Finding nth letter in alphabet from current letter

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So I am trying to take a letter from the alphabet, input by the user, and then finding the letter that is 10 letters away, and I want it to wrap around the alphabet if the letter is 'z' or 'y' or anything that is < letter 16.

I am struggling with the looping part. I know that the alphabet is just thrown into the ASCII table with numbers that are not 1-26, so I am not sure how to deal with it. This is what I have so far.

public static void main(String[] args){

    Scanner input = new Scanner(System.in);
    System.out.println("Please input your favorite letter");
    char userLetter = input.next().charAt(0);
    char newLetter = (char) ((userLetter + 10) % 26);

    System.out.println("10 letters beyond your letter is " + newChar);

}

Can anyone help?

We can try mapping both lowercase and uppercase alphabet characters to a 1-26 scale, then shift and possibly wrap using the modulus. Finally, we keep track of the shift amount, so that we may add it back to generate the shifted character.

Scanner input = new Scanner(System.in);
System.out.println("Please input your favorite letter");
char userLetter = input.next().charAt(0);

// get the ASCII value of the input character
int ascii = (int) userLetter;
// compute the shift (97 for lowercase, 65 for uppercase)
int shift = ascii > 90 ? 97 : 65;

int newPosition = (ascii - shift + 10) % 26;
newPosition += shift;

char newChar = (char) newPosition;
System.out.println("10 letters beyond your letter is " + newChar);

Replacing letters with numbers with its position in alphabet, First of all, you don't need to hardcode the letters and their positions in the alphabet - you can use the string.ascii_lowercase . Also, you don't have to call list () on� So I am trying to take a letter from the alphabet, input by the user, and then finding the letter that is 10 letters away, and I want it to wrap around the alphabet if the letter is 'z' or 'y' or anything that is < letter 16. I am struggling with the looping part.

Instead you could just use the valueOf combination.

String userLetter = ...;
int charValue = userLetter.charAt(0);
String next = String.valueOf((char)(charValue + 10));

Then just just an if statement to detect when it reaches A or Z and change it accordingly.

Hope this helps.

How to Extract the Nth Letter from Left, The result returns the third letter "w". Explanations: Step 1: To find the length of the text string;. Formula, =LEN(A1)� This does not answer the given question; instead, it goes the other way. Given a letter, it will return a number indicating that letter's position relative to the start of the alphabet, regardless of case. (And it would be easier to force the letter to upper or lower case to start.) – Mogsdad Apr 14 '16 at 17:35

it is called CaesarCipher s is your shift count

//A Java Program to illustrate Caesar Cipher Technique 
public class CaesarCipher 
{ 
    // Encrypts text using a shift od s 
    public static StringBuffer encrypt(String text, int s) 
    { 
        StringBuffer result= new StringBuffer(); 

        for (int i=0; i<text.length(); i++) 
        { 
            if (Character.isUpperCase(text.charAt(i))) 
            { 
                char ch = (char)(((int)text.charAt(i) + 
                                s - 65) % 26 + 65); 
                result.append(ch); 
            } 
            else
            { 
                char ch = (char)(((int)text.charAt(i) + 
                                s - 97) % 26 + 97); 
                result.append(ch); 
            } 
        } 
        return result; 
    } 

    // Driver code 
    public static void main(String[] args) 
    { 
        String text = "ATTACKATONCE"; 
        int s = 10; 
        System.out.println("Text : " + text); 
        System.out.println("Shift : " + s); 
        System.out.println("Cipher: " + encrypt(text, s)); 
    } 
} 

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Try this :

public static void main(String[] args) {

    public static void main(String[] args) {

    Scanner input = new Scanner(System.in);
    System.out.println("Please input your favorite letter");
    char userLetter = input.next().charAt(0);
    int unumber = (int) userLetter;

    int newNum=unumber+10;


    if(newNum>122 || newNum>90){

        newNum=(unumber)-(26-10);
    }

    char newLetter = (char) (newNum);


    System.out.println("10 letters beyond your letter is " + newLetter);
}

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Python: Remove the nth index character from a nonempty string , Write a Python program to remove the nth index character from a nonempty string . Python String Flowchart: Flowchart: Remove the nth index character from a non empty string Resetting will undo all of your current changes. c = input(" Enter the alphabet to be deleted:") for i in b: if i == c: e = a.find(c) Get row letter of current cell. Copy one of the following formulas, paste it into the active cell, and press the Enter key to get the relative letter. =CHAR(ROW()+64) =LEFT(ADDRESS(1,ROW(),2),1+(ROW()>26)) Get column letter of current cell. Copy one of the following formulas, paste it into the active cell, and press the Enter key to get the

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Comments
  • @JohnForbes Hi John. If you look in my code you can see that I have used modulo for wrapping. The problem is that in the ASCII table the alphabet is not numbered 1-26. But I do have an idea now
  • This is a very elegant way to do this. Thank you, it works perfectly!