How to generate a random dictionary?

I need to create a dictionary with key and random values given a scope, i.e.

{key 1: value1, key 2: value2, key 3: value1, key 4: value 1, key 5: value 1}

or

{key 1: value2, key 2: value1, key 3: value1, key 4: value 1, key 5: value 1}

or

{key 1: value1, key 2: value1, key 3: value1, key 4: value 1, key 5: value 2}

...and so on

As you can see, the dictionary has the pattern below:

  • the key is generated from the input number of the function, if I input 5, I have 5 keys, if I input 3, I have 3 keys
  • the value has only 2 different values (value1 and value2), but value2 can only appear 1 time randomly in any key. The remaining values will be value1.

Code:

def function(n):
   from random import randrange
   mydict = {}
   for i in range(5):
         key = "key " + str(i)

   value = ['value1', 'value2']

Just default all the values to value1 first, and then randomly pick one key to change to value2:

def function(n):
   from random import randrange
   values = ['value1', 'value2']
   mydict = {"key " + str(i): values[0] for i in range(n)}
   mydict["key " + str(random.randrange(n))] = values[1]

   return mydict

Python, The choice function performs the task of random value selection and list method is The original dictionary is : {'Gfg': 1, 'best': 3, 'is': 2} The random pair is : ('is', 2) Please use ide.geeksforgeeks.org, generate link and share the link here. Method #1 : Using random.choice () + list () + items () The combination of above methods can be used to perform this task. The choice function performs the task of random value selection and list method is used to convert the pairs accessed using items () into a list over which choice function can work. filter_none.

I think the fastest way would be to use the built-in dict.fromkeys() classmethod to create a dictionary full of value1 entries and then randomly change one of them.

import random

def function(n):
   mydict = dict.fromkeys(("key "+ str(i) for i in range(n)), 'value1')
   mydict["key "+ str(random.randrange(n))] = 'value2'  # Change one value.
   return mydict

print(function(3))  # -> {'key 0': 'value1', 'key 1': 'value1', 'key 2': 'value2'}
print(function(5))  # -> {'key 0': 'value2', 'key 1': 'value1', 'key 2': 'value1', 'key 3': 'value1', 'key 4': 'value1'}

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You can simply try this:

>>> def func(n):
...   mydict = {}
...   for i in range(n):
...     mydict['key'+str(i)] = randrange(10)
...   return mydict
... 
>>> print(func(5))
{'key0': 8, 'key1': 2, 'key2': 4, 'key3': 4, 'key4': 7}

How to get a random entry from a dictionary in Python, How to get a random entry from a dictionary in Python. Randomly choosing a key -value entry from a dictionary gives each entry equal selection probability. You can change how much random text Word generates by filling in what’s between the parentheses. To do that, you’ll use =Rand (x,y), where x is the number of paragraphs and y is the number of sentences in each paragraph. For example, if you want seven paragraphs that each contain four sentences, you’d use the following formula: =Rand (7,4)

similar to @Idlehands, but parametrized for n and actually returns the dict

def function(n):
    from random import randrange, randint
    mydict = {'key'+str(i):'value1' for i in range(n)}
    mydict['key'+str(randint(0,n-1))] = 'value2'
    return mydict

print(function(5))

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Your question is not terribly clear to me, but I think this is what you are trying to do:

   from random import randrange
   mydict = {}
   value = ['value1', 'value2', 'v3', 'v4', 'v5']

   for i in range(5):
         key = "key " + str(i)
         mydict.update(key: value[i])

Your list either has to be 5 values long (or more) or your for loop has to iterate only twice.

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This AI Generates Random Gibberish Words With 'Dictionary , The website even allows users to submit their own words where it can then generate dictionary definitions. The platform is powered by GPT-2, a� Try these simple steps to create random numbers: Create function: private int randomnumber(int min, int max) { Random rnum = new Random(); return rnum.Next(min, max); } Use the above function in a location where you want to use random numbers. Suppose you want to use it in a text box. textBox1.Text = randomnumber(0, 999).ToString();

Comments
  • Is there any constraint on the number of key-value pairs that will be present in the dict?
  • @Idlehands The OP hasn't mentioned the total number of key-value pairs to be generated.
  • @taurus05 The number of keys would be dynamic based on description, but the constraint is that there will always be two values, and only one of them will be value2. If the conditions are changed we can revisit this solution.
  • Thanks. I made some changes and now it works!! def function(n): from random import randrange import random mydict = {} mydict = {"key " + str(i): 'value1' for i in range(1,n+1)} mydict["key "+ str(random.randrange(1,n+1))] = 'value2' return mydict
  • You could also just use str(random.randrange(n)+1) as well :)
  • Is fromkeys more efficient than a dict comprehension? Genuinely curious.
  • @Idlehands: I haven't actually timed the two, but fromkeys() is written in C, so is likely faster. Using Python's built-ins whenever possible is often a good way to improve performance.
  • You piqued my interest, so I timed it. For a dict generation of 100 keys with n=1000000 trial, the performance between fromkeys (53.68s) and dict comp (54.38s) are relatively comparable. IIRC comprehensions uses C code too so it should be similar.
  • @Idlehands: I guess that doesn't surprise me too much in this particular case because it's still generating the keys iteratively using user-supplied (i.e. relatively-slow interpreted) Python code.