Android - programmatically change the state of a switch without triggering OnCheckChanged listener

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I'm looking for a method of programmatically changing the state of an Android Switch widget using switch.setChecked(true); without triggering OnCheckedChangedlistener. My first thought was to swap it out for an OnClickListener but as this only registers clicks and you are able to not only click but also slide a Switch then it's not really fit for purpose as if the user was to slide the Switch from off to on then the Switch would actually do nothing as the user is not clicking...If anyone's got a solution or a smart work around for this, that would be awesome

Well, just before doing things in code with the switch you could just unregister the Listener, then do whatever you need to, and again register the listener.

Change the state of a switch without triggering , I worked around this problem by using setOnClickListener() instead of setOnCheckedChangeListener() , then I can use isChecked inside the� If you want to only change the state of the switch with swipe do the programmatically change the state of a switch without triggering OnCheckChanged listener. 1.

Set the listener to null before calling setCheck() function, and enable it after that, such as the following:

switch.setOnCheckedChangeListener (null);
switch.setChecked(true);
switch.setOnCheckedChangeListener (this);

Reference: Change Checkbox value without triggering onCheckChanged

Android programmatically checkable widgets, differentiate between , Android - programmatically change the state of a switch without triggering setChecked(true); without triggering OnCheckedChangedlistener. My first thought� Switch (On/Off) Tutorial With Example In Android Studio. In Android, Switch is a two-state toggle switch widget that can select between two options. It is used to display checked and unchecked state of a button providing slider control to user.

Every CompoundButton (two states button - on/off) has a pressed state which is true only when a user is pressing the view.

Just add a check in your listener before starting the actual logic:

if(compoundButton.isPressed()) {
    // continue with your listener
}

That way, changing the checked value programmatically won't trigger the unwanted code.

From @krisDrOid answer.

Change the state of a switch without triggering , There are times when setting a switch to ON results in some action (Save to DB/ perform an HTTP POST etc). In particular, the {@code OnCheckedChangeListener} is. * <strong>not</strong> triggered when the state of the checkbox is changed whose checked state can be changed programmatically, without triggering� By default, the android Switch will be in the OFF (Unchecked) state. We can change the default state of Switch by using android:checked attribute. In case, if we want to change the state of Switch to ON (Checked), then we need to set android:checked = “true” in our XML layout file.

I have one solution and its working fine at my end. I have added setOnTouchListener and setOnCheckedChangeListener on my switch control, and added following code to solve my problem.

    // set tag by default.
    mMySwitch.setTag("TAG");

    // Add OnCheckedChangeListener.
    mMySwitch.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
         @Override
         public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
            if (mMySwitch.getTag() != null) {
                 mMySwitch.setTag(null);
                 return;
                }

          // Do your stuff here.
        }
    });

    // Add Touch listener.
    mMySwitch.setOnTouchListener(new View.OnTouchListener() {
         @Override
         public boolean onTouch(View v, MotionEvent event) {
            mMySwitch.setTag(null);
            return false;
         }
    });

In this way setOnCheckedChangeListener is getting called only when check changed happens by human intervention by drag, by click, by touch.

Also don't forgot to add your valid string tag ( not null ) when your trying to change check status of switch control. like :

 mMySwitch.setTag("TAG");
 mMySwitch.setChecked(true);

Change Checkbox value without triggering onCheckChanged, setChecked(true); without triggering OnCheckedChangedlistener() ? switch. Android, I'm looking for a method of programmatically changing the state of an� Getting Started. At first, we will create android application. Then, we will use android switch widget in it. 1. Creating New Project. Follow the steps below to create a new project.

Write a custom Switch or SwitchCompat and override the setOnCheckedListener.

public class SwitchCompat extends android.support.v7.widget.SwitchCompat {
private boolean mIgnoreCheckedChange = false;

public SwitchCompat(Context context) {
    super(context);
}

public SwitchCompat(Context context, AttributeSet attrs) {
    super(context, attrs);
}

public SwitchCompat(Context context, AttributeSet attrs, int defStyleAttr) {
    super(context, attrs, defStyleAttr);
}


@Override
public void setOnCheckedChangeListener(final OnCheckedChangeListener listener) {
    super.setOnCheckedChangeListener(new OnCheckedChangeListener() {
        @Override
        public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
            if (mIgnoreCheckedChange) {
                return;
            }
            listener.onCheckedChanged(buttonView, isChecked);
        }
    });
}

public void setChecked(boolean checked, boolean notify) {
    mIgnoreCheckedChange = !notify;
    setChecked(checked);
    mIgnoreCheckedChange = false;
}

}

Switch, An Android checkbox listener (setOnCheckedChangeListener Android - programmatically change the state of a , setChecked(true); without triggering In case, if we want to change the state of Switch to ON (Checked), then we need to set android databinding: how to avoid onCheckedChanged triggered by , type � A Switch is a two-state toggle switch widget that can select between two options. Add Switch control to your Activity or Fragment layout as follows.

How can I distinguish whether Switch,Checkbox - android, OnShowModeChangedListener � AccessibilityService. A Switch is a two-state toggle switch widget that can select between two options. The user may drag the Change the checked state of the view to the inverse of its current state Failure to do so will trigger an IllegalStateException , thrown by measure(int, int) . I'd have to change isChecked to true/false i believe since isChecked only works inside the listener but that should work – user2677095 Sep 20 '14 at 7:58 Yeah that's true. Actually it's just a default value if there isn't any preference with this key. – reVerse Sep 20 '14 at 9:19

How can I distinguish whether Switch,Checkbox Value is changed , Inside onCheckedChanged() just check whether user has actually checked/ unchecked Use it in listener to check that listener is triggered by the user. public boolean When you check the box "programmatically", set a boolean value before to setOnCheckedChangeListener(mListener) }} To change switch state without� Decorating Switch and ToggleButton in Android Android 16.06.2017. Switch button. In Android, Switch is a two-state toggle switch widget that can select between two options. It is used to display checked and unchecked state of a button providing slider control to user. Switch is a subclass of CompoundButton. It is basically an off/on button

Change Checkbox value without triggering onCheckChanged, If you want to set checked from code without triggering the listener, call When you check the box "programmatically", set a boolean value before to @ Override public void onCheckedChanged(CompoundButton buttonView, Just call setChecked(boolean, true) to change the switch's checked state without detected! For more information on saving your activity UI state, see Saving UI States. Handling multi-window cases. When an app enters multi-window mode, available in Android 7.0 (API level 24)and higher, the system notifies the currently running activity of a configuration change, thus going through the lifecycle transitions described above.

Comments
  • Please use below line of code. "buttonView.isPressed()"
  • How would you go about unregistering the listener? sorry, i'm quite new to this
  • I think there are two options: 1. switch.setOnCheckedChangeListener(null); //not sure though, if that could lead to problems... 2. create a dummy class, implementing the OnCheckedChangeListender with a dummy method onCheckedChanged, which does nothing. then registering a new object of that and later on again registering you default listener
  • so if I was to use switch.setOnCheckedChangeListener(null); how would I then re-register the listener? would it be switch.setOnCheckedChangeListener(listener);??
  • As long as 'listener' is a reference to your listener object, yes. That would have been my approach to work this around (though there my be better solutions).
  • How did you re-register the listener?
  • Sorry but this didn't work out, onCheckedChanged was still repeatedly called.
  • Thanks for this solution, helped me a lot!! no need of mListener, unfortunately there is no switch.getOnCheckedChangeListener() method. BTW: in your onCheckedChanged() it is possible to replace mMySwitch with buttonView
  • Working great, genious !