How can get a column where my result is 1 2 3 6 7 8 I want to exclude the common IDs from both the table and display the result in one column

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Let's say I have Two tables T1 and T2 with ID as the column. For example

T1:ID

1              
2              
3              
4              
5   

T2:ID

4
5
6
7
8

How can get a column where my result is 1 2 3 6 7 8 I want to exclude the common IDs from both the table and display the result in one column.


Hmmm . . . one method is union all:

select t1.id
from table1 t1
where not exists (select 1 from table2 t2 where t2.id = t1.id)
union all
select t1.id
from table2 t2
where not exists (select 1 from table1 t1 where t2.id = t1.id);

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use minus

select id from 
(
select id from t1 
union 
select id from t2
) a
minus select id from (
select  id from t1 join t2 on t1.id=t2.id
) b 

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If your DBMS support FULL OUTER JOIN then i would do :

select coalesce(t1.id, t2.id)
from t1 full outer join
     t2
     on t2.id = t1.id
where (t1.id is null or t2.id is null);

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