## How to get a and b value from a text like axb?

cartesian product of sets example

cartesian product calculator

cartesian product of a set with itself

cross product

a x b = ab

cartesian product a x b x c

a x b sets

I am facing a problem with how to get a specific *string value* from a *text*. For example: for a given `string`

"400X500 abc"

How can I get some `string`

from that text like:

string width = "400" string height = "500"

Thank you so much for your help.

Best Regards,

Cherry Truong

You can try *regular expressions* in order to *extract* numbers

using System.Text.RegularExpressions; ... string source = "400X500 abc"; string[] numbers = Regex .Matches(source, "[0-9]+") .OfType<Match>() .Select(match => match.Value) .ToArray(); string width = numbers.ElementAtOrDefault(0) ?? ""; string height = numbers.ElementAtOrDefault(1) ?? "";

Or (if you want to be sure that `X`

delimiter is present)

Match match = Regex .Match(source, @"([0-9]+)\s*X\s*([0-9]+)", RegexOptions.IgnoreCase); string width = match.Success ? match.Groups[1].Value : ""; string height = match.Success ? match.Groups[2].Value : "";

**[PDF] CROSS-PRODUCT REVIEW The cross product (or vector product ,** We need to find its magnitude and direction. (See section 3-7 in the text for more review.) Magnitude: |AxB| = A B sinθ. Just like the� Question: 24 S X13dx To!" +C B The Value Of A Is The Value Of B Is X2/3 Da AxB + C = ) The Value Of A Is The Value Of B Is Each Answer Should Be An Integer (like -2 Or 3), A Simplified Proper Fraction (like -2/3), Or A Simplified Improper Fraction (like -3/2).

You can try something like this:

string data = "400X500 abc"; string[] splitData = data.TrimEnd('a', 'b', 'c').Trim().Split('X'); string width = splitData[0] ?? string.Empty; string height = splitData[1] ?? string.Empty;

**Cartesian Product of Two Sets |Cartesian Product|Ordered Pairs ,** If A and B are two non-empty sets, then their Cartesian product A � B is the set of all set of all ordered pairs (a, b) such that a ∈A and b∈B which is denoted as A � B. of 6 elements: If three elements of A � B are (2, 5) (3, 7) (4, 7) find A � B. Thanks for asking me to answer this. I am assuming A and B are 2 vectors and the · and × represent the dot and cross products respectively. The expression can be split across the + sign to give A.(A×B)+B.(A×B).

If you can assume that it will always be in that format, you can do something like this:

string raw = "400X500"; string width = raw.Substring(0, raw.IndexOf("X")); string height = raw.Substring(raw.IndexOf("X") + 1);

Now `width="400"`

and `height=500`

.

**Algebraic_expressions,** Substitution: 'Find the value of 2x + 3 if x = 4.' In this Solving an equation: 'Find x if 2x + 3 = 8. For example, 3 � x is written as 3x and a � b is written as ab. The earliest Chinese text with algebraic ideas is The Nine Chapters on the The solution to one particular case of the cubic, x3 + ax = b (in modern notation), was � The man said that using the formula 'AxB/A+B' you can get the answer. So 5x3=15. And 5+3=8. The answer is 15/8. which is equivalent to 1 hour and 52 and a half minutes.

Assuming the text is always going to be in the format "100X200 aabdsafgds", then a working solution would look something like:

var value = "100X200 aabdsafgds"; var splitValues = value.Split(new[] { 'X', ' ' }, StringSplitOptions.RemoveEmptyEntries); var value1 = splitValues[0]; var value2 = splitValues[1];

**Cartesian Product,** Cartesian Product: The Cartesian product of two sets A and B, denoted A � B, is the set The elements from the two sets form a list of ordered pairs such as the� Value. expression A variable that represents a TextBox object. Remarks. The Text property returns the formatted string. The Text property may be different than the Value property for a text box control. The Text property is the current contents of the control. The Value property is the saved value of the text

I assume the input string is always in the same format.

"heightXwidth abc"

var value = "400X500 abc"; var vals = value.Trim().Split('X'); var height = new string(vals[0] == null ? "0".ToArray() : vals[0].Where(char.IsDigit).ToArray()); var width = new string(vals[1] == null ? "0".ToArray() : vals[1].Where(char.IsDigit).ToArray());

I'm sure you could adjust as needed.

**EDIT:**

I adjusted the code to avoid the issues as pointed out in the comments and ensure you only get the numbers from the string

**Solving linear equations,** An equation of the first degree is called linear because, as we will see much later, its graph is a straight line. become true only when the unknown has a certain value, which we call the solution to the equation. We must get a, b, c over to the other side, so that x is alone. First, you will never see that in any calculus text. I have 3 known matrices A B and C and wish to find X. My question here is why AXB = C ⇔ XB = A^-1 *C and not AXB = C ⇔ XB = C*A^-1 The A^-1 matrix is of size 3x3 and C is 3x2 is it the size that d

**Find the equation of an exponential function,** Solve the resulting system of two equations in two unknowns to find a and b. as years after 2006, we have given ourselves the initial value for the function, a = 80. \(\begin{cases}y=a{b}^{x}& \text{Write the general form of an exponential� where inn each bracket( ) the first element belongs to A and the second to B. 3- As you can find out by inspection they are not the same AxB and BxA. for example (5,1) is an element ob BxA but not of AxB and so the sets cannot be the same.NOTICE that the ORDER of the 2 elements in each ( ) bracket is important.

**Power Functions with Any Exponent,** (It may only be defined for positive values of x.) For example Text. 3. Let f(x)= axb where a and b are nonzero constants. This can also be written as y=axb. Let B=1b and A=(1a)B. Now our inverse equation looks like f−1(x)=AxB. You can get two types of functions; Power Function:f(x)=xa or Exponential Function:f(x )=ax. the tails of A and B, perpendicular to the plane containing them. Grab the axis with your right hand so that your fingers sweep A into B. Your outstretched thumb points in the direction of AxB. Note that BxA gives you a new vector that is opposite to AxB. Why? Because, now you have to sweep B into A. Cross-product facts: BxA = -AxB

**Exploring the solution set of Ax = b (video),** Exploring the solution set of Ax=b (non homogeneous equations) Also in this case if you took Duration: 16:34
Posted: Sep 4, 2014 Write the expression in power form axb for numbers a and b. 40/(2√x)3 I don't even know where to start to be honest. Press J to jump to the feed. Press question mark to learn the rest of the keyboard shortcuts

##### Comments

- You need to provide more details, some example code showing what you're trying to do because it's not clear.
- Whats is
`abc`

in`400X500 abc`

? - is the string in the same format all the time?
- He probably want to split the string by "X" as delimiter. Shouldn't this question be closed as there is no search effort?
- abc mean random text or some description for the specific type of structural beam in my case. For example : "400x500mm" . So I want to get specific string of width and height value of the structural beam from it label.
- Thank you so much for the sharing code. It worked beautiful for me.
- No, in that case you would need to use regex like Dmitry showed.
- yes, but in the original case it says the string is formatted as "400x500 abc", resulting in the not so different endresult of var height = value.Split(' ')[0].Split('x')[0]; var width = value.Split(' ')[0].Split('x')[1];
- In this case,
`vala[1]`

would also contain the postfix`abc`

.