## Conditional IF() statement problem, not returning desired value

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Currently writing a program in excel that will return a value based on user input. The current formula has 5 different return options which are returned based on the selection of a number by the user. I use the IF() statement embedded into more IF() statements to account for multiple input options. However, when I go to enter in a number beyond the range of the first IF() statement, I am getting 0 even though it should be a different number.

For the code below, C30 is the input cell and it should return .15 if I was to enter 25.

=IF(C30<20, 0.35, IF(20<C30<40, 0.15, IF(40<C30<60, 0, IF(60<C30<80, -0.1, IF(80<C30, -0.2, 0)))))

From the logic statements, it should be returning .15, but all I am getting is 0.

Excel does not use `20<C30<40`

it would be:

AND(20<C30,C30<40)

But you can shorten this with a simple MATCH and CHOOSE:

=CHOOSE(MATCH(C30,{0,20,40,60,80}),0.35,0.15,0,-0.1,-0.2)

If you really want a nested if there is no need for the extra tests:

=IF(C30<20,0.35,IF(C30<40,0.15,IF(C30<60,0,IF(C30<80,-0.1,-0.2))))

IF will resolve sequentially and short circuit as soon as it finds the first TRUE, so it does not need the other logic.

**Developer insists if statements shouldn't have negated conditions ,** I don't even mention the fact that an if statement isn't necessarily followed by For example, if (condition) { do_stuff; return; } Similarly, an empty else is not if ( condition) { do_if_action() } else { // I was told that an if always should have an else . use a boolean value, you need some blocks of code to operate when it's set,� IF (VLOOKUP (…) = sample_value, TRUE, FALSE) Translated in plain English, the formula instructs Excel to return True if Vlookup is true (i.e. equal to the sample value). If Vlookup is false (not equal to the sample value), the formula returns False. Below you will a find a few real-life uses of this IF Vlookup formula.

The problem here is the logic that you have used to evaluate whether `C30`

falls within a range of numbers.

`IF(20<C30<40,...)`

will *not* check whether `C30`

is in the range of 20 through 40.

Instead, use `AND(cond1, cond2, ...)`

to check whether the values are within the range:

IF(AND(C30 > 20, C30 < 40), ...)

**How to use IF function in Excel: examples for text, numbers, dates ,** ISBLANK(), Evaluates to TRUE is a specified Returns 1 if A1 is non-blank; otherwise returns 0. ISBLANK()=FALSE, Evaluates to TRUE if a specified cell is not Problem Statement: I want to print 'Fail' in result I have a conditional formula in Column F and� I have a conditional format in F9 that compares the value between F9 and C46. If the values are NOT equal, then the background color and font in F9 changes (background = red | font = Yellow). C46 is the sum of C1:C45. F9 is the sum of F1:F8 which sums column C to recap values based on year using a SUMSIF statement.

Replace terms like:

20<C30<40

with:

AND(20<C30,C30<40)

etc.

**[PDF] Beyond IF THEN ELSE: Techniques for Conditional ,** false, we have cleverly returned a value of 1, which will have no effect when The desired string is obtained in a single statement, and the code makes it easy to see In this specific example, we can sidestep this problem by simply using the� The formula also needs to check if h18=0 AND the sum of cells f18 < d12+d14, it should return the value in cell m18. Those two statements are the same. You are asking that if H18=0 And SUM(d12+d14)>F18 to return both 0 and M18. I assumed your first statement was correct and the directional sign on the second statement was a mistake. So please

**“No-else-after-return” considered harmful – Nicholas Nethercote,** void f() { if (errorcase()) return; a(); b(); c(); d(); } Also, it's just harder to read because the two return statements have In this case there's a way around the problem: the profile of the instruction if (!set) { // desired register class is not free so to check if anything else happens before the value is returned. MISRA requires a single return statement: (MISRA, rule 14.7 : required) "A function shall have a single point of exit at the end of the function" Now, personally I don't think it is a good rule. Minimize the number of return statements but use a return statement when it enhances the readability of your code.

**[PDF] If Statements and Booleans,** For a program to do anything interesting, it needs if-statements and booleans to The less-than operator, <, takes two values and evaluates to true if the boolean b = "hello"; // NO, String and boolean are different isLow() message that returns true if the car is low on fuels. code-writing problems, but it's a good way to. If conditional doesn't yield a strict Boolean value and you want that, then return bool (conditional) – kindall Nov 3 '14 at 23:44. Assumes that conditional is a boolean expression. If it's an expression that returns a non-boolean value that will be int

**Groovy Truth,** Closure case values match if the calling the closure returns a result which is true toArray() x = 0 for ( i in array ) { x += i } assert x == 10 // iterate over a map def map Despite not changing the semantics of the labelled statement, it is possible to use While using def in a local variable is not really a problem because the� C26=40 and C25=10. So, it is returning a 4. So, the cell that is reassigning a value should be coming back with a 3. However, it is returning a 1.50. To make that above statement work, I had to change the semi-colon to a comma. It would not work with semi-colon. – Brian White Feb 23 '15 at 21:53

##### Comments

- Try replacing
`20<C30<40`

with just`C30<40`

and replace`60<C30<80`

with just`C30<80`

. - If you go to "Formulas" > "Evaluate Formula" and step through - you should see the issue on the second or third click of "Evaluate"...
- I've always been fond of the form
`IF(C30=MEDIAN(20,C30,40), ...)`

for this