How to remove triplicate letters and leave duplicate in python?

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Basically, I want to leave the double letters like 'ss' in guess and remove the 'iiiiiiiiiiiiiiii'

I'm cleaning data for text analytics.

s_input = "guess who just got shoes boiiiiiiiiiiiiii"

print(''.join(i for i, _ in itertools.groupby(s_input ))) #this also takes out the 'ss' in guess

>"guess who just got shoes boi"

The intent is to get the following "guess who just got shoes boi"

notice, 'guess' keeps the 'ss'

You could use re.sub to get this done

Return the string obtained by replacing the leftmost non-overlapping occurrences of pattern in string by the replacement repl. If the pattern isn’t found, string is returned unchanged. repl can be a string or a function; if it is a string, any backslash escapes in it are processed.

import re

s_input = "guess who just got shoes boiiiiiiiiiiiiii"
print(re.sub(r'(\w)\1{2,}',r'\1',s_input))

output:

guess who just got shoes boi

Remove all duplicates from a given string in Python, Function to remove all duplicates from string. # and keep the order of characters same. def removeDupWithOrder( str ):. return "".join(OrderedDict.fromkeys( str )). The following approach can be followed to remove duplicates in O(N) time:. Start from the leftmost character and remove duplicates at left corner if there are any. The first character must be different from its adjacent now.

You could do:

print(''.join(i if len(g) > 2 else ''.join(g) 
              for i, g in itertools.groupby(s_input)
              for g in [list(g)]))

But that would be rather bad.

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For complicated generators, I like to write a generator function:

import itertools

def kill_long_dups(s):
    for key, group in itertools.groupby(s):
        group = list(group)
        if len(group) > 2:
            yield key
        else:
            yield from group


s_input = "guess who just got shoes boiiiiiiiiiiiiii"
print(''.join(kill_long_dups(s_input)))

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