How to get the dropdown list value and insert into MySQL server?

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I would like to get the value from the dropdown in main.php file into MySQL server using PHP file.


If the user didn't select any choice or a select default choice <option value="0">(Select Animal)</option> where option value = 0.

Then if the option value = 0, the value from dropdown should not be inserted into the MySQL server.

So, what should I need to add into add.php?


include 'connection.php';
require_once 'add.php';
<form method="post" action="add.php">
     <select id="animal" name="animal">                      
            <option value="0">(Select Animal)</option> <!--Non select option-->
            <option value="Cat">Cat</option>
            <option value="Dog">Dog</option>
            <option value="Cow">Cow</option>
     <button type="submit" name="Save">Save</button > <!--Send the selected value to add.php-->

Another PHP file (add.php)


include 'connection.php';
              $animal = mysqli_real_escape_string($conn,$_POST['animal']; );            
              $conn->query("INSERT INTO animal (name) VALUES(?)");              
              header("location: main.php");

you can use Javascript validation for the dropdown or Keep a condition for $_POST of animal like below:


include 'connection.php';
              $animal = mysqli_real_escape_string($conn,$_POST['animal']);            
              $sql="INSERT INTO animal (name) VALUES(?) ";              
              header("location: main.php");
      header("location: main.php");

PHP Insert Selected DropDown Value MySQL phpMyAdmin Remote , phpdropdown #selectoptiondropdown #dropdownlist PHP Tutorial insert select option value Duration: 9:57 Posted: Dec 28, 2017 How to get create drop down list in php directly via set MySQL db records. In this tutorial we are creating complete dynamic drop down list and inside that list all the list items directly coming from MySQL db table rows-columns. Means all you have to is enter the value directly to db and it will call and set them inside drop down list using PHP.

Make sure you know the array key exists before checking if it is set or you may get an error/warning.

Then ensure that the animal value is greater than 0... and include it in your query.

    include 'connection.php';
    if(array_key_exists('Save', $_POST)) {
      if(array_key_exists('animal', $_POST) && $_POST['animal'] > 0) {
        $animal = mysqli_real_escape_string($conn, $_POST['animal']);

        //Prepare statement
        $conn->prepare("INSERT INTO animal (name) VALUES (?)");

        //Include animal value in string query
        $conn->bind_param("s", $animal);

        //Run query

        header("location: main.php");
      } else {
        //Fail gracefully
        header("location: error.php"); //Or whereever you want to redirect to.

Bare in mind, you are not actually running the query here.

You're just creating it as a string, nor are you adding the value of animal to it.

Also, remove that semicolon after $_POST['animal'] when doing mysqli_real_escape_string().

EDIT: I've updated mine with your update.

EDIT 2: I have also added what you need to correctly prepare the statement.

How to add value to the database from DropDown List, using dropdownlist. We just have to define a string which will store the dropdownlist value Duration: 7:23 Posted: Dec 24, 2017 Select from database based on a mysql populated dropdown list. PHP. option value as a GET or POST to a server side script which then uses the sent value as input to an sql select query

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  • It seems little syntax error but I have already fixed it. Thank for help. :D