Is there a way to count and loop with plain SQL?
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I have the following tables:
album:
albumID, albumTitle, albumReleaseDate, albumLabel, albumDigitalImg, albumCoverStory
albumTrack:
trackID, albumID, recordingID, albumTrackNumber, cd
italic = primary key
bold = foreign key
The question is as follows:
List the total number of tracks on each album that has any. Give the column containing the total number of tracks a sensible name and use albumId to identify each total.
My only idea would be to iterate over each albumID and check how many tracks are assigned to it but obviously loops aren't a thing in plain SQL? Is there any way to do this using plain SQL?
This only checks how many tracks are assigned for albumID 1, not for all albums and I'm really lost as to how I could do this without a loop.
SELECT COUNT(albumID) FROM albumTrack WHERE albumID = 1;
I'm using Oracle.
Below query will give you the number of tracks against each albumID,if any.
SELECT albumID,count(trackID) as NumberOfTracks FROM albumTrack Group By albumID;
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You can try:
Select ab.albumID, Count(Distinct trackID) As trackCount From album ab Inner Join albumTrack at on at.albumID = ab.albumID Group By ab.albumID;
This will give the count of tracks for each album.
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The question asks for the counts per albumID.
For just that, a select on albumTrack alone with a GROUP BY
on the albumID should be sufficient.
SELECT albumID, COUNT(*) AS TotalTracks FROM albumTrack GROUP BY albumID ORDER BY albumID
But if albumTrack.albumID can be NULL, or isn't a foreign key on album.albumID?
Then an INNER JOIN
on the "album" table should still be used.
To make sure that it only counts for albumID's that actually exist in the "album" table.
SELECT tracks.albumID, COUNT(*) AS TotalTracks FROM albumTrack AS tracks JOIN album ON album.albumID = tracks.albumID GROUP BY tracks.albumID ORDER BY tracks.albumID
And if you'd like to show the counts per albumTitle:
SELECT a.albumTitle, COUNT(t.trackID) AS TotalTracks FROM album a JOIN albumTrack t ON t.albumID = a.albumID -- WHERE a.albumID = 1 GROUP BY a.albumID, a.albumTitle ORDER BY a.albumTitle
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Comments
- Kindly share some sample data and desired output.
- sample data and desired output: i.imgur.com/DFsxJBk.png
- The question is trivial. And answer for its is each sql tutorial. (count employees in department) Type of rdbms is not relevant here.