## Multiplying each sublist by a constant

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l2=[[13,11,9],[7,5,3],[1]]

I want to multiply each sublist in list `l2`

with a constant number i.e 13*1,11*1,9*1 and 7*2,5*2,3*2 and 1*3 and the final result would be 13,11,9 and 14,10,6 and 3.

Using `enumerate`

**Ex:**

l2=[[13,11,9],[7,5,3],[1]] print([[j*i for j in v] for i, v in enumerate(l2, 1)])

**Output:**

[[13, 11, 9], [14, 10, 6], [3]]

**Python,** Given a list of lists, the task is to multiply each element in a sublist by its index and return a summed list. Given below are a few methods to solve the problem. Set up a column of numbers you want to multiply, and then put the constant in another cell. 2. In a new cell, type "=" and click the first cell you want to multiply. 3. Type the name of the cell

You can leverage `enumerate`

here:

l2 = [[13,11,9],[7,5,3],[1]] l3 = [[x * (idx + 1) for x in sublist] for idx, sublist in enumerate(l2)] print(l3)

This yields

[[13, 11, 9], [14, 10, 6], [3]]

**Python,** Sometimes, when we are fed with the list of list, we need to multiply each of its a loop to get all the elements and it's nested components and multiply accordingly. Sublist Maximum in custom sliced List � Python - Constant Multiplication over� To multiply a constant to each and every element of an array, use multiplication arithmetic operator *. To multiplication operator, pass array and constant as operands as shown below. b = a * c. where a is input array and c is a constant. b is the resultant array. Example. In the following python example, we will multiply a constant 3 to an array a.

Try this:

l2=[[13,11,9],[7,5,3],[1]] counter = 1 for i in range(len(l2)): for j in range(len(l2[i])): l2[i][j] *= counter counter += 1 print(l2)

**I have a list with lists. How do I multiply a number x with the last ,** Print the parent list and verify each last element of each sub-list is now x times larger than their original values, with n. Continue Reading. Multiply each equation by a constant that would help to eliminate the y terms. 2x-5y=-21 3x-3y=-18 - 12296200

Is it always the first sublist is 1, the 2nd is two, etc?

for i in range(0, len(l2)): i += 1 print(f'{l2[i-1]} times {i}') print(list(map(lambda x: x*i, l2[i-1])))

**Multiplying two dimensional data by a constant,** You can change 2 in 2 y to whatever constant you want. E.g. Suppose you want to multiply the first dimension by 3 and the second by 2 , you simply write: is faster, by about factor 3) (and it doesn't make sense to compare to all the others ,� 1. Enter the certain number in a blank cell (for example, you need to multiply or divide all values by number 10, then enter number 10 into the blank cell). Copy this cell with pressing the Ctrl + C keys simultaneously. 2. Select the number list you need to batch multiply, then click Home > Paste > Paste Special. See screenshot: 3.

One liner with `map`

and `enumerate`

[map((idx).__mul__, sublist) for idx,sublist in enumerate(l2,1)] #[[13, 11, 9], [14, 10, 6], [3]]

using `numpy.multiply`

import numpy as np [np.multiply(sublist,[idx]).tolist() for idx,sublist in enumerate(l2,1)]

**multiply every item in a 2D list by a scalar in python,** python multiply all elements in list by constant Given a list of lists l. flat_list = [ item for sublist in l for item in sublist] which means: flat_list = [] for sublist in l: for� I cannot seem to find a way to multiple a column with a constant. For example I have total sales. Now I need to set the target is 15%. The measure would loke like Target Sales = XXX(financials[Sales]) * 15%) + (financial[Sales]) I don't know which function to use in my case. Thank you

**How to multiply two lists in Python,** Multiplication between two equal length lists multiplies each element from one list by the element at the same index in the other list. For example, multiplying [1,� Select the range that you want to multiply a value, and click Home > Paste > Paste Special. See screenshot below: 3. In the Paste Special dialog box, click All option in the Paste section, and click Multiply option in the Operation section, and click the OK button. See screenshot above: And the selected range will be multiplied by the number 8.7. See screenshot below:

**[PDF] Divide-and-conquer algorithms,** Thus our method for multiplying n-bit numbers starts by making recursive calls to This merge procedure does a constant amount of work per The three sublists SL,Sv, and SR can be computed from S in linear time; in fact, this compu-. A Computer Science portal for geeks. It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive programming/company interview Questions.

**How to multiply positions of a list of lists,** Python, Given a list of lists, the task is to multiply each element in a sublist by its You can then convert the iterator to list Multiplying a constant to a NumPy array� PLEASE HELP ME Multiply each equation by a constant that would help to eliminate the y terms. 2 x - 5 y = -21. 3 x - 3 y = -18. What are the resulting equations? A) 6 x - 15 y = -63. -15 x + 15 y = 90.

##### Comments

- All that has been posted is a program description. However, we need you to ask a question. We can't be sure what you want from us. Please edit your post to include a valid question that we can answer. Reminder: make sure you know what is on-topic here;
**asking us to write the program for you**, suggestions, and external links are**off-topic.** - This is a more general versionof stackoverflow.com/questions/43671999/… .. if the list would contain the same number instead of different ones... similarly question is here stackoverflow.com/questions/26446338/… and there are about a dozend more on SO already
- Type Errror:'int' object is not iterable
- Your error makes no sense. At least not with this code.
- Yes the first sublist is always 1
- why not
`range(1,len(l2)+1)`

to remove an extra step - I thought about that, too. Figured it was about 50/50 on which was better.