How to extract the string between 2 characters in same line on python
I have a text file with alphanumeric filenames:
\abc1.txt. \abc2.txt \abc3.txt \abcde3.txt \Zxcv1.txt \mnbd2.txt \dhtdv.txt
I need to extract all
.txt extensions from the file, which will be in the same line and also different line in the file in python.
abc1.txt abc2.txt abc3.txt abcde3.txt Zxcv1.txt mnbd2.txt dhtdv.txt
I appreciate your help.
If I were you, I would use regular expressions (regex).
import re # Open the file with the mode r, which means read the file with open("text_file.txt", "r") as f: # Actually read the content of the file file_content = f.read() # Find everything which matches the given regex code # This returns a list of the matches files = re.findall(r"\\(.*?.txt)", file_content) # Iterate through each item in the list for file in files: # Print the item print(file)
Here is the explaination of the regex that I used: https://regex101.com/r/DAPlqM/1
How to extract the substring between two markers?, In python, extracting substring form string can be done using findall method in regular expression ( re ) module. You can find first substring with this function in your code (by character index). Also, you can find what is after a substring. >>> s = '/tmp/10508. Simple python script to extract sub string between two delimiters of a string. Examples of delimiters are brackets, parentheses, braces, single or double quotes etc. You can also customize this code to extract the string between two special characters or two sub strings. Comments on each line of code explains you to easily understand the code.
string = r"\abc1.txt. \abc2.txt \abc3.txt \abcde3.txt \Zxcv1.txt \mnbd2.txt \dhtdv.txt" list = string.split("\\") print(list) formatted = "\n".join(list) print(formatted)
['', 'abc1.txt. ', 'abc2.txt ', 'abc3.txt ', 'abcde3.txt ', 'Zxcv1.txt ', 'mnbd2.txt ', 'dhtdv.txt'] abc1.txt. abc2.txt abc3.txt abcde3.txt Zxcv1.txt mnbd2.txt dhtdv.txt
How to get the substring between two markers in Python, Code faster with the Kite plugin for your code editor, featuring Line-of-Code Completions and cloudless processing. Extracting the substring between two known marker strings returns the characters between the two markers as a new string. Python offers many ways to substring a string. It is often called ‘slicing’. It follows this template: string[start: end: step] Where, start: The starting index of the substring. The character at this index is included in the substring. If start is not included, it is assumed to equal to 0. end: The terminating index of the substring. The character at this index is NOT included in the
You can use
re.findall with a pattern that matches two words delimited by a
import re print('\n'.join(re.findall(r'\w+\.\w+', s)))
Given your input text in variable
s, this outputs:
bc1.txt bc2.txt bc3.txt bcde3.txt Zxcv1.txt mnbd2.txt dhtdv.txt
Extract string between two delimiters- GetHowStuff, Simple python script to extract sub string between two delimiters of a string. extract the string between two special characters or two sub strings. Comments on each line of code explains you to easily understand Note: This code is written in Python 2 Excel combine multiple cells into one separated by. A Python program can read a text file using the built-in open() function. For example, the Python 3 program below opens lorem.txt for reading in text mode, reads the contents into a string variable named contents, closes the file, and prints the data.
Extract text from a file between two markers, For simple cases, this could also be solved with a regular expression. Extract Values between two strings in a text file using python � printing lines between start� Method #2 : Using regex( findall() ) In the cases which contain all the special characters and punctuation marks, as discussed above, the conventional method of finding words in string using split can fail and hence requires regular expressions to perform this task.
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Given your sample input, it looks like every line begins and ends with brackets. In which case, forget regexps, this is trivial: for line in whatever: contents = line.strip()[1:-1] (I've added the strip in case your line source is leaving the newlines in, or there are invisible spaces after the closing bracket in your input. If it's not
- What have you tried so far?
- for more exact matching files = re.findall(r"\(.*?.txt\b)", file_content) will help
- @Justin Remember that you have to escape the backslash. So this is better:
files = re.findall(r"\\(.*?.txt\b)", file_content)