## How to find only the top 3 values of a column and group the rest of the column values as zero?

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Consider a table having data as shown. I want to find the top 3 marks and combine the rest of the values of column marks as a single value 0.

name age marks height ----------------------------- anil 25 67 5 ashish 23 75 6 ritu 22 0 4 manish 25 0 6 kirti 23 97 5

**Output**

name age marks height ----------------------------- kirti 23 97 5 ashish 23 75 6 anil 25 67 5 OTHERS 0 0 0

With TOP 3 and UNION ALL for the last row:

select t.* from ( select top 3 * from tablename order by marks desc ) t union all select 'OTHERS', 0, 0, 0

See the demo. Results:

> name | age | marks | height > :----- | --: | ----: | -----: > kirti | 23 | 97 | 5 > ashish | 23 | 75 | 6 > anil | 25 | 67 | 5 > OTHERS | 0 | 0 | 0

**For each group find observations with max value of several columns ,** As seen above, some elements of x , y , z vectors take value of zero, the rest being drawn from the uniform distribution between 0 and 1. For each� Hi, I did some extensive researches about this and couldn't find the way to do what I want It's pretty simple in Access when one makes a report to have grouping headers, but I want to stay in Excel for some reasons the goal would be to have a table formatted with headers that would group lines based in a single column values.

I would use a CTE (Common Table Expression) and the ROW_NUMBER() function:

;WITH cte AS (SELECT [Name], Age, Marks, Height, ROW_NUMBER() OVER (ORDER BY Marks DESC) AS [Rank] FROM Test ) SELECT [Name], Age, Marks, Height FROM cte WHERE [Rank] <= 3 UNION ALL SELECT 'OTHERS', 0, 0, 0

**Excel MAX function,** How to find only the top 3 values of a column and group the rest of the column values as zero? - sql-server. I'm then using a table grouping (COUNT on column RANGE) to try and find out how many values are included in a particular range. It works fine, however when I chart the results I only see data where there is a positive count > 0 - which I suppose is strictly how a group function would work.

You can use select top 3 or row_number()

You can use row_number() as follows

declare @mytable as table(name varchar(50),age int,marks int,height int) insert into @mytable values('anil', 25, 67, 5),('ashish', 23, 75, 6),('ritu', 22, 0, 4),('manish', 25, 0, 6),('kirti', 23, 97, 5), ('other',0,0,0); with cte as( select name,age,marks,height,row_number() over(partition by 1 order by marks desc) row# from @mytable ) select name,age,marks,height from cte where row#<4 or name='other' order by row#

Another way, using union without inserting ('other',0,0,0) to the table, you can the same result

declare @mytable as table(name varchar(50),age int,marks int,height int) insert into @mytable values('anil', 25, 67, 5),('ashish', 23, 75, 6),('ritu', 22, 0, 4),('manish', 25, 0, 6),('kirti', 23, 97, 5) --,('other',0,0,0) ; with cte as( select name,age,marks,height,row_number() over(partition by 1 order by marks desc) row# from @mytable ) select name,age,marks,height,row# from cte where row#<4 union select 'others',0,0,0,4 order by row#

**How can I extract values that are less than 10 from different values in ,** See how to use the MAX function in Excel to find highest value in a Find max value in a group; Max formula for non-adjacent cells or =MAX(1, 2, 3) a contiguous row or column (like in this example), you can get Excel to If the arguments do not contain a single number, the MAX function returns zero. SELECT UnitID, MAX(Column1) as Column1, MAX(Column2) as Column2, FROM Table1 GROUP BY UnitID ; This should return a value if there is a non-NULL value, and should only return NULL if that's the only value found. Note that MAX isn't the only possible aggregate function you could use. MIN should work as well. Depending on you DBMS, there may be other possibilities as well.

**Excel formula: Rank if formula,** If I have values in column A in a spreadsheet starting from A1 to A5 as for example in cell A1 is less than 5 it enters same number in cell B1, if not, it enters a Zero. need to make the new list containing only the required values without zeroes. sorting your data from lowest number to highest number ( ascending order) for� Assuming that Flag is a BIT column or an INT that takes only 0 and 1 as values, this could be achieved using windowed functions as well. For instance: DECLARE @Test TABLE ( ID INT , Category VARCHAR(1) , Flag BIT ); INSERT INTO @Test (ID, Category, Flag) VALUES (1, 'A', 1) , (2, 'A', 0) , (3, 'A', 0) , (4, 'B', 0) , (5, 'C', 0); SELECT T.ID , T.Category , T.Flag FROM ( SELECT ID , Category

**Use Queries to show records based on conditions – Documentation ,** In the example shown, the formula in E5 is: =COUNTIFS(groups,C5,scores The second criteria restricts the count to only scores greater than the "current score" from there are three scores in group A higher than 79, so COUNTIFS returns 3. To reverse rank order and rank in order (i.e. smallest value is ranked #1) just� Gathers the result with two columns where name and dept are merged together in a single column. select id, (select top 1 Name + ' , ' + department from @t t2 where t.id = t2.id) from @t t group by id go. This method relies on another column that should be different between all the duplicates, like dt_created

**Get n-largest values from a particular column in Pandas DataFrame ,** label, Corporate Promotion, A roster of 34 candidates of which only the top 5 will make it through Task 3: Display everything then sort by Complexity in reverse alphabetical order. Explanation: Select all columns and sort the rows by the values in column J But once I get to a certain point, Then the rest stops working . One of the common ways is to change the Excel settings so all zero values are hidden. This “solution” however creates new challenges: If you send the file to someone else who hasn’t changed their Excel settings, they will see the zero values. You can’t decide if you only want to hide the zeros in certain parts of your workbook or sheets.

##### Comments

- Why use a subquery on the first select?
- Because of order by before union all. It is syntactically wrong.
- Sorry, I was thinking as bit too complicated... Although this works, the solution of forpas is simpler and works as well ;-)