Compare 2 different arrays with same indexer but different amount of values in

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looking for your help.

I do have 2 arrays

a = [["01000340001001", 0, 1122, "Triju vai vair─üku dz─½vok─╝u m─üjas", "Dz─½vojam─ü ─ōka", 27, "Aleksandra ─īaka iela 110, R─½ga"], ["01000340002001", 0, 1122, "Triju vai vair─üku dz─½vok─╝u m─üjas", "Dz─½vojam─ü ─ōka", 15, "Aleksandra ─īaka iela 108, R─½ga"], ["01000340002002", 0, 1122, "Triju vai vair─üku dz─½vok─╝u m─üjas", "Dz─½vojam─ü ─ōka", 4, "Aleksandra ─īaka iela 108, R─½ga"], ["01000340002005", 0, 1252, "Noliktavas, rezervu─üri, bunkuri un silosi", "Noliktava", 1, "Aleksandra ─īaka iela 108B, R─½ga"], ["01000340002006", 0, 1252, "Noliktavas, rezervu─üri, bunkuri un silosi", "Noliktava", 1, "Aleksandra ─īaka iela 108, R─½ga"], ["01000340002006", 0, 1252, "Noliktavas, rezervu─üri, bunkuri un silosi", "Noliktava", 1, "Aleksandra ─īaka iela 108B, R─½ga"], ["01000340002008", 0, 1274, "Citas, iepriek┼Ī neklasific─ōtas, ─ōkas", "Nojume", 0, nil]]

Another one

b = [["01000340002001", 0, 1122, "Triju vai vair─üku dz─½vok─╝u m─üjas", "Dz─½vojam─ü ─ōka", 15], ["01000340002002", 0, 1122, "Triju vai vair─üku dz─½vok─╝u m─üjas", "Dz─½vojam─ü ─ōka", 4], ["01000340002006", 0, 1252, "Noliktavas, rezervu─üri, bunkuri un silosi", "Noliktava", 1]]

I need to remove from a those arrays, that are in b by indexers as i think(e.g. remove duplicated).

What i was trying is to do this

all = []
all = a.collect {|key, value | key} - b.collect {|key, value | key}
# ["01000340002005", "01000340001001", "01000340002008"]

And then select arrays that i need

a.select { |key, value| key == b }
# ["01000340002008", 0, 1274, "Citas, iepriek┼Ī neklasific─ōtas, ─ōkas", "Nojume", 0, nil]

As outcome i get only 1 array, but should 3.

Could someone please suggest me how to make it work? :)

Try this:

b_indexes = b.map(&:first)
a.delete_if { |arr| b_indexes.include?(arr.first) }
#~> [
      ["01000340001001", 0, 1122, "Triju vai vair─üku dz─½vok─╝u m─üjas", "Dz─½vojam─ü ─ōka", 27, "Aleksandra ─īaka iela 110, R─½ga"],
      ["01000340002005", 0, 1252, "Noliktavas, rezervu─üri, bunkuri un silosi", "Noliktava", 1, "Aleksandra ─īaka iela 108B, R─½ga"],
      ["01000340002008", 0, 1274, "Citas, iepriek┼Ī neklasific─ōtas, ─ōkas", "Nojume", 0, nil]
    ]

Compare same index of two array having same length, If you want to receive array with boolean values which indicates if this is called lexicographical comparison and is built-in for arrays in other  When you compare those two arrays, you're comparing the objects that represent the arrays, not the contents. You'll have to use a function to compare the two. You could write your own that simply loops though one and compares it to the other after you check that the lengths are the same.

It seems that elements of a differs from elements of b for having a string more as last element.

So, you could just Array#reject! comparing the whole element of b:

a.reject! { |e| b.include? e[0...-1] }

But if only the first element of each nested array is the signal, mapping b against the first element before and then rejecting elements based on that map is the correct way.

Note that Array#reject! affects the original array.

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assoc is nice for this:

p b.map{|ar| a.assoc(ar.first)}

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