"if elif" statement dependent on input won't run after placing my input
My problem is the script ends immediately after I enter an input.
def add(var1, var2):
print(var1 + var2)
def times(var1, var2):
print(var1*var2)
x = input("press 1 to add, press 2 to multiply: ")
if x == 1:
print("what two number do you want to add?")
a = input("input first number: ")
b = input("input second number: ")
add(a, b)
elif x == 2:
print("what two number do you want to multiply?")
a = input("input first number: ")
b = input("input second number: ")
times(a, b)
I want the script to run the if-elif statement which is dependent on the entered input.
The input function returns a string. You should therefore either compare its returning value to a string instead of an integer:
if x == '1': ... if x == '2':
or convert the returning value to an integer first:
x = int(input("press 1 to add, press 2 to multiply: "))
The input will be a string not a number, and 2 != '2'. You need to convert the input to an integer before trying to use it.
input() will return str, you need to convert it to int before calculating.
x = input("press 1 to add, press 2 to multiply: ")