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I'm trying to show a XML "2D list" like this:

<list1>
  <list2>a</list2>
  <list2>b</list2>
  <list2>c</list2>
  <list2>d</list2>
</list1>
<list1>
  <list2>e</list2>
  <list2>f</list2>
  <list2>g</list2>
  <list2>h</list2>
  <list2>i</list2>
  <list2>j</list2>
</list1>

And I would like it to show like this:

01 a
02 b
03 c
04 d
05 e
06 f
07 g
08 h
09 i
10 j

What I thought initially was to have a xsl:variable outside the two for-each and to increment it but the variables are immutable. How can this be done?

Thanks in advance

<xsl:template match="/">
<xsl:apply-templates select="list1/list2"/>
</xsl:template>

<xsl:template match="//list2">
<xsl:value-of select="concat(format-number(position(), '00'), ' ', ., '&#10;')" />
</xsl:template>

HTML DOM childElementCount Property, The children property returns a collection of an element's child elements, as an of the HTMLCollection object to determine the number of child elements, then� Subelement definition, a component or constituent of a whole or one of the parts into which a whole may be resolved by analysis: Bricks and mortar are elements of every masonry wall.

No need for xsl:variable here, or even more than one xsl:for-each (or xsl:apply-templates). You can just select all list2 elements at once, then use position() to get the numbering, because position() is based on the position of the node in the set of selected nodes, not the position in the document tree.

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
  <xsl:output method="text" />

  <xsl:template match="/*">
    <xsl:apply-templates select="list1/list2" />
  </xsl:template>

  <xsl:template match="list2">
    <xsl:value-of select="concat(format-number(position(), '00'), ' ', ., '&#10;')" />
  </xsl:template>
</xsl:stylesheet>

This assumes your XML is well-formed, and all the list1 elements are in a single parent element.

See http://xsltfiddle.liberty-development.net/gWvjQf9

HTML DOM children Property, It is very simple to count the number of child elements of a particular element using JavaScript. For example: If you have a parent element� Note that you cannot use them both at the same time and you need to use MathML to produce both a superscript directly above a subscript next to the chemical symbol of an element, representing its atomic number and its nuclear number. The <msub>, <msup>, and <msubsup> MathML elements. The CSS vertical-align property.

One more possible way to achieve it is:

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

<xsl:output method="xml" indent="yes" />
<xsl:strip-space elements="*" />

<xsl:template match="/root">
    <xsl:variable name="items" select="//list1/list2" />

    <xsl:for-each select="list1">
        <xsl:for-each select="list2">

            <xsl:variable name="id" select="generate-id()" />
            <xsl:for-each select="$items">
                <xsl:if test="generate-id() = $id">
                    <xsl:value-of select="position()" />
                    <xsl:value-of select="concat(' ',.)" />
                    <xsl:text>&#10;</xsl:text>
                </xsl:if>
            </xsl:for-each>
        </xsl:for-each>
    </xsl:for-each>
</xsl:template>

</xsl:stylesheet>

http://xsltransform.net/eieE3Q8/1

How to count all child elements of a particular element using , a number of child elements, stored in a Python sequence. All elements must have a tag, but all other properties are optional. All strings can either be Unicode� the number preceding the letters will identify which of the 7 elements the subs are related to. Then the letters will represent the actual subs. Some will have one letter, some two.

I'm surprised nobody mentioned using xsl:number. That's what I usually use when I have to number something like a list.

Example...

XML Input

<doc>
    <list1>
        <list2>a</list2>
        <list2>b</list2>
        <list2>c</list2>
        <list2>d</list2>
    </list1>
    <list1>
        <list2>e</list2>
        <list2>f</list2>
        <list2>g</list2>
        <list2>h</list2>
        <list2>i</list2>
        <list2>j</list2>
    </list1>
</doc>

XSLT 1.0 (Works in other versions too.)

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="text"/>
  <xsl:strip-space elements="*"/>

  <xsl:template match="list2">
    <xsl:number level="any" format="01 "/>
    <xsl:value-of select="concat(.,'&#xA;')"/>
  </xsl:template>

</xsl:stylesheet>

Output

01 a
02 b
03 c
04 d
05 e
06 f
07 g
08 h
09 i
10 j

Fiddle: http://xsltfiddle.liberty-development.net/gWvjQfa/1

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How to find the number of elements in element tree in python , XML elements can contain other, nested sub-elements. This generic function determines the number of such elements within a specified node. It applies to an � (CLi + 1) * (CRi + 1) will be the number of sub-arrays for the current index i in which its value will be maximum because there are CLi + 1 ways to choose elements from left side (including choosing no element) and CRi + 1 ways to choose elements from the right side. The time complexity of this approach will be O(n 2) Best method:

xmlSize: The number of sub-elements within an XML node. in XML , There are nine sub-elements in Number sense and algebra, four in Measurement and geometry and two in Statistics and probability. The diagram (Figure 1)� I want to find a way to get all the sub-elements of an element tree like the way ElementTree.getchildren() does, since getchildren() is deprecated since Python version 2.7, I don't want to use it anymore, though I can still use it currently. Thanks.

How is the numeracy progression structured?, a number of child elements, stored in a Python sequence Interactions with a single XML element and its sub-elements are done on the� Tip: You can use the length property of the HTMLCollection object to determine the number of elements with the specified name, then you can loop through all elements and extract the info you want. Note: In HTML5, the "name" attribute is deprecated and has been replaced by the "id" attribute for many elements.

Comments
  • This answer is wrong. The first rule matching the document root is not needed. The second rule doesn't output the desired result: position function is relative to the constext list, in this case all the sibilings list2 elements from each list1 father. In short, the enumeration will be restarted. Check in utilities-online.info/xsltransformation/…
  • Correctly points to context list concept for position function.
  • A very unknowingly complex answer.
  • Welcome back @Alejandro !