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I am trying to sum the total number from a name table below:
id type num 2 0 90 24 1 38 2 1 878 9 0 8763 9 2 76 9 1 374
There are three types in the
type column, I would like to find all ids which their
type = 0 and
1. for example, in the table, the
id = 2 and
id = 9 have the
type = 0 and
type = 1. So will pick these data and add them together like below:
type: num id 2 - 0:90 1:878 id 9 - 0:8763 1: 374 sum = 90 + 878 + 8764 + 374 = 10,106
I did the query like this:
SELECT SUM(num) FROM table WHERE type = 0 AND type = 1;
ut there is nothing to show. It workq if I change the query to the
type = 0 OR type = 1, but I do not think its right. How to sum
type = 0 and
type = 1?
I am very confused, I am not sure am I explain clearly, if you can give some helps it will be very appreciated.
With this query:
select id from tablename where type in (0, 1) group by id having min(type) = 0 and max(type) = 1
you get all the ids that have both types 0 and 1. So you join it to the table to get the total you want:
select sum(t.num) total from tablename t inner join ( select id from tablename where type in (0, 1) group by id having min(type) = 0 and max(type) = 1 ) g on g.id = t.id where t.type in (0, 1)
See the demo Or without join:
select sum(t.num) total from ( select id, sum(num) num from tablename where type in (0, 1) group by id having min(type) = 0 and max(type) = 1 ) t
See the demo
SQL SELECT DISTINCT Statement, Inside a table, a column often contains many duplicate values; and sometimes you only want to list the different (distinct) values. SELECT DISTINCT Syntax. Get Table information like Column Name, Data Type, Character length, Default Values etc in SQL Server To get the Table in information in SQL Server, we can use below Query: SELECT * FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME = 'Users' ORDER BY ORDINAL_POSITION
This should do the trick:
select sum(a.num + b.num) from ( select id, num from table where type = 0 ) a join ( select id, num from table where type = 1 ) b on a.id = b.id
SQL Server SELECT DISTINCT, The query uses the combination of values in all specified columns in the SELECT list to evaluate the uniqueness. If you apply the DISTINCT clause to a column� Returns a datetime value containing the date and time of the computer on which the instance of SQL Server runs. The returned value does not include the time zone offset. datetime: Nondeterministic: GETDATE: GETDATE ( ) Returns a datetime value containing the date and time of the computer on which the instance of SQL Server runs. The returned
If I understand the question well the answer is quite easy:
SELECT SUM(num) FROM name WHERE type = 0 OR type = 1
You want to sum all
num values from the rows where type = 0 or
type = 1. That's exactly what the above SQL query expresses. Which you've actually come to as well.
Is it that what you need @lily?
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where type = 0 and type = 1. Do you think this will give you any result? The two condition together will never be true. A record can't be both type 0 and 1.