Non-repetitive random number in asp.net C#

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I have 6 question in 6 asp.net panel server control , I need to show them all panel one by one in random order( one question is visible and other invisible every time ).

I don't know how to exclude the number from generating again . I write like this :

    protected void Page_Load(object sender, EventArgs e)
        {
            if (!IsPostBack)
            {
                Random rnd = new Random();
                int startNumber = rnd.Next(1, 6);
                ShowNextPanel(startNumber);
            }
        }

    private void ShowNextPanel(int excludeNumber)
    {
        Random rnd = new Random();
        //I need to exclude the "excludeNumber" here but I don't know how !?
        int number = rnd.Next(1, 6);
        switch (number)
        {
            case 1:
                {
                    Panel1.Visible = true;
                    break;
                }
            case 2:
                {
                    Panel2.Visible = true;
                    break;
                }
            case 3:
                {
                    Panel3.Visible = true;
                    break;
                }
            case 4:
                {
                    Panel4.Visible = true;
                    break;
                }
            case 5:
                {
                    Panel5.Visible = true;
                    break;
                }
            case 6:
                {
                    Panel6.Visible = true;
                    break;
                }
        }

    }
    protected void Button1_Click(object sender, EventArgs e)
    {
       // InsertToDB(1, DropDownList1.SelectedValue);
        Panel1.Visible = false;
        ShowNextPanel(1);

    }
    protected void Button2_Click(object sender, EventArgs e)
    {
       // InsertToDB(2, DropDownList2.SelectedValue);
        Panel2.Visible = false;
        ShowNextPanel(2);

    }
//and go on till button6_click

You can put the numbers in a list, and generate your random number not based on your real numbers, but on the remaining items in the list.

Random random = new Random();
List<int> nums = new {1, 2, 3, 4, 5, 6}; // or whatever you need to put there.
List<int> result = new List<int>(); // will hold your results in order.
while(nums.Count > 0){
    int idx = random.next(0, nums.Count);
    result.add(nums[idx]);
    nums.RemoveAt(idx);
}
return result;

You don't have to use int values in your nums list; it can be your Question objects, or whatever you need; What you will get is the items in a random order.

Generate random numbers without repetitions, Your current code indicates that the range of random numbers is specified by Random. If you add a duplicate value to a HashSet, it does not grow, and the operation performance is not Note, my C# is weak, so I have tried to make the logic clear. I implemented three algorithms for returning non repetitive Numbers:. Sometimes developers need to generate random numbers in a Web page or website. This article demonstrates how to create a simple Web page using ASP.NET and generates and displays a random number using the Random class available in C# and .NET.

You need a list of Panels/Indices and then shuffle them with for example Fisher-Yates .

How to get non-repetative 6 digit's Random number ., I want 6 digit random number,which shouldn't be repetative. number must is in / how-to-generate-random-numbers-with-non-repeating-digits-in-java of Random number generation within C# and possibly using one of his� How To Generate Random Numbers In Asp.Net. In this tutorial we will let you know How To Generate Random Numbers In Asp.Net.Here we will demonstrate two methods for this.On first we are generating only random numbers, on second method we are generating number with alphabet.This is a very simple approach.

Start with a list of all your panel numbers:

var panels = new List<int>() { 1, 2, 3, 4, 5, 6 }

You will need to "remember" what panels you have already seen accross postbacks, so you could store this in ViewState or Session maybe.

Each time you need a new number:

Random random = new Random();
var idx = random.next(0, panels.Count);
var selectedPanel = panels[idx];
panels.Remove(selectedPanel);

When panels.Count() == 0, re-inistialise it with all the numbers.

Non repeat random number generation using c# , Hi, i want to generate Non repeat random number using C# from 1 to 10 Lacks. My code works fine, but it creates upto 1 Lacks. But i want to� // First, this will not give you a random number // int n // n = new random().next(1,100) // // Try this and see: int n; for (int i = 0; i < 100; i++) { n = new Random().Next(1, 100); Console.WriteLine(n.ToString()); } Console.ReadKey(); // here is one approach Random rand = new Random((int)DateTime.Now.Ticks); int RandomNumber; RandomNumber = rand.Next(100000, 999999); int CharCode = rand

You can "mark" panels that you've already showed as seen and if the random number selected is already marked go to the next panel (i++) until you find one that wasn't marked.

Generate random numbers in loop without repeating., How to generate many random various numbers? I realise that this is an old question and I would not normally respond but I feel that the best solution has not been explored. It seems to me that Here is an implementation in C#. C#. Delphi / Pascal. F#. HTML / XML / ASP. Java. Kotlin. Javascript. SQL. The Random.Next() method returns a random number, Random.NextBytes() returns an array of bytes filled with random numbers, and Random.NextDouble() returns a random number between 0.0 and 1.0. The Random.Next() method has three overloaded forms and allows you to set the minimum and maximum range of the random number.

Write the following classes in your C# Page,

int RandNo = 0;

private int RandomNumber(int min, int max)
{
    Random random = new Random();
    return random.Next(min, max);
}

Then call the following method where ever you require,

RandNo = RandomNumber(10000000, 99999999);
Response.Write(RandNo);

Random number generator without duplicates C#, create a random numbers with no duplicates Your browser does not currently recognize Duration: 3:38 Posted: May 21, 2017 How to Generate Random Numbers in .NET. Webucator provides instructor-led training to students throughout the US and Canada. We have trained over 90,000 students from over 16,000 organizations on technologies such as Microsoft ASP.NET, Microsoft Office, Azure, Windows, Java, Adobe, Python, SQL, JavaScript, Angular and much more.

You can also use the Random class for such tasks as generating random T:System.Boolean values, generating random floating point values with a range other than 0 to 1, generating random 64-bit integers, and randomly retrieving a unique element from an array or collection.

The simplest random password generation scheme with ASP.NET is to return a portion of a GUID. A GUID is a G lobally U nique ID, a 128-bit number that can be quickly generated with one method call, producing a hexidecimal string that can be used as a random password.

Similarly, click on N numbers at a time and it will generate various random numbers with no specific sequence and for moves the loop between the random function specified range 10 to 200. Summary So by all the examples above I have explained how to use the Random function of C# .

Comments
  • All I want is to show every question once and I need to show them all one by one in random manner .
  • this is the easiest solution but would distort the randomness, e.g. if the first panel is panel 3, you are now twice as likely to see panel 4 next as any other panel.
  • Save in your session an array - bool[] panelsShown = new bool[6]; When generating a random number just check if the cell is already marked as true, if yes mark it to true and show it, else do i++ until you find non-marked then select it and mark it. Make sure that your loop won't be infinite if all panels already marked.
  • If it's important for you to make it really random then count how many non-marked panels left and select a random number from the count of non-marked panels. For example if your array is FFTFTF and you've chose a random number up to 4. The go to the i's FALSE.
  • This answer is incorrect; it does nothing to prevent previously-selected panels from being selected again, and further, because it uses a constant seed, it will cause the sequence to be the same every time.