Is it possible to pass an array into a function as a parameter without creating a variable for that array?

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So I made a function that takes arrays as parameters and I've tried calling the function by passing arrays that have not been defined as variables into said function (like {0,0,0,0}). However, I am given an error which says "too many initializer values."

Say we have a function defined as:

int func(int values[]) {
  int average = 0;
  for(int x = 0; x < values.size(); x++) {
    average += values[x];
  }
  return average / values.size();
}

And we want to call it without defining an array to pass in like this: func({1,6,7,2});

Is there any way to do something like this or would I have to define an array and pass it into the function that way?

C++ Passing Arrays to Functions, C++ does not allow to pass an entire array as an argument to a function. However, You can pass a pointer to an array by specifying the array's name without an index. If you want to pass a single-dimension array as an argument in a function, you would have to declare a formal parameter in one of following three ways and all three declaration methods produce similar results because each tells the compiler that an integer pointer is going to be received.

Using a vector, yes:

#include <vector>
using namespace std;

void f( const vector <int> & v ) {
}

int main() {
    f( {1,2,3,4} );
}

Passing arrays to functions, To pass an array as a parameter to a function, pass it as a pointer (since it is a of the same array that is passed to it, and can change what is in that memory. If you want to pass a single-dimension array as an argument in a function, you would have to declare function formal parameter in one of following three ways and all three declaration methods produce similar results because each tells the compiler that an integer pointer is going to be received. Way-1 Formal parameters as a pointer as follows −

Arrays don't work like that. When you pass an array to a function, the address of the first element gets passed like a pointer, and inside the function there is no more information about the size of the array. (Before the compiler itself could infer the size because the array was declared in the scope, but a function can be called from any number of places)

If you want to do something like that you would either have to use a container class, such as a vector, or you could pass a second argument into the function stating the size of the array. Another way is to have some sort of end point in your array, such as is the case with c-strings, for example a null value.

How to pass an array by value in C ?, How to pass array by value, i.e., how to make sure that we have a new copy of array when we pass it to function? This can be done by wrapping the array in a structure and creating a variable of type of that Note that array members are copied when passed as parameter, but dynamic arrays are not. To pass an entire array to a function, only the name of the array is passed as an argument. result = calculateSum(age); However, notice the use of [] in the function definition. float calculateSum(float age[]) { .. } This informs the compiler that you are passing a one-dimensional array to the function.

Passing an array as parameter to a method, Write a Java program that finds the minimum values in 2 different arrays a and b. I.e.: find the minimum value in array a We must pass an array variable as parameter to the method !!! We have never done this before. Can you explain why a[0] was updated ??? Remember the failed attempt to make a copy of an array:� Re: Is it possible to pass an array as a parameter to a macro? Posted 04-11-2013 (1809 views) | In reply to mediaeval var1-var10 is not an array but a SAS Variable List called an enumerated variables list.

Passing arrays to methods, To pass an array to a method, the method declaration should look like this: public static int[] returnArrayMethod() { // method code which includes creating an int e.g. double, is passed to a method, its value is copied to the new method variable. earlier it is not possible for a method to change the value of its arguments. Individual element is passed to function using Pass By Value parameter passing scheme Original Array elements remains same as Actual Element is never Passed to Function. thus function body cannot modify Original Value. Suppose we have declared an array ‘arr ’ then its individual elements are arr,arr …arr.

Passing arrays as arguments, Arrays in C# can be passed as arguments to method parameters. You can initialize and pass a new array in one step, as is shown in the following example. WriteLine(); // Assign new values to individual array elements. A parameter array can be used to pass an array of arguments to a procedure. You don't have to know the number of elements in the array when you define the procedure. You use the ParamArray keyword to denote a parameter array. The array must be declared as an array of type Variant, and it must be the last argument in the procedure definition.

Comments
  • Pass by reference though for great success
  • This answer has worked for me, however when I have a 2D std::array in the parameters (like {{ {"Character", "hello"} }}) as well as a normal std::array, for some reason I get an error saying "cannot convert argument <number> from initializer list to std::array. I will edit my post to include more details.
  • @CodyFG: Please ask another question instead. Because it is irrelevant to keep editing the topic.
  • @M.M: Yea I've pointed to that at the end of the answer. I made the loop variable const auto& as long as I don't extra copy and not changing the elements of the array.
  • OK. I'd not use reference since it is just an int we are talking about, but it is personal preference really
  • @Rietty Not by doing s/vector/array/