## While loop until you randomly roll selected number, where to put random

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while practicing while loops I tried to make code where you put random number and then your guess how many tries it takes to roll it but I cant declare variable "chance" inside the while but if I put it before it it just keep rolling 1 number.

```    Random rng = new Random();
Scanner input = new Scanner(System.in);
System.out.println("Select a number you want to roll");
int choice = input.nextInt();
System.out.println("You feelin' lucky?\nHow many tries until you get " + choice);
int tries = input.nextInt();
int count = 0;
int chance = rng.nextInt((100)+1);
while (choice != chance) {
System.out.println(chance);
count++;

}
System.out.println("You won! It only took " + count + " tries.");
}
```

How can i declare the int chance so it gets into while loop?

You can just re-assign chance to a new value in the while loop :

```int count = 0;
int chance = rng.nextInt((100)+1);
while (choice != chance) {
System.out.println(chance);
chance = rng.nextInt((100)+1);
count++;
}
```

11. Guessing Games with Random Numbers and Loops — Arcade , This set of code loops through and draws each object in the game. That loop If you want to Duration: 12:18 Posted: Sep 12, 2018 while loop random number Java. Sep 06, 2019 Examples, Loops, Problem Solving, Snippet comments So in this post we try to do a simple loop that display some random Numbers. See example below: while loop random number Java. So below is a simple example that uses while loop to generate 10 random numbers between 0 and 100.

If I understood your question, I think you should use the `do-while` loop. It will enter the loop atleast once.

```Random rng = new Random();
Scanner input = new Scanner(System.in);
System.out.println("Select a number you want to roll");
int choice = input.nextInt();
System.out.println("You feelin' lucky?\nHow many tries until you get " + choice);
int tries = input.nextInt();
int count = 0;

do {
int chance = rng.nextInt((100)+1);
System.out.println(chance);
count++;
} while (choice != chance)

System.out.println("You won! It only took " + count + " tries.");
```

Guide on a Random Number Generator C++: The Use of C++ Srand, You can easily imitate dice rolling by using a random number generator. However, the prizes need to be selected randomly while also keeping For this aim, you should also use the switch statement to present different outcomes: If you want this function to work, you need to add the <cstdlib> header. We create a simulation program that rolls two dice until we get "box Cars" (double sixes). We show two ways to use random numbers in java and the post test indefinite do..while loop.

Don't declare the variable `chance` again. Just re-assign it to a new value.

```chance = rng.nextInt((100)+1);
```

Issues in the code:

1. Loop never uses `tries`.
2. Code doesn't determine when number of tries is not enough to guess the number entered by user

```Random rng = new Random();
Scanner input = new Scanner(System.in);
System.out.println("Select a number you want to roll");
int choice = input.nextInt();
System.out.println("You feelin' lucky?\nHow many tries until you get " + choice);
int tries = input.nextInt();
int count = 1;
int chance = rng.nextInt((100) + 1);

while (tries > 0) {
System.out.println(chance);
if (choice == chance)
break;
chance = rng.nextInt((100) + 1);
count++;
tries--;
}

if (choice == chance) {
System.out.println("You won! It only took " + count + " tries.");
} else {
System.out.println("You lost");
}
```

Logic:

1. Use `tries` to determine how many times the loop is required to run. Decrement it after each run.
2. If choice and chance are equal then control jumps out of the loop.
3. The last if condition is to determine whether the user was able to guess within the number of tries

Chapter 5: Program Logic and Indefinite Loops, The for loops that we have been writing are definite loops; before the loop, we know If r < 0.5, then another random number is assigned to r, and the flow of control Roll die 2. What is the sum of the dice before the loop? One option is to add One method is to use a sentinal value, which is a specific value that signals the� 2 Random distinct numbers in nested loop May 7 '19 2 While loop until you randomly roll selected number, where to put random May 7 '19 2 SQL show ONLY displayed duplicates after filtering out duplicates with same results in other column Nov 22 '18

Chapter 18, In the second phase you keep rolling the dice until you roll a 7 or you roll the value of the Then we just generate two random values 1 through 6 and add them together. return value of the function is the amount won, where a negative number means a loss. The logic for the first phase just needs a conditional statement. so i have a while loop, each time it runs i want it to take in account each previous number that was randomly selected. When i run the loop i want it to create a new number every time the user says so, and at the same time taking in account the new numbers generated in the loop already, This code doesnt work, it wont take into account the new numbers generated.

Basic Programming With Python, If you don't even know how to install Python, look here. Note that this article Loops. There are two different kinds of loops in Python: the for loop and the while loop. This continues so on until the number, 50, is reached. Therefore Easy peasy. We will just generate a random number from 1 to 6 with the package like this: Let us see how to generate different random numbers using C++. Here we are generating random numbers in range 0 to some value. (In this program the max value is 100).

Python can generate such random numbers by using the random module. In the below examples we will first see how to generate a single random number and then extend it to generate a list of random numbers. Generating a Single Random Number. The random() method in random module generates a float number between 0 and 1. Example

• You need to re-assign chance inside the loop... i.e. `chance = rng.nextInt(101);`