## MySQL getting percentage of count

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My Data would like this

Name Similar_Percentage A 15 B 20 C 65

I want like this

Similar_Percentage count(*) Less than 20 2 Less than 70 1

How to write a query for this. I know having make this but it show one by one data.

use case when

select case when Similar_Percentage<20 then 'Less than 20' when (Similar_Percentage<70) then 'Less than 70' end as Percentage,count(*) from table group by case when Similar_Percentage<20 then 'Less than 20' when (Similar_Percentage<70) then 'Less than 70' end with cte as ( select 15 as Similar_Percentage union all select 20 union all select 65 )select case when Similar_Percentage<=20 then 'Less than 20' when (Similar_Percentage<70) then 'Less than 70' end as Percentage,count(*) from cte group by case when Similar_Percentage<=20 then 'Less than 20' when (Similar_Percentage<70) then 'Less than 70' end

Percentage count(*) Less than 20 2 Less than 70 1

**Getting percentage of "Count(*)" to the number of all items in ,** I'm not sure of the MySql syntax, but you can use a sub-query as shown. 100 AS percent FROM Item as I, (SELECT COUNT(*) AS total FROM� Summary: in this tutorial, you will learn how to use the MySQL COUNT() function to return the number rows in a table. Introduction to the MySQL COUNT() function. The COUNT() function is an aggregate function that returns the number of rows in a table. The COUNT() function allows you to count all rows or only rows that match a specified condition.

Another approach can be like following.

SELECT 'Less than 20' Percentage, Count(*) [Count(*)] FROM tablename WHERE similar_percentage <= 20 UNION ALL SELECT 'Less than 70' Percentage, Count(*) [Count(*)] FROM tablename WHERE similar_percentage <= 70 AND similar_percentage > 20

**Calculating percentage of count and adding it to the count in MySQL ,** For general case use your original query as derived table: SELECT cnt + (cnt * 0.75) AS total FROM ( SELECT COUNT(order_id) AS cnt FROM� use subquery to get total records and then calculate percent by using count of data for each state using group by clause. SELECT user8, concat((count( * ) *100 / (SELECT count( * ) FROM `lm_users`)) , "%") AS percent FROM `lm_users` GROUP BY user8

Use a `case`

*expression* in a *derived table* (the subquery) to do the classification. `GROUP BY`

its result:

select percentage, count(*) from ( select case when Similar_Percentage <= 20 then 'Less than 20' when Similar_Percentage <= 70 then 'Less than 70' else 'More than 70' end as percentage from tablename ) dt group by percentage

**mysql - get the percentage of a row count of all counts,** say select count(*) as thecount , fname, count(*)/sum(count(*)) as percentage and you get thecount fname percentage 4 sara 10 19 mike 7 lou Issues getting percentage and count of duplicates in table? Ask Question Asked 5 years, 2 months ago. Adding multiple columns AFTER a specific column in MySQL. 48.

MySQL allows you to use column aliases in the `group by`

. This simplifies the query.

I also recommend an explicit `order by`

, so you get the results in the order you want:

select (case when Similar_Percentage <= 20 then 'Less than 20' when Similar_Percentage < 70 then 'Less than 70' end) as Percentage, count(*) from cte group by Percentage order by min(Similar_Percentage)

**Calculate Percentage with Count,** I need a query to count number of records depending on percentage, means I have a student database with their marks, now I want to count� Pandas count and percentage by value for a column. Published a year ago 1 min read. Insert multiple rows at once with Python and MySQL. 3 Python, Linux, Pandas

**MySQL: Get percentage of COUNT's??,** I need a 1 more column showing %'s of each COUNT(*) in a row to the total. - SUM(COUNT(*)) doesn't work, so I can't get the %. - Subquerying� ProductID ProductName SupplierID CategoryID Unit Price; 1: Chais: 1: 1: 10 boxes x 20 bags: 18: 2: Chang: 1: 1: 24 - 12 oz bottles: 19: 3: Aniseed Syrup: 1: 2: 12

**Calculating percentages from MySQL [SOLVED],** use subquery to get total records and then calculate percent by using count of data for each state using group by clause. SELECT user8� Visualize what a percentage represents. A percentage is an expression of part of the whole. 0% represents nothing, and 100% represents the entire amount. Everything else is somewhere in between! For example, say you have 10 apples. If you eat 2 apples, then you have eaten 2 out of the whole 10 apples (2 / 10 × 100% = 20% eaten).

**Calculating percentage in a MySQL query and round off the result,** For this, you can use CONCAT() and round(). Let us first create a table −mysql> create table DemoTable1844 ( Number int, TotalNumber i @Digitalsa1nt (100 * 2) / 4 = 50, (2/4) * 100 = 50 as long as the enumerator is is the part being multiplied. Due to precedence of SQL statements it will be the same. however, due to data types if using 100 you can still get the result rounded to 0 decimals you desire for the % where as if you put it after the division operation you would have to make sure that you cast to a data type that can

##### Comments

- Are you sure that the expected output is correct? I think the count column should be in reverse order
- In your sample data you have 1 value < 20 and 3 values < 70
- I want count over percentage. Thanks for your ques. @HarshilDoshi
- You are right I don't think about this I want between record 1 between 20 is this and 20 between 70 is that thanks for your suggestion.
- then you should update the question