## Drawing arrowheads which follow the direction of the line in PyGame

In Pygame, how can I calculate the coordinates for the three points of the head of an arrow, given a start point and an end point for the arrow, so that the arrowhead points in the same direction as the line?

def __draw_arrow(self, screen, colour, start, end): start = self.__coordinate_lookup[start] end = self.__coordinate_lookup[end] dX = start[0] - end[0] dY = -(start[1] - end[1]) print m.degrees(m.atan(dX/dY)) + 360 pygame.draw.line(screen,colour,start,end,2)

I've tried playing around with angles and with the gradient of the line, the fact the Y coordinates increase downwards instead of upwards is throwing me off and I would really appreciate a nudge in the right direction.

This should work:

def draw_arrow(screen, colour, start, end): pygame.draw.line(screen,colour,start,end,2) rotation = math.degrees(math.atan2(start[1]-end[1], end[0]-start[0]))+90 pygame.draw.polygon(screen, (255, 0, 0), ((end[0]+20*math.sin(math.radians(rotation)), end[1]+20*math.cos(math.radians(rotation))), (end[0]+20*math.sin(math.radians(rotation-120)), end[1]+20*math.cos(math.radians(rotation-120))), (end[0]+20*math.sin(math.radians(rotation+120)), end[1]+20*math.cos(math.radians(rotation+120)))))

Sorry for the poorly organized code. But as you said, the coordinates starting in the top-left do require some math to be flipped. Also, if you want to change the triangle from being equalatiral to something else you just have to change the `rotation +/- 120`

in line 4, or the `20*`

for a different radius.

Hope this helps :)

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I denote start and end coordinates as `startX, startY, endX, endY`

dX = endX - startX dY = endY - startY //vector length Len = Sqrt(dX* dX + dY * dY) //use Hypot if available //normalized direction vector components udX = dX / Len udY = dY / Len //perpendicular vector perpX = -udY perpY = udX //points forming arrowhead //with length L and half-width H arrowend = (end) leftX = endX - L * udX + H * perpX leftY = endY - L * udY + H * perpY rightX = endX - L * udX - H * perpX rightY = endY - L * udY - H * perpY

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Vladimir's answer is great! For anyone visiting in the future, here's the function with control over every aspect of the arrow:

def arrow(screen, lcolor, tricolor, start, end, trirad): pg.draw.line(screen,lcolor,start,end,2) rotation = math.degrees(math.atan2(start[1]-end[1], end[0]-start[0]))+90 pg.draw.polygon(screen, tricolor, ((end[0]+trirad*math.sin(math.radians(rotation)), end[1]+trirad*math.cos(math.radians(rotation))), (end[0]+trirad*math.sin(math.radians(rotation-120)), end[1]+trirad*math.cos(math.radians(rotation-120))), (end[0]+trirad*math.sin(math.radians(rotation+120)), end[1]+trirad*math.cos(math.radians(rotation+120)))))'

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