How to get yesterday and day before yesterday in linux?
I want to get sysdate -1 and sysdate -2 in variable and echo it. I am using below query which gives todays date as output.
#! /bin/bash tm=$(date +%Y%d%m) echo $tm
How to get yesterday and day before yesterdays date?
Here is another one way,
date -d '-1 day' '+%Y%d%m'
For day before yesterday,
date -d '-2 day' '+%Y%d%m'
Getting Yesterdays or Tomorrows Day With Bash Shell Date , I have Solaris 9 & 10, redhat and centos system (i don't do windows). The 2 days ago option worked on each, though i do admit the day before yesterday wasn't� For older versions of BSD date (on old versions of macOS for example) which don't provide a -v option, you can get yesterdays date by subtracting 86400 seconds (seconds in a day) from the current epoch. date -r $(( $(date '+%s') - 86400 )) Obviously, you can subtract 2 * 86400 away for the day for yesterday etc.
YES_DAT=$(date --date=' 1 days ago' '+%Y%d%m')
Day before yesterdays date
DAY_YES_DAT=$(date --date=' 2 days ago' '+%Y%d%m')
For any date you can use below one default it take 1 days. If its passing value that day before it take
ANY_YES_DAT=$(date --date=' $1 days ago' '+%Y%d%m')
Day before yesterday's date - UNIX and Linux Forums, What if you want get several days, for example day before 5 days? date +%Y-%m -%d -d "5 day ago". Would you take yesterday date to variable? YESTERDAY� To get yesterday and earlier day in the past use string day ago: date --date = 'yesterday' date --date = '1 day ago' date --date = '10 day ago' date --date = '10 week ago' date --date = '10 month ago' date --date = '10 year ago'
You can get the yesterday date by this:
date -d "yesterday 13:00 " '+%Y-%m-%d'
and day before yesterday by this:-
date -d "yesterday-1 13:00 " '+%Y-%m-%d'
bash how to get yesterday's date, Hello All, I am writing a script in Sun Solaris I want the date for "day before yesterday", i got the yesterday's date by this command Code : TZ=GMT+24 date +%b" "%d
For older versions of BSD date (on old versions of macOS for example) which don't provide a
-v option, you can get yesterdays date by subtracting 86400 seconds (seconds in a day) from the current epoch.
date -r $(( $(date '+%s') - 86400 ))
Obviously, you can subtract 2 * 86400 away for the day for yesterday etc.
Edit: Add reference to old macOS versions.
To get yesterday, subtracting 86400 seconds and scalar prints it in human readable format. I assume you just need yesterday in DAY MON DT format, so you could grep all lines matching that day, irrespective of time. To just grab required fields, using substr to print the first 10 characters and saving in dt variable.
Re: [solved] grep today, yesterday & the day before ooooh, ok, that made it easier than what I had in mind in the beginning, thanks. I guess I should just have read the whole date manpage.
[admin@devopsrun1 ~]$ date Thu Nov 7 02:30:08 EST 2019 [admin@devopsrun1 ~]$ cat date.sh #!/bin/bash # printing day before yesterday date in unix shell script
This bash function will work on both Linux and OSX. Basically it tries the GNU Linux style first. If that fails it tries the OSX style. Call it with an argument of the number of days in the past you want the date. If you pass no argument it assume 0 days. This code is a one-liner, so cut and paste should work -- no line endings assumed.
date -d"yesterday -1 day"work to you?
- Please use YYYY-mm-dd xkcd.com/1179
- Note that the BSD
datecommand (like macOS has) uses the
-vswitch for this. So
date -v '-1d' '+%Y%d%m'would do what you want.
- Sane version (iso 8601):
date -v '-1d' '+%Y-%m-%d'
- Exactly what I was looking for
yesterday -1not working in RHEL 7.1, only
date -d "yesterday -1 day"