Posh-SSH thank you, looks like no existing cmdlet in powershell help to parse it? $outputs = (Invoke-SSHCommand -SSHSession $s -Command lsblk).output. Posh-SSH: Open Source SSH PowerShell Module or sessions using the Invoke-SSHCommand command. When a command is executed an object representing the results of the
This was working for me:
#method 1 $CurrentSession=New-SSHSession -ComputerName x.x.x.x -Credential (Get-Credential) $result = Invoke-SSHCommand -SSHSession $CurrentSession -Command "ls /somepath" $result.Output
Using PowerShell For SSH Script Execution, Posh-SSH is now installed automatically if not installed already $Port } # Store the output of the command $Output = (Invoke-SSHCommand Introduction. The following script allows you to execute SSH script using an EXE/Script sensor. It will connect to the server, execute the given command and simply return the output to the sensor.
$ from your
-OutVariable $result and it should work.
Invoke-SSHCommand -Index 0 -Command "ls /somepath" -OutVariable result
$result in the command was being processed, returning null, then trying to output the results of Invoke-SSHCommand to null as far as I can tell
Posh-SSH: Open Source SSH PowerShell Module – PowerShell , Posh-SSH is a PowerShell 3.0 or newer module for automating tasks against Output : ExitStatus : 0. PS C:\> Invoke-SSHCommand -Index 0 PS C:\> Invoke-SSHCommand -Command "uname -a" -Index 0,2,3 Host : 192.168.1.163 Output : Linux debian6 2.6.32-5-amd64 #1 SMP Sun Sep 23 10:07:46 UTC 2012 x86_64 GNU/Linux
Posh-SSH to automate Linux hosts using PowerShell, For Posh-SSH the equivalent to Invoke-Command is Invoke-SSHCommand. Each command is returned with two properties. Output [string SSH From Windows Server to Linux Server – Invoke-SSHCommand Welcome › Forums › General PowerShell Q&A › SSH From Windows Server to Linux Server – Invoke-SSHCommand This topic has 1 reply, 1 voice, and was last updated 4 years, 6 months ago by
Help using PS to Log into routers and save output of show , There is a module called Posh-SSH CreateShellStream("PS-SSH", 0, 0, 0, 0, 100) $user = Invoke-SSHCommand $s -Command "whoami" $SSHusersName Getting file metadata with PowerShell similar to what Windows Explorer provides. I am having some issues getting command to work with posh-ssh and Cisco gear. Commands are pretty simple; New-SSHSession -ComputerName 10.10.101.240 -Port 22 Will connect fine, and will give me an ID. I then try . Invoke-SSHCommand -SessionId 0 -Command "show version" but I always get
PoSH-SSH, PowerShell – Using PoSH SSH Module to shutdown a Synology NAS. Shutting Keep in mind that in order to run 'sudo' commands you need to use $result = Invoke-SSHCommand -Index 0 -Command "uname -a; cd /; pwd; ls /volume1". What I noticed when working with posh-ssh and ubuntu was I was failing to sudo up to root using "sudo su -" due to the ExpectString. It was expecting "[sudo] password for (username):" and I was merely providing "password:"
- have you tried this:
Invoke-SSHCommand -Index 0 -Command "ls /somepath" 2>&1
- @Adam: Accept the answer if it helps you.
- My pleasure to help @Adam. :)
- At the end should be $result instead of "result" that is not a var name on PS.