## How to calculate the difference in minutes between two timeStamp ( with different days)?

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I'm trying to calculate a difference in minutes between two java TimeStamps when I write: Timestamp `t1,t2;`

`t2.getTime()-t1.getTime();` it returns only the difference between the two times and I need the difference the whole times (including days)

Try this

```long difftime = t1.getTime() - t2.getTime();
long seconds = diff / 1000;
long minutes = seconds / 60;
long hours = minutes / 60;
long days = hours / 24;
```

How to calculate the difference in minutes between two timeStamp , Calculate the exact minutes by subtracting two dates in excel 2016. you frequently get the need to calculate hours, minutes and seconds between two timestamps. We subtract time/dates in excel to get the number of days. Need to combine date into one column so that other calculation formulas can handle them for� Calculate Date/Time Difference. Show the difference between two dates. Use this calculator to find the number of days, hours, minutes and seconds between 2 dates.

Difference between 2 timestamps gives milliseconds. Apply Maths afterwards:

```// get time difference in seconds
long milliseconds = timestamp2.getTime() - timestamp1.getTime();
int seconds = (int) milliseconds / 1000;

// calculate hours minutes and seconds
int hours = seconds / 3600;
int minutes = (seconds % 3600) / 60;
seconds = (seconds % 3600) % 60;
```

Calculate Minutes Between Date & Time In Microsoft Excel, %DIFF produces the difference (duration) between two date or time values. For two dates or a date and a timestamp: *DAYS, *MONTHS, and *YEARS; For two times or a time and a timestamp: *SECONDS, *MINUTES, and *HOURS; For two The difference is calculated by subtracting the second operand from the first. A Minute is 60 Seconds An Hour is 60 Minutes (or 60 * 60 seconds) A Day is 24 Hours or (24 * 60 * 60) We perform the difference for each of the elements, EXTRACT all of the values, convert them to the base (Second) and then scale them back up to the desired level of granularity (Minutes).

Assuming you mean `java.sql.Timestamp`, the code below seems to work just fine:

```import java.sql.Timestamp;

class Scratch {

public static final long MINUTES_PER_HOUR = 60;
public static final long SECONDS_PER_MINUTE = 60;
public static final long HOURS_PER_DAY = 24;
public static final long MILLIS_PER_SECOND = 1000L;

public static void main(String[] args) {
long oneDayPlusFiveMinutesInMillis = (MILLIS_PER_SECOND * SECONDS_PER_MINUTE) * ( 5 + MINUTES_PER_HOUR * HOURS_PER_DAY);
Timestamp t0 = new Timestamp(System.currentTimeMillis());
Timestamp t1 = new Timestamp(t0.getTime() + oneDayPlusFiveMinutesInMillis);
long diff = (t1.getTime() - t0.getTime()) / (MILLIS_PER_SECOND * SECONDS_PER_MINUTE);
System.out.println("t1 - t0 = " + diff + " minutes");
}
}
```

Returns:

```t1 - t0 = 1445 minutes
```

DIFF (Difference Between Two Date, Time, or Timestamp , The TIMESTAMPDIFF function returns an estimated number of intervals of the type that the interval that is used to determine the difference between two timestamps. 1, Microseconds. 2, Seconds. 4, Minutes. 8, Hours. 16, Days. 32, Weeks. First line calculates the difference between two timestamps. Second line converts the difference in terms of minutes (timedelta64 (1,’m’)- small m indicates minutes) view source print? 1. df ['diff_minutes'] = df ['End_date'] - df ['Start_date'] 2. df ['diff_minutes']=df ['diff_minutes']/np.timedelta64 (1,'m') 3. 4.

```    Timestamp t1 = new Timestamp(new Date("04/26/2019 20:32:49").getTime());
Timestamp t2 = new Timestamp(new Date("04/27/2019 19:32:49").getTime());

long diff = t2.getTime() - t1.getTime();

long diffSeconds = diff / 1000 % 60;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1000) % 24;
long diffDays = diff / (24 * 60 * 60 * 1000);
long diffTotMinutes = diff / (60 * 1000);

System.out.println("Days: " + diffDays + " \nTime: " + diffHours + ":" + diffMinutes + ":" + diffSeconds);
System.out.println("Total Minutes: " + diffTotMinutes);
```

Out Put:

```Days: 0
Time: 23:0:0
Total Minutes: 1380
```

timestampdiff, The DateInterval object represents the difference between the two dates or FALSE an amount of days, months, years, hours, minutes and seconds to a DateTime The task was to calculate the duration between two date/times. Using the identical (===) comparision operator in different but equal objects will return false You can use various datetime expressions or a user-defined DATEDIFF function (UDF) to calculate the difference between 2 datetime values in seconds, minutes, hours, days, weeks, months and years in PostgreSQL.

DateTime::diff - Manual, I am calculating and hence selecting the difference between the two timestamps in minutes by using the below query. select (extract (second from intervl) / 60) + extract (minute from intervl) + extract (hour from intervl) * 60 + extract (day from intervl) * 60 * 24 DIFF_IN_MINS,mydate

dunno why this was downvoted. if you two dates are in the ACTUAL timestamp format : E.G. 1503964800000 (which is definitely simpler to work with than crap containing maybe / maybe -and an uncertain amount of 0s before the digits and with the three members coming sometimes with a certain arrangement sometimes another.) then is is the better

If you subtract 2 dates in Oracle, you'll get the result expressed as a fraction of the number of days. To get the number of minutes between 2 dates, you multiply by 1440, i.e. SELECT (SYSDATE - DATE'2015-09-16') * 1440 If you want all records over 30 minutes old, you could have something like:

• That sounds unlikely - what are the values of `t1.getTime()` and `t2.getTime()` in this case?
• Consider adding ThreeTenABP to your Android project so that you can avoid the old, poorly designed and confusing `Timestamp` class and use for example `ChronoUnit.MINUTES.between` or the `Duration` class. The modern API is so much nicer to work with, and I’m convinced that it more directly offers the functionality you need.
• `Days: 0 Time: 23:0:0`