How to extract a valid number from string even if it is followed by zeroes

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A question for sed and awk experts.

If I have a string like this : ABCDEF00012300XYZ. I want to extract the number that follows the alphabets and the zeroes. So, I want to extract 12300 from the string.

By spirit, I just want extract the valid number in the string. 00012300 means 12300 in mathematical sense.

I tried the following

VALID_NUMBER="$(echo $STR | awk '{sub(/.*0+/,"");sub(/[a-zA-Z]+/,"")} 1')"

Above works if I pass ABCDEF000123XYZ and it extracts 123 from STR. But fails if 123 is followed by zeroes in which case it should get 12300.

Note that this is sed on linux that I am using

Excel: Extract number from text string, When it comes to extracting a number from an alphanumeric string, Microsoft In our case, the result will be a numeric substring, which in terms of Excel is also text, not number. just notice the right-aligned values in column B and truncated leading zeros. Incredible product, even better tech support… 1) Start traversing the given string. Continue traversing if there are any leading zeroes or any lowercase character. b) Form a string of integer values. c) Update the maximum string. i) If the maximum string and current string are having equal lengths then on the basis of the first unmatched value return maximum string.

Another awk:

$ awk '
match($0,/[1-9][0-9]*/) {            # match first non-zero leading string of numbers
    print substr($0,RSTART,RLENGTH)  # and print it
}' <<< ABCDEF00012300XYZ             # or you could echo ... | awk ...

Or sed:

$ sed -E 's/(^[^1-9]*|[^0-9]+$)//g' <<< ABCDEF00012300XYZ

That sed script replaces from the beginning all [^1-9] and from the end [^0-9].

Find all the numbers in a string using regular expression in Python , This pattern will extract all the characters which match from 0 to 9 and the + sign indicates one or more occurrence of the continuous characters. Example #1 – How to Extract Numbers Positioned from Right. As you might have seen while extracting characters from a string, the most important thing we should know is the position of the last character.

Could you please try following(tested with GNU awk).

echo "ABCDEF00012300XYZ" |
awk '
    print val

Explanation: Adding explanation for above code.

echo "ABCDEF00012300XYZ" |               ##Printing value by shell echo command here and sending its output as standard input for awk command.
awk '                                    ##Starting awk command here.
  match($0,/[a-zA-Z]+0+[0-9]+/){         ##Using match for matching regex for continous alphabets with continous zeros and then following digits in match OOTB function of awk.
    val=substr($0,RSTART,RLENGTH)        ##Creating variable val whose value is sub string of current line whose starting point is RSTART till value of RLENGTH.
    gsub(/[a-zA-Z]+[^1-9]0+/,"",val)     ##Using gsub to globally substituting alphabets then continous zeroes Leaving other digits(till other digit occurence comes) for val here.
    print val                            ##Printing val value here.
   val=""                                ##Nullifying variable val here.
}'                                       ##Closing BLOCK for awk program here.

Extract numbers from mixed string - MATLAB Answers, Extract numbers from mixed string. Follow. 1,050 views (last 30 days) question Jan: what if you want to find all the uccurrence of a numeric value between two strings? This is how I went about it, all steps included even the errors. nums = zeros(length(a),1); for k = 1:length(a) nums(k) = str2double(str(a(k):b(k))); end� pandas.Series.str.extract¶ Series.str.extract (* args, ** kwargs) [source] ¶ Extract capture groups in the regex pat as columns in a DataFrame. For each subject string in the Series, extract groups from the first match of regular expression pat. Parameters pat str. Regular expression pattern with capturing groups. flags int, default 0 (no flags)

Another GNU awk solution:

$ STR=ABCDEF00012300XYZ                                                          

$ awk -v str="$STR" 'BEGIN{print gensub(/[A-Za-z0]+([0-9]+).*/, "\\1", 1, str)}' 

However, if it's not limited to after alphabets and zeros, then it's better like this:

awk -v str="$STR" 'BEGIN{print gensub(/[^1-9]*([0-9]+).*/, "\\1", 1, str)}' 

Example: Matching Floating Point Numbers with a Regular Expression, Detailed example of building a regex to match a floating point number as an point number as an optional sign, followed by an optional series of digits (integer part), In fact, it even considers an empty string as a valid floating point number. To extract number from a text, we need to know 2 things: Starting position of the number in text; Length of the number; For example, in text US $ 31330.00 the number starts at 6th letter and has a length of 8. So, if we can write formulas to get 1 & 2, then we can combine them in MID formula to extract the number from text!

With Parameter Expansion :

echo "valid_number = $str"

Regular Expression (Regex) Tutorial, Take note that this regex matches number with leading zeros, such as "000" , " 0123" This regex matches any non-empty numeric strings (comprising of digits 0 to 9), It begins with at least one word character [a-zA-Z0-9_] , followed by more back-reference, is used to extract the matched substring from the input string. Extract Number from String with User Defined Function Assuming that you have a list of data in range B1:B5, in which contain text string values, and you want to eextract all numbers from each cell in which contain letters and numbers.

More Examples Of Regular Expressions, By examining typical examples of the strings we want to match: Valid numbers are: 1.0, .02, +0., 1, +1, -0.0120; Invalid numbers (that is, strings we do not want to recognise as numbers but superficially look like them): -, +., 0.0.1, 0..2, We can easily extract the parentheses and put them in a list (the -inline option does that): I have a string series[Episode 37]-03th_July_2010-YouTube and I want to extract the number which comes directly after Episode (eg: 37 from Episode 37)the position ofEpisode 37` may not be fixed in the string. I tried: def extract_episode_num(self,epiname): self.epiname = epiname try: self.temp = ((self.epiname.split('['))[1]).split(']')[0] #

Regex Remove Leading Zeros, It doesn't avoid non-numeric values. I am trying to extract all numbers from a string but I got the below code to work newStr is a single piece of text even when expression or replace is a cell array of character vectors or a string array. 0 or else a single non-zero digit followed by an optional number of additional digits). Regex extract number from a string with a specific pattern in Alteryx-1. Regex in CSS sheet. Is it valid to change the model after seeing the results of test data?

Java Add Leading Zeros To Int, Checks whether the String a valid Java number. or add zeros to the Java also has a type called long that has a larger range, but even values of (And follow the "format string" link found in the method description for format. One straightforward way to do this is to extract digits separately (using integer division and mod). which returns 7, the position of the number 3 in the string "apples30". Overview. The formula looks complex, but the mechanics are in fact quite simple. As with most formulas that split or extract text, the key is to locate the position of the thing you are looking for. Once you have the position, you can use other functions to extract what you

  • Perfect. Works! Thanks for the explanation about the character match