Converting array to Linked list - from Eloquent Javascript

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It is one of the challenge in the book I fail to understand, or my brain is unable to break it down. Here is the solution function:

 function arrayToList(array) {
  var list = null;
  for (var i = array.length - 1; i >= 0; i--)
    list = {value: array[i], rest: list};
  return list;
}

console.log(arrayToList([10, 20]));
// → {value: 10, rest: {value: 20, rest: null}}

so we are looping the array inversly so first time list should be:

list = {value:20, rest:{value:20, rest:**mind blows here**}}

can any one help me through this process?

Just step through it, keeping track of the values of each name/variable as you go:

Initially:

array = [10, 20]
list = null
i = 1

Next step:

array = [10, 20]
list = {value: 20, rest: null}
i = 1

Next step:

array = [10, 20]
list = {value: 20, rest: null}
i = 0

Next step:

array = [10, 20]
list = {value: 10, rest: {value: 20, rest: null}}
i = 0

At this point the loop, and the function, ends.

The key is when operations are performed. Since this is imperative style programming (as opposed to (pure) functional), the value associated with a name (variable) can be changed during the execution of the code. So when list is read and when list is assigned a new value is crucial.

Data Structures: Objects and Arrays :: Eloquent JavaScript, It is called an array and is written as a list of values between square brackets, separated by commas. value named “x”, value[x] tries to evaluate the expression x and uses the result, converted to a string, as the property name. A linked list. Java List to Array Examples. Nov 18, 2015 Array, Core Java, Examples, Snippet comments Although a List is a more powerful than an array, there are cases where we wish to convert the former to the latter's data structure. For example, if there is an existing API where the expected parameter is an Array, but what you have is a List.

Here it is:

function L(val){
    this.val = val;
    this.next = null;
}

//We have to develop
/*
L{
    val:1,
    next:{
        val:2,
        next: {
            val:3,
            next: {
                val:4,
                next:null
            }
        }
    }
}
*/

function createL(a){
    let node, temp;
    for(let i=a.length-1; i >= 0; i--){
        if(!node)
            node = new L(a[i]);
        else {
            temp = new L(a[i]);
            temp.next = node;
            node = temp;
        }
    }
    return node;
}

createL([1,2,3,4]);

Converting an array to a list (eloquent javascript) : learnjavascript, Click here for a link to the YouTube playlist. I have already uploaded about 2/3 of the total course videos, and will continue to upload new ones as I complete them. O ne of the best ways to understand the use of spread operator in JavaScript is to look at the the built-in functions Math.min() and Math.max(), which both expect a list of arguments, not an array

Basically you create an object that has inside 2 elements. first element is the value, the second element is the rest of the list. in the line list = {value:20, rest:{value:20, rest:list}} we are basically creating the list from end to start, so you always add the list former status. so let's say we had 3 elements [10,20,30]. 1. we start in 30 - creating an object called list with the elements value = 30, list = null. 2. we are in 20 - taking the list object that looks like this {value:30, rest:null} and placing it inside of a new object with the 20 value, so we have {value: 20, rest:{**old list** --> {value:30, list:null} }} now we change the reference of list to point to the newly created object. list = {value: 20, rest:{**old list** --> {value:30, list:null} }} 3. we do the same as in 2.

now you have a list. (hope I was clear)

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With some extra logs

function arrayToList(array) {
    var list = null;
    for (var i = array.length - 1; i >= 0; i--) {
        console.log(i);//2, then 1
        console.log(array[i]);//20, then 10
        list = {
            value: array[i],
            rest: list//null, then {value:20, rest: null}
        };
    }
    return list;
}
console.log(arrayToList([10, 20]));
//{ value: 10, rest: { value: 20, rest: null } }

you can see that although you are iterating through the list in reverse, the list object's value property will be the last iterated array element. The rest property will be a copy of list at that iteration.

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Comments
  • what will be the output of this: console.log(arrayToList([10, 20, 30, 40, 50])); When I am executing this, I get: { value: 10, rest: { value: 20, rest: { value: 30, rest: [Object] } } }. Where are the remaining nodes??
  • They are there. Your browser's console limited the amount of output it displayed. You can interactively inspect your object right there in the console and see all of it.