This question already has answers here :
You can use CTEs
WITH CTE0 AS
(
SELECT
REV_USAGE_DATA.DDATE,
REV_USAGE_DATA.SEGMENT,
COUNT(*) AS Freq
FROM CADA_PERMSISDN_DASH REV_USAGE_DATA
GROUP BY
REV_USAGE_DATA.DDATE,
REV_USAGE_DATA.SEGMENT
)
SELECT
DDATE,
SEGMENT,
FREQ
FROM CTE0
WHERE (DDATE, SEGMENT, FREQ) IN (
SELECT DDATE, MAX(SEGMENT), MAX(FREQ)
FROM CTE0
GROUP BY DDATE
)
Get records with max value for each group of grouped SQL results , How do you get the rows that contain the max value for each grouped set? I've seen some overly-complicated variations on this question, and none with a good � How do you get the rows that contain the max value for each grouped set? I've seen some overly-complicated variations on this question, and none with a good answer. I've tried to put together the simplest possible example: Given a table like that below, with the person, group, and age columns, how would you get the oldest person in each group?
Use ROW_NUMBER():
SELECT DDATE, SEGMENT, Freq
FROM (SELECT REV_USAGE_DATA.DDATE, REV_USAGE_DATA.SEGMENT,
COUNT(*) AS Freq,
ROW_NUMBER() OVER (PARTITION BY REV_USAGE_DATA.DDATE ORDER BY COUNT(*) DESC) as seqnum
FROM CADA_PERMSISDN_DASH REV_USAGE_DATA
GROUP BY REV_USAGE_DATA.DDATE,REV_USAGE_DATA.SEGMENT
) rud
WHERE seqnum = 1
ORDER BY REV_USAGE_DATA.DDATE;
If you have ties on a date and you want all the highest values, then use RANK() instead.
SQL MAX() function with GROUP by, ORDER by, SQL MAX() function with GROUP by, ORDER by: How the GROUP BY can be used to find the maximum value of a column over each group. Note: Outputs of the said SQL statement shown here is taken by using Oracle Database However, actual result turn out that SQL only pick up 1 row of record� Fetch the row which has the Max value for a column (35 answers) Closed 4 years ago . I want to get the values of a column based on max of a different column grouped by another column.
Plenty of similar solutions! Here's mine.
Use a CTE to calculate which record has the highest frequency (similar to row-number) then select them
WITH data AS
(
SELECT
REV_USAGE_DATA.DDATE,
REV_USAGE_DATA.SEGMENT,
COUNT(*) AS Freq
FROM CADA_PERMSISDN_DASH REV_USAGE_DATA
GROUP BY
REV_USAGE_DATA.DDATE,
REV_USAGE_DATA.SEGMENT
),
maxRecords AS
(
SELECT DDATE, SEGMENT, FREQ,
CASE WHEN FREQ = MAX(FREQ) OVER(PARTITION BY DDATE) THEN 1 ELSE 0 END HighestFreq
FROM data
)
SELECT DDATE, SEGMENT, FREQ
FROM maxRecords
WHERE HighestFreq = 1
ORDER BY DDATE;
Having Sums, Averages, and Other Grouped Data, All aggregate functions group data to ultimately produce a single result value. SQL> set feedback on SQL> select SUM(salary) from employee; SUM(SALARY) The query requests a count of all rows and a count of all manager values for all Code Listing 9: MAX and MIN obtain maximum and minimum column values @Craig wrong, this query works in all flavours of rdbms and returns the data as expected, since the OP was not after returning the entire record with the maximum value per group, but wanted the max value per pump. The select list has 2 fields: name and value. Name is in the group by clause and value is aggregated via max.
Tutorial: Aggregating Rows: Databases for , Sum: the result of adding up all the values for the expression in the group; Min: the smallest value in the group; Max: the largest value in the� SQL max() with group by and order by . To get data of 'cust_city', 'cust_country' and maximum 'outstanding_amt' from the customer table with the following conditions - 1. the combination of 'cust_country' and 'cust_city' should make a group, 2. the group should be arranged in alphabetical order, the following SQL statement can be used:
Ask TOM "Howto select first value in a group by bunch of ro", In a query where I group by a field, I would like to select the first values and code_subject into the same values for all rows per same name. The Oracle 10gR2 SQL Reference manual on page 5-68 explains 2 max(emp_name) keep (dense_rank first order by salary) first n rows grouped by a column. SQL ROW_NUMBER Function Example. The SQL ROW_NUMBER Function allows you to assign the rank number to each record present in a partition. In this example, we show you how to Select First Row from each SQL Group. The following SQL Query will. First, partition the data by Occupation and assign the rank number using the yearly income.
GROUP BY clause, In each group, no two rows have the same value for the grouping column or columns. For example, if a GROUP BY clause is in a subquery, it cannot refer to with a GROUP BY clause must contain only aggregates or grouping columns . orig_airport FROM Flights GROUP BY orig_airport SELECT MAX(city_name), � Select Rows with Maximum Value on a Column Example 2. In this example, we will show how to select rows with max value along with remaining columns. It is useful if you want to return the remaining columns (non-group by columns). For this SQL Server example, we used the Inner Join to join the employee table with itself.
Comments worked like a charm. Thank you thank you but this is giving me 4 rows per date. Infact its reproducing the same result set that I shared in my question. @tendaitakas. . . Yup. It would do that wouldn't it? I added the where clause that does the filtering you want.
