Creating a program that searches if a word is repeated and how many times it is in a list,

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So far I have created this:

    a = str(input("Word 1 = "))
    b = str(input("Word 2 = "))
    c = str(input("Word 3 = "))
    d = str(input("Word 4 = "))
    e = str(input("Word 5 = "))
    f = str(input("Word 6 = "))

words = [a, b, c, d, e, f]

def count_words(words):
    for i in words:
        wordscount = {i:words.count(i)}
        print(wordscount)

count_words(words)

And this is what comes out:

{'word': 6}
{'word': 6}
{'word': 6}
{'word': 6}
{'word': 6}
{'word': 6}

And my question is how can I make it so it doesn't print the key in the list if it already has so for example not the above but this:

{'word': 6}

You should slice the array and check if the word you're going to print hasn't already been checked.

def count_words(words):
    for index, i in enumerate(words):
        wordscount = {i:words.count(i)}
        if i not in words[0:index]:
            print(wordscount)

See also that I used enumerate() to keep track of the index inside your loop.

Python, Many times it is required to count the occurrence of each word in a text file Note : Make sure the text file is in same directory as the Python file. for key in list (d. keys()): Python program to Count the Number of occurrences of a key-value Find the first repeated word in a string in Python using Dictionary� I need to write a program that asks the user for some text and then checks how many times the word "owl" is repeated in there. The program should also count the word if it's included in another one. Ex "hellowl" should return; The word "owl" was repeated 1 time.

First of all, welcome to Stack Overflow!

A solution to your problem would involve initialising another list, probably called words_mentioned above your loop, and adding to it the words that you've already printed. If the word is in words_mentioned, don't print it. Final code would look like this:

a = str(input("Word 1 = "))
b = str(input("Word 2 = "))
c = str(input("Word 3 = "))
d = str(input("Word 4 = "))
e = str(input("Word 5 = "))
f = str(input("Word 6 = "))

words = [a, b, c, d, e, f]
words_mentioned = []

def count_words(words):
    for i in words:
        wordscount = {i:words.count(i)}
        if i not in words_mentioned:
            print(wordscount)
            words_mentioned.append(i)

count_words(words)

Python, Python | Count occurrences of each word in given text file (Using dictionary) � Python program to Count the Number of occurrences of a key-value� The Problem As an author I want to know the number of times each word appears in a sentence So that I can make sure I'm not repeating myself. Acceptance Criteria Given a sentence When the program is run Then I'm returned a distinct list of words in the sentence and the number of times they have occurred

In order to not count words more than once, you could use a set in your for i in words: loop: replace it with for i in set(words):

You could also use the Counter() class from iterTools:

from itertools import Counter
print( Counter(words) )

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Generating a Count of Word Occurrences (Microsoft Word), If you are searching for individual words, make sure you click the list is in descending order based on how many times the word If you don't like to use macros for some reason, there are other programs you can use to create word counts. What if I dont know the word and want to find repeating words! Sorting the list is as easy as calling the sort() function. After the example calls the sort() function, it prints the list again so that you can see the result. Choose Run→Run Module. You see a Python Shell window open. The application outputs both the unsorted and sorted lists. You may need to sort items in reverse order at times.

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