How to make an addition instead of a concatenation

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I have an input button. I created for this input an attribute called "multiplicateur" which has the value of 1. When the button is clicked I have a .click() triggered. The function is suppose to get the value of the attribute and add 1 to it. So my output should be 2. Instead the output is 11. It seems the system makes a concatenation instead of an addition.

My HTML:

<input id="envoyer" type="submit" multiplicateur=1>

My JS:

$('#envoyer').click(function() {
    var ajaxData = $(this).attr('multiplicateur');
    alert(ajaxData + 1);
});

ajaxData is a string. Thus, you need to parse it to an integer...

 $('#envoyer').click(function() {
    var ajaxData = $(this).attr('multiplicateur');

    /* parse string to integer */
    alert(parseInt(ajaxData) + 1);

});

Javascript (+) sign concatenates instead of giving sum of variables , using braces surrounding the numbers will treat as addition instead of concat. The reason you get that is the order of precendence of the operators, and the fact that + is used to both concatenate strings as well as perform numeric addition. I'm trying to add all of the calorie contents in my javascript like this: total = parseFloat(myInt1 + myInt2 + myInt3); $('#response').append(total); Instead How to force addition instead of concatenation - jQuery Forum

You have to parse it first:

    parseInt(ajaxData)+1;

How to force addition instead of concatenation, Instead of adding the variables they get concatenated. I've tried using parseInt, parseFloat, and Number but I still just get concatenation and not� The following statement appends the value to the element with the id of response $('#response').append(total); This makes it look like you are concatenating the strings, but you aren't, you're actually appending them to the element

In order to add value with decimal point, please use parseFloat(ajaxData)

alert(parseFloat(ajaxData) + 1);

Numbers are concatenating instead of adding - Phaser 2, But instead, I get 55. I looked up the API, and it says this.score should be a number so I cannot understand why this is happening� That make sense. I have one more question about DenseNet: What if instead of using 48 Dense connection, use 12 of 4 Dense connections. Will this cause any change in the performance and memory usage? The above question is with concatenation not addition.

For substracting

function removeFromQtt(){
             $("qty").value = parseInt($("qty").value)-1;
 }

For addition

function add(){
             $("qty").value = parseInt($("qty").value)+1;
 }

How To Force Addition Instead Of Concatenation In Javascript , Instead of adding the variables they get concatenated. I've tried using parseInt, parseFloat, and Number but I still just get concatenation and not� Add ability to use concatenation instead of addition in FPN #82 qubvel merged 1 commit into qubvel : master from SiarheiFedartsou : feature/fpn-merge-policy Oct 8, 2019 Conversation 8 Commits 1 Checks 1 Files changed

How to force addition instead of concatenation in javascript, Adding two numbers concatenates them instead of calculating the , If we have two input fields then get the values from input fields, and then add them using� JavaScript - Addition Instead Of Concatenation - Free JavaScript Tutorials, Help, Tips, Tricks, and More.

How to force addition instead of concatenation in javascript [duplicate], Instead of adding the variables they get concatenated. I've tried using parseInt, parseFloat, and Number but I still just get concatenation and not� Some confusion stems from the fact that, in JavaScript, the concatenation operator is the same as that for addition, and so it must decide whether to concatenate the values or add them.

Addition and Concatenation in Java, Basically, Strings take precedence because they have a higher casting priority than integers do. System.out.println(2 + 0 + 1 + 5 + “� It has a preference for concatenation, so even an expression like 3+'4' will be treated as concatenation. Third, JavaScript will attempt to change types dynamically if it can, and if it needs to. For example '2'*'3' will change both types to numbers, since you can’t multiply strings. If one of them is incompatible, you will get NaN, Not a Number.

Comments
  • You code works but when i test it in JS Fiddle it returns an error (Missing radix parameter). Do you know why?
  • @user1162116 It's intriguing your to receiving that error as the second parameter to parseInt is optional. Try passing 10 - parseInt(ajaxData, 10)
  • No error know! Great. What does the second parameter represent?
  • @user1162116 the second parameter is the radix or base (number of unique digits). I assumed you wanted the common base 10