Python get coordinate with pair of nans

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I have a dataframe like this

>>df1 = pd.DataFrame({
          'A': ['1', '2', '3', '4', '5'],
          'B': ['1', '1', '1', '1', '1'],
          'C': ['c', 'A1', NaN, 'c3', Nan],
          'D': ['d0', 'B1', 'B2', Nan, 'B4'],
          'E': ['A', Nan, 'S', Nan, 'S'],
          'F': ['3', '4', '5', '6', '7'],
          'G': ['2', '2', NaN, '2', '2']
        })
>>df1

    A   B     C     D     E   F     G
0   1   1     c    d0     A   3     2
1   2   1    A1    B1   NaN   4     2
2   3   1   NaN    B2     S   5   NaN
3   4   1    c3   NaN   NaN   6     2
4   5   1   NaN    B4     S   7     2

and I would like to get the coordinates of all nans. that is the output should be:

[[1,"E"], [2,"C"] , [2,"G"] , [3,"D"] ,[3,"E"] , [4,"C"] ]

All other questions i looked at just want the column name and not the pairs.

Is there any efficient way to solve this problem? Thank you

Use stack with filter index values by missing values:

s = df1.stack(dropna=False)
L = [list(x) for x in s.index[s.isna()]]
print (L)
[[1, 'E'], [2, 'C'], [2, 'G'], [3, 'D'], [3, 'E'], [4, 'C']]

sklearn.metrics.pairwise.nan_euclidean_distances — scikit-learn , scikit-learn: machine learning in Python. Compute the euclidean distance between each pair of samples in X and Y, where Y=X is If all the coordinates are missing or if there are no common present coordinates then NaN is returned for that pair. get distance to origin >>> nan_euclidean_distances(X, [[0, 0]]) array([[1. ]� Python assigns an id to each variable that is created, and ids are compared when Python looks at the identity of a variable in an operation. However, np.nan is a single object that always has the same id, no matter which variable you assign it to. import numpy as np one = np.nan two = np.nan one is two. np.nan is np.nan is True and one is two is also True.

Try using np.where:

df = pd.DataFrame({'A': ['1', '2', '3', '4','5'],
          'B': ['1', '1', '1', '1','1'],
          'C': ['c', 'A1', np.nan, 'c3',np.nan],
          'D': ['d0', 'B1', 'B2', np.nan,'B4'],
          'E': ['A', np.nan, 'S', np.nan,'S'],
          'F': ['3', '4', '5', '6','7'],
          'G': ['2', '2', np.nan, '2','2']})

arr = np.where(df.isna())
arr
(array([1, 2, 2, 3, 3, 4], dtype=int64),
 array([4, 2, 6, 3, 4, 2], dtype=int64))

np.where returns the indices where the given condition is True, here where df is null.

[(x, df.columns[y]) for x, y in zip(arr[0], arr[1])]

[(1, 'E'), (2, 'C'), (2, 'G'), (3, 'D'), (3, 'E'), (4, 'C')]

Split Lat/Long Coordinate Variables Into Separate Variables, Try my machine learning flashcards or Machine Learning with Python Cookbook. Split Lat/Long Coordinate Variables Into Separate Variables if you get an error except: # append a missing value to lat lat.append(np. NaN) # Create two new columns from lat and lon df['latitude'] = lat df['longitude'] = lon� You obtained the same result as with the pure Python implementation. If you have nan values in a dataset, then gmean() will return nan. If there’s at least one 0, then it’ll return 0.0 and give a warning. If you provide at least one negative number, then you’ll get nan and the warning. Median. The sample median is the middle element of a

You could use np.argwhere with pd.isna, like this:

result = [[r, df1.columns[c]] for r, c in np.argwhere(pd.isna(df1).values)]
print(result)

Output

[[1, 'E'], [2, 'C'], [2, 'G'], [3, 'D'], [3, 'E'], [4, 'C']]

Geocoding And Reverse Geocoding, Python offers a number of packages to make the task incredibly easy. dataframe structures, and numpy for its missing value (np.nan) functionality. strings, with each coordinate in a coordinate pair separated by a comma. comma to lon lon.append(float(row.split(',')[1])) # But if you get an error except:� Python Tuples. Python provides another type that is an ordered collection of objects, called a tuple. Pronunciation varies depending on whom you ask. Some pronounce it as though it were spelled “too-ple” (rhyming with “Mott the Hoople”), and others as though it were spelled “tup-ple” (rhyming with “supple”).

How to find the indices of rows in a pandas DataFrame containing , Kite is a free autocomplete for Python developers. DataFrame containing NaN values results in a list of the indices of the rows in the DataFrame.iterrows() to iterate over each index, row pair in pandas. Get Kite updates & coding tips. import arcpy # Set the workspace environment arcpy.env.workspace = "c:/base/base.gdb" # Get a list of the feature classes in the input folder feature_classes = arcpy.ListFeatureClasses() # Loop through the list for fc in feature_classes: # Create the spatial reference object spatial_ref = arcpy.Describe(fc).spatialReference # If the spatial reference is unknown if spatial_ref.name == "Unknown

NumPy, SciPy, and Pandas: Correlation With Python – Real Python, Each of these x-y pairs represents a single observation. In Python, nan is a special floating-point value that you can get by using any of the following: can access them with either their labels or their integer position indices:. scipy.ndimage.map_coordinates¶ scipy.ndimage.map_coordinates (input, coordinates, output = None, order = 3, mode = 'constant', cval = 0.0, prefilter = True) [source] ¶ Map the input array to new coordinates by interpolation. The array of coordinates is used to find, for each point in the output, the corresponding coordinates in the input.

Outputs `NaN,NaN` for invalid geometry centroids � Issue #31, Do we ignore the NaN coordinates and keep the rest of the geometry I tried to load the file as dumped by pyesridump (including the NaN 's) in the source but got: File "/usr/local/lib/python3.4/dist-packages/ijson/backends/python.py", Do we skip the coordinate pair or do we ditch the whole geometry? Python | Pandas dataframe.get_value() Python is a great language for doing data analysis, primarily because of the fantastic ecosystem of data-centric python packages. Pandas is one of those packages and makes importing and analyzing data much easier.

Comments
  • Do you mean None or nan?
  • Sorry i meant NaN