How to replace a single character inside a char array?

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I'm trying to figure out how to replace a single character in a char array. I'm just so stuck on how to do this.

int addInsert (char *editing_buffer, char to_insert, int pos){

   editing_buffer[pos-1] = to_insert;


int main() {
    char string[5] = "ABCDE";
    int r = addInsert(string, "Z", 3);

I've tried doing it like that, but it shows as an unreadable symbol. This is my first time ever using C, so I'm still not sure entirely what I'm doing.

1) Your character array initialization is wrong:

char string[5] = "ABCDE";

You are missing room for the terminating NUL character ('\0').


char string[6] = "ABCDE";


char string[] = "ABCDE";

fixes that problem.

2) (presuming addInsert() is supposed to be editor_insert_char()) You pass the wrong type to your function's second parameter. "Z" is a string (a character array), but your function expects a single character.

Call your function like this, using single quotes.:

int r = editor_insert_char(string, 'Z', 3);

Find and replace substrings - MATLAB strrep, If any input argument is a nonscalar string array or cell array of character vectors, then the other input arguments must have Create a character vector and replace a substring within it. Data Types: string | char | cell The old string and new string inputs can be single strings or tall arrays of strings with the same size. C Program To Replace A Character in String. Learn How To Replace A Character in String in C Programming with another User Defined Character. This C Program To Exchange Characters in an Array of Characters, also known as Strings uses three Block Structures:

your initializer-string for array of chars is too long ,if you define char string[5],you can only use 4 characters or less,use char string[5]="ABCD";instead

Replace a Character at a Specific Index in a String in Java, public String replaceCharUsingCharArray(String str, char ch, int index) {. char[] chars = str.toCharArray();. chars[index] = ch;. return String. We can replace the character at a specific index using the method setCharAt(): public String replaceChar(String str, char ch, int index) { StringBuilder myString = new StringBuilder(str); myString.setCharAt(index, ch); return myString.toString(); }

the main issue is that by using double quotes you are passing the Z character as a string literal, i.e an array of chars. As editing_buffer is a char array, when you want to replace one character with another you will have to pass it like a single character which means you have to use single quotes.

"Z" -->  String literal i.e in memory ['Z', '\0']  
'Z' -->  Character i.e ASCII value of Z

So basically you were trying to replace a char with a char*.

C Strings, In fact, C-style strings are really arrays of chars with a little bit of special sauce to literals unless they modify the string (in which case your program will crash). The type of both the variables is a pointer to char or (char*), so you can pass either of them to a function whose formal argument accepts an array of characters or a character pointer. Here are the differences: arr is an array of 12 characters. When compiler sees the statement:

C String Replace, Other examples already provide a way to replace a single character of your choice. String literals are stored in C as an array of chars, terminted by a null byte. Next, it will search and replace the first occurrence of a character inside a string. I want to run through a 'for' loop and replace every character in my buffer, called 'mybuf[256]', with a 'Z', output that to my screen (which is no p Replace a single character in a char array - C - Tek-Tips

Java Char Array, Use char arrays to store characters and create Strings. Measure char Char arrays are faster—we can change text data without allocations. We create a 26- element array and then, in a for-loop, initialize all letters to the lowercase alphabet. C Program to Replace All Occurrence of a Character in a String Example 1. This program allows the user to enter a string (or character array), and a character value. Next, it will search and replace all occurrences of a character inside a string.

C# Char Array, Use char arrays to store character and string data. Char arrays can replace StringBuilder usage. Char arrays can replace StringBuilder usage. Char array. A char array Note: Array elements are stored together in one block of memory. The solution is to create a new string with the given char replaced or removed. Replace. There are multiple ways to achieve the replacement, e.g. using StringBuilder or String.ToCharArray(); Important: Don't forget to make sure the string is not empty or too short - otherwise you would get an exception!

  • Your compiler should be screaming warnings at you for that code. And if not, then enable more warnings. Hint about the problem: Think about the difference between 'Z' and "Z".
  • And if this really is your first time with C, then you're way in over your head. Take many steps back, get a couple of good books (or take classes) and start over from the very beginning.
  • BTW, your question is very poorly formulated, maybe because you don't yet understand what you are doing. Looking back from the code you posted, I'd reformulate along this line: " to replace a single character in a C-type string / character array." Your question might be upvoted then.
  • Your code does not add a character, it replaces an existing one. Very different!
  • "but it shows as an unreadable symbol." --> Posted code does not print anything. See minimal reproducible example
  • You're a life saver!! I can't believe my main issue was the quotation marks... thank you so much!!! i can't thank you enough!
  • Actually the missing room for the NUL-terminator in your original array definition / initialization is a way more dangerous error as it will lead straight into undefined behaviour land even with simple things like passing that string to printf(). If you are happy with my answer, you can accept it.
  • You have missed the most important problem - OP tries to modify string literal, this is UB typically leading to crash
  • @qrdl: "tries to modify string literal": no, as string is a char array and not a char pointer.
  • @qrld As alk already said, you are wrong. Don't confuse beginners with such sloppy answers/comments.
  • Hi, thanks for replying. When I did this the output I got was 'AB�D', the problem I'm having s with this unreadable symbol instead of the letter I'm trying to input?
  • "z" is a string,while 'z' is a character,try to use the 'z'
  • Initializer-string for array of chars is not too long for legal code. It simply means string[] is not a string.