Remove one array from a bigger one?

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I have two arrays in VBA and i'm trying to obtain a third subarray substracting those arrays, something like this:

Original arrays:

array1=("A","B","C","D")
array2=("B","C")

Expected result:

array1-array2=("A","D")

Is there a way to achieve this?

loop the first array and use Application.Match to search the second array.

Load a 3rd array with those items that throw an error from the match:

Sub try()
    Dim array1()
    array1 = Array("A", "B", "C", "D")

    Dim array2()
    array2 = Array("B", "C")

    Dim array3()
    ReDim array3(0)

    Dim i As Long
    For i = LBound(array1) To UBound(array1)            
        If IsError(Application.Match(array1(i), array2, 0)) Then
            array3(UBound(array3)) = array1(i)
            ReDim Preserve array3(UBound(array3) + 1)
        End If
    Next i

    ReDim Preserve array3(UBound(array3) - 1)

    Debug.Print Join(array3, ",")

End Sub

The Fastest Way to Remove a Specific Item from an Array in , indexOf and .splice to remove an item from an array. Then I compare One way to solve this problem is using Array.prototype.indexOf() to find the What if we are working with a bigger array, of say 10,000 items? In that case� We need to reduce size of array to one. We are allowed to select a pair of integers and remove the larger one of these two. This decreases the array size by 1. Cost of this operation is equal to value of smaller one. Find out minimum sum of costs of operations needed to convert the array into a single element. Examples: Input: 4 3 2 Output: 4 Explanation: Choose (4, 2) so 4 is removed, new array = {2, 3}.

TBH, I normally find VBA's Filter function next to useless for day-to-day programming requirements and rarely use it but in this case it does seem ideally suited to your purpose if you set the optional third [include/exclude] argument to False.

The following assumes that you want to retain the original values in array1 so a copy of the originals is made in array3 where only exclusion values are retained. I've also used vbTextCompare instead of vbBinaryCompare for a case insensitive filtering operation. Change to vbBinaryCompare for a case sensitive operation.

Option Explicit

Sub arrayDiff()

    Dim i As Long
    Dim array1 As Variant, array2 As Variant, array3 As Variant

    'populate array1 and array2
    array1 = Array("A", "B", "C", "D")
    array2 = Array("B", "C")

    'make a working copy of array1 to process
    array3 = array1

    'loop through the elements in array2 and remove them from array3
    For i = LBound(array2) To UBound(array2)
        array3 = Filter(array3, array2(i), False, vbTextCompare)
    Next i

    'display results in Immediate window
    Debug.Print "array3 = Array(""" & Join(array3, """,""") & """)"

    'alternate result display
    For i = LBound(array3) To UBound(array3)
        Debug.Print array3(i)
    Next i

End Sub

'results from Immediate window
array3 = Array("A","D")
A
D

Delete array elements which are smaller than next or become , Given an array arr[] and a number k. The task is to delete k elements which are smaller than next element (i.e., we delete arr[i] if arr[i] < arr[i+1])� Basically it returns the elements from arr which are not 6. Another point to be noted is that it returns a copy of existing array with elements with value 6. We can assign this new array back to arr to have the deletion effect of all occurrences of 6 from the numpy array. Delete elements in Numpy Array based on multiple conditions

You can use a dictionary to create a function that will return an array consisting of array1 - the elements of array2:

Option Explicit
Function arrSubtr(arr1, arr2)
    Dim D As Dictionary
    Dim V

Set D = New Dictionary
    D.CompareMode = TextCompare

For Each V In arr1
    D.Add V, V
Next V

For Each V In arr2
    If D.Exists(V) Then
        D.Remove (V)

'    Uncomment below if you want to add in items in
'    array2 that don't exist in array1
'    Else
'        D.Add V, V
    End If
Next V

arrSubtr = D.Keys

End Function

Remove Element from an Array in JavaScript, Finding the location by value can be done with the indexOf() method, which returns the index for the first occurrence of the given value, or -1 if it is not in the array. Both the arrays should: be of the same type. have the same length or the array in which you’ll copy should be larger. Illustration : If one of your arrays contains A={1,4,5,6,3,3,2,3,4,4} then the array you’ll copy should have B={1,4,5,6,3,3,2,3,4,4} after copying. Procedure to copy elements of one array to another in C++. Create an empty

Remove Elements From Lists | Python List remove() Method, But, there's one major difference. Arrays contain elements of the same data types, whereas Python lists can contain items of different types. A� Slicing an array. You can slice a numpy array is a similar way to slicing a list - except you can do it in more than one dimension. As with indexing, the array you get back when you index or slice a numpy array is a view of the original array. It is the same data, just accessed in a different order.

How to Remove an Element from an Array in Java? Example , Problem: Given an array and a value, write a function to remove all instances of that I mean loop through the initial array and copy to a new array, which is one space complexity or understand the Big O notation of algorithms complexity,� There are mainly four different ways to copy all elements of one array into another array in Java. 1. Manually 2. Arrays.copyOf() 3. System.arraycopy() 4. Object.clone() Lets discuss each of them in brief. How to Copy One Array to Another in Java 1. Manually. In this method we manually copy elements one by one. It is not an efficient way.

Put a small matrix in a bigger one. code where you can specify the upper left corner and it will check to make sure the small array does not go outside the big

Comments
  • Loop over array1, and check if each element is in array2: if not then add to array3.
  • Are the arrays guaranteed to be in order?