print every nth line into a row using gawk

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I have a very huge file in which I need to obtain every nth line and print it into a row.

My data:

1      937  4.320194
2      667  4.913314
3      934  1.783326
4      940  -0.299312
5      939  2.309559
6      936  3.229496
7      611  -1.41808
8      608  -1.154019
9      606  2.159683
10     549  0.767828

I want my data to look like this:

1      937  4.320194
3      934  1.783326
5      939  2.309559
7      611  -1.41808
9      606  2.159683

This is of course an example, I want every 10th line for my huge data file. I tried this so far:

 NF == 6 {
     if(NR%10) {print;}
     }

To print every second line, starting with the first:

awk 'NR%2==1' file.txt

To print every tenth line, starting with the tenth line:

awk 'NR%10==0' file.txt

To use this in a script, add the following to a file called script.awk:

BEGIN {
    print "Processing file"
}

NR%10==0

END {
    print "Finished processing"
}

Then execute:

awk -f script.awk file.txt

Every Nth line position # (AWK) Using awk, awk 'NR%3==1' file - (Every Nth line position # (AWK) A better way to show the file lines 3n + 1). The best command line collection on the internet, submit yours and save your favorites. Print only the odd lines of a file (GNU sed) commandlinefu.com is the place to record those command-line gems that� Hi, I have a comma separated file. I would like to print every alternate columns into a new row. Example input file: Name : John, Age : 30, DOB : 30-Oct-2018 Example output: Name,Age,DOB John,30,30-Oct-2018 (3 Replies)

With sed, you can do a lot of variations on this quite easily with the first~step command. For instance:

# Odd lines
sed -n 1~2p file
# Every tenth line (10, 20, 30, ...)
sed -n 10~10p file
# Every tenth line (1, 11, 21, ...)
sed -n 1~10p file
# First plus every tenth (1, 10, 20, 30, ...)
sed -n -e 1p -e 10~10p file

Printing every Nth line out of a large file into a new file, awk 'NR % 5 == 0' input > output. This prints every fifth line. To use an environment variable: NUM=5 awk -v NUM=$NUM 'NR % NUM == 0' input > output. Then from the command line, I try to print the first, second and third fields from the file tecmintinfo.txt using the command below: $ awk '//{print $1 $2 $3 }' tecmintinfo.txt TecMint.comisthe From the output above, you can see that the characters from the first three fields are printed based on the IFS defined which is space: Field one which

Piece of cake: cat test.txt | awk 'NR % 10 == 1'

How to keep only every nth line of a file, For example, ``sed -n 1~2p'' will print all the odd-numbered lines in the input stream, and the address 2~5 will match every fifth line, starting with the second. first� This built-in ability to process every line in the input file is a great feature of awk. While all of these examples show how awk works on a file, it can also read its input from a Unix pipeline, like this: $ cat foo | awk '{ print $3, $1 }' 3 1 c a Using a field separator with awk

It's not (g)awk, but it'll work:

cat myfile | grep ^[[:digit:]]*0[[:blank:]] should do the trick.

Print every nth line - UNIX and Linux Forums, Dear all, How to print every nth line. File like this: Code: File input: 1 1 1 1 1 1 2 2 2 3 3 3 Please help me print nth line after match awk or sed one line command. While trying to do it for a single file , i am using sed sed '3 i this is the 4th line'� Print a line from multiple files. Suppose we have two files, file1.txt and file2.txt, We can use the above commands and print particular line from multiple files by

Doing it directly in command Prompt (Windows).

Put the gawk.exe file in the folder where the file is and start a command Prompt in the folder, and write

gawk "NR%n==x" oldfile.txt>newfile.txt

n is every n'th line you want to print and x is the starting line.

E.g n=10 and x=1, printing line 1,11,21,31,41......end line from the original file into the new file.

E.g n=20 and x=5, printing line 5,25,45,65......end line from the original file into the new file.

How to print every nth line in a file in Linux?, variable in Perl is equivalent to awk's NR. Only those lines are printed whose modulus is not equal to 0. 4. Bash shell script: #!/usr/bin/bash x� This variable gets appended after every line that gets output. In this example, it gets changed on every 3rd line from a comma to a newline. For lines 1, 2 it’s a comma, for line 3 it’s a newline, for lines 4, 5 it’s a comma, for line 6 a newline, etc. Recommended Reading. Sed and Awk 101 Hacks, by Ramesh Natarajan. I spend several hours

Using awk to extract lines in a text file, in a text file. awk is not an obvious choice as a tool for strictly extracting rows from a text file. A more interesting task is to extract every nth line from a text file. What we are saying here is, as we go line-by-line in this file, if the value in column 7 is equal to 6 then the match is true and the line is included in the output. I’m piping, using the | operator, the results to head to keep the output concise for this blog. Now we want to test the other part of the conditional on the Pos column.

How to remove every other line with sed?, Vim: how to delete every second row?, PS: To go to command mode just press How can I delete every Xth line in a text file?, sed -n -e 'p;N;d;' file # print every� Mokhtar.. thanks for the help.. I was wondering how do I extend the previous code.. where I need to extract the 4th and 5th value from every nth row and concatenate those values to the rows n+1 to 2n-1.. I know you have to do a nested for loop.. I am not a programmer so any help would be appreciated.

3 ways to get the Nth Line of a File in Linux, The need to get/print a particular line of a file on the Linux shell is a common For example, sed will output the 25th line of sample_data_1.txt with each of the awk has a built in variable NR that keeps track of file/stream row� Special Files: File name interpretation in gawk. gawk allows access to inherited file descriptors. Close Files And Pipes: Closing Input and Output Files and Pipes. The print Statement. The print statement does output with simple, standardized formatting. You specify only the strings or numbers to be printed, in a list separated by commas.

Comments
  • Shouldn't that be awk 'NR%10==0' file.txt?
  • @D.Shawley Yes you are correct. I should really read things through before answering! Cheers!
  • Thank you so much, I know it was a simple question but I couldn't figure it out for the life of me.
  • If there anyway to execute this in a script?
  • HTH. Also, you don't need either the BEGIN or END blocks.
  • @Gerard See: stackoverflow.com/questions/30003570/…
  • That prints the line following every 10th line - lines 1, 11, 21, 31, etc. You want lines where the modulus is zero instead of 1.
  • Well, why? This also prints every 10th line, starting with the first, and it matches with what is given as example.