## Searching through a repeated string

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Lilah has a string, `s`, of lowercase English letters that she repeated infinitely many times.

Given an integer, `n`, find and print the number of letter `'a'` in the first `n` letters of Lilah's infinite string.

This is my solution, but it is not correct, and I'm struggling to figure out why:

```function repeatedString(s, n) {
let counter = 0;
const remainder = n % s.length;
const substring = s.substring(0, remainder);
const concatString = s + substring;

for (let letter of concatString) {
if (letter === 'a') {
counter++;
}
}
return (counter * n);
}

const str = "dhfgjhdfoiahwiuerhiguhzlkjvxzlkjghatriaeriaauih";
console.log(
repeatedString(str, 20)
);```

I think it may be the

const concatString = s + substring;

```  for (let letter of substring) {
if (letter === 'a') {
counter++;
}
}
return counter
```

Find the first repeated character in a string, Scan the input array from left to right. For every element, count its occurrences in temp[] using binary search. As soon as we find a character that� 1. Find the occurrences of character ‘a’ in the given string. 2. Find the No. of repetitions which are required to find the ‘a’ occurrences. 3. Multiply the single string occurrences to the No. of repetitions. 4. If given n is not the multiple of given string size then we will find the ‘a’ occurrences in the remaining substring.

You just need to loop through the `s.substring(0, n)` and return the `counter` value, `(counter * n)` doesn't make any sense.

```function repeatedString(s, n) {
let counter = 0;
//const remainder = n % s.length;
const substring = s.substring(0, n);
console.log(substring);
//const concatString = s + substring;

for (let letter of substring) {
if (letter === 'a') {
counter++;
}
}
return counter;
}

const str = "dhfgjhdfoiahwiuerhiguhzlkjvxzlkjghatriaeriaauih";
console.log(
repeatedString(str, 20)
);```

Find repeated character present first in a string, The solution is to loop through the string for each character and search for the same in the rest of the string. This would need two loops and thus� Start by building a prefix array. Loop through it in reverse and stop the first time you find something that's repeated in your string (that is, it has a str.count()>1.. Now if the same substring exists right next to itself, you can return it as the word you're looking for, however you must take into consideration the 'appleappl' example, where the proposed algorithm would return appl.

Repeated String Match, Return 3, because by repeating A three times (“abcdabcdabcd”), B is a substring of it; and B is not a substring of A repeated two times ("abcdabcd"). Note: In computer science, string-searching algorithms, sometimes called string-matching algorithms, are an important class of string algorithms that try to find a place where one or several strings (also called patterns) are found within a larger string or text.

This should give you the number of times a appears in the numbers of n length

```const input = s;

var subStr = input.substr(0,n).split('');
console.log(subStr);

var output = 0;

subStr.forEach((e) => {
if (e === 'a') {
console.log(e);
output++;
}
})
console.log(output);
```

Longest repeated substring problem, In computer science, the longest repeated substring problem is the problem of finding the longest substring of a string that occurs at least twice. This problem can� Each of the files has random text data inside. We’re looking for only the files that contain one particular string. Additionally, since we don’t know how many matches we are going to find, we’re going to create an array to store the found matches.In order to search for strings or string patterns, we’re going to use the cmdlet Select-String.

Using the next link as the source of the question:

https://medium.com/@yashka.troy/want-to-know-the-major-player-in-programming-18f2d35d91f7

Where it is explained better:

Lilah has a string, `s`, of lowercase English letters that she repeated infinitely many times.

Given an integer, `n`, find and print the number of letter `a's` in the first letters of Lilah's infinite string.

For example, if the string `s=’abcac’` and `n=10`, the sub string we consider is `‘abcacabcac’`, the first `10` characters of her infinite string. There are `4` occurrences of `a` in the substring.

A solution could be:

```function repeatedString(s, n)
{
let res = 0;
const remainder = s.slice(0, n % s.length);

// Get number of times 'a' is present on "n / s.length" repetitions.

for (let letter of s)
{
if (letter === 'a') res++;
}

res *=  Math.floor(n / s.length);

// Add the number of times 'a' is present on the remainder.

for (let letter of remainder)
{
if (letter === 'a') res++;
}

return res;
}

const str = "abca";
console.log(`\${repeatedString(str, 10)} a's on first 10 letters:`);
console.log(`\${repeatedString(str, 4)} a's on first 4 letters:`);
console.log(`\${repeatedString(str, 0)} a's on first 0 letters:`);
console.log(`\${repeatedString(str, 22)} a's on first 22 letters:`);```
```.as-console {background-color:black !important; color:lime;}
.as-console-wrapper {max-height:100% !important; top:0;}```

Regex Tutorial, In a regular expression, the asterisk or star causes the preceding token to be matched the string you are searching through does not contain any such invalid tags. That is, the plus causes the regex engine to repeat the preceding token as� The Select-String cmdlet searches for text and text patterns in input strings and files. You can use it like Grep in UNIX and Findstr in Windows with Select-String in PowerShell. Select-String is based on lines of text.

In the if statement we use the strstr () function to search for our string in the content we fetched from the file. If we found a match we display line-number, line and we increase find_result with one. The while loop will continue until we reach the end of the file.