Removing patterns in list

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I have a list as following:

list=[80,"error",100,74,72,71,"error",39,38,63,"error",82,"error",62,75,23,77,87,"error",36]

and I want to remove "error" from the list :

llist=len(list)

for i in range(llist):
     if list[i]=="error":
         del list[i]
         llist-=1

print(list)

but the compiler still display,"if list[i]=="error": IndexError: list index out of range".

Where am I wrong? Thanks in advance!

Your fix:

llist=len(list_)

for i in range(llist):
    try:
         if list_[i]=="error":
             del list_[i]
             llist-=1
    except IndexError:
        pass
print(list_)

OUTPUT:

[80, 100, 74, 72, 71, 39, 38, 63, 82, 62, 75, 23, 77, 87, 36]

Suggested:

Looks like you only need the numbers from the list:

import numbers
print([x for x in list_ if isinstance(x, numbers.Number)])

OUTPUT:

[80, 100, 74, 72, 71, 39, 38, 63, 82, 62, 75, 23, 77, 87, 36]

OR:

print([num for num in list_ if isinstance(num, (int,float))])

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First don't use keyword list as variable name. Then conditional list comprehension is an easy way to do it:

my_list = [i for i in my_list if i != "error"]

Your problem here is that you are modifying the list length while trying to iterate over it. Perfect recipe for errors...

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Try using remove function.

l = ['a', 'b', 'error', 'c']
l.remove('error')

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Try this :

list1 = [i for i in list1 if i != 'error']

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Try :

>>> list1=[80,"error",100,74,72,71,"error",39,38,63,"error",82,"error",62,75,23,77,87,"error",36]
>>> filter(lambda a: a != "error", list1)
[80, 100, 74, 72, 71, 39, 38, 63, 82, 62, 75, 23, 77, 87, 36]

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DeleteCases—Wolfram Language Documentation, DeleteCases[expr, pattern] removes all elements of expr that match pattern. DeleteCases[expr Deleting elements from a nested Association: Copy to clipboard�

Overriding or removing resource ignore patterns, Overriding or removing resource ignore patterns. After you have added global file -matching patterns to the list of files to be ignored for version management, you�

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