Return the last item in an array to first spot

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Is there a better approach to my code below. my code is working, but I'm just wondering if there is a better way to it. I have an array and i want to return the last item in this array to the first spot.

const replce = arr => {
       let n = arr.pop();
       arr.splice(0, 0, n);
       return arr;
    };

console.log(replce(['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h']));

You can use Pop with destructing.

let arr = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h']
let last = arr.pop()
let final = [last,...arr]

console.log(final)

Get the first and last item in an array using JavaScript, Javascript array is a variable which holds multiple values at a time. The first and last elements are accessed using an index and the first value is accessed using� Get the first and last item in an array using JavaScript Javascript array is a variable which holds multiple values at a time. The first and last elements are accessed using an index and the first value is accessed using index 0 and the last element can be accessed through length property which has one more value than the highest array index.

const replce = arr => {
   return arr.unshift(arr.pop()) && arr;
};

console.log(replce(['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h']));

Get first and last elements from Array and Vector in CPP , Given an array, find first and last elements of it. Input: {4, 5, 7, 13, 25, 65, 98} Output: First element: 4 Last element: 98. Using slice() We can also use the slice()method to get the last element of the array. If we provide negative index -1to it then it will remove the last item and return it as a new array. let arr = [1, 2, 3, 4, 5, 6, 7, 8];

Two variables values can be swapped in one destructuring expression. Please refers to doc Destructuring assignment

var arr = ['a', 'b', 'c', 'd','e','f','g','h'];
[arr[0], arr[arr.length-1]] = [arr[arr.length-1], arr[0]];
console.log(arr);

Array.prototype.shift(), the first element from an array and returns that removed element. has similar behavior to shift , but applied to the last element in an array. String myString = "the"; int myIndex = Array.LastIndexOf( myArray, myString ); Console.WriteLine( "The last occurrence of \"{0}\" is at index {1}.", myString, myIndex ); // Searches for the last occurrence of the duplicated value in the first section of the Array. myIndex = Array.LastIndexOf( myArray, myString, 8 ); Console.WriteLine( "The last occurrence of \"{0}\" between the start and index 8 is at index {1}.", myString, myIndex ); // Searches for the last occurrence of the duplicated

You can use unshift() with pop() Refer this. Unshift adds an element to the first index in the array

const replce = arr => {
   let n = arr.pop();
   arr.unshift(n)
   return arr;
};
console.log(replce(['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h']));

Indexed collections, reverse() transposes the elements of an array, in place: the first array element becomes the last and the last becomes the first. It returns a� Tip 7 in this Useful JavaScript Hacks Article proposes the following method to get the last item in an array. syntax1.js. 1. 2. var array = [ 1, 2, 3, 4, 5, 6 ]; console .log (array.slice ( -1 ) [ 0 ]); // 6. It is a very neat and readable alternative to the often seen: syntax2.js. 1.

unshift() will add to the start of an array, and pop() will remove from the end of the array. Example below will show you how to do this.

const replace = arr =>{
	let tempvalue = arr.pop();
	arr.unshift(tempvalue);
	return arr;
}
console.log(replace(['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h']));

Array methods, Here we can see that splice returns the array of removed elements: The call to arr.sort() sorts the array in place, changing its element order. On the first run, sum is the initial value (the last argument of reduce ), equals 0� When it reaches the end of the array, it will "step back" to the last valid value – the last 1 – which corresponds to the last match based on criteria provided. INDEX and MATCH array version The beauty of the LOOKUP function is it can handle the array operation described above natively, without requiring you to enter as an array formula with control + shift + enter.

Get the last element of an Array in JavaScript, Tip 7 in this Useful JavaScript Hacks Article proposes the following method to get the last item in an array. syntax1.js. 1. 2. var array = [� element_at (array, index) - Returns element of array at given (1-based) index. If index < 0, accesses elements from the last to the first. Returns NULL if the index exceeds the length of the array. from pyspark.sql.functions import element_at, split, col df = spark.createDataFrame( [ ('a b c d',)], ['s',]) df.withColumn('arr', split(df.s, ' ')) \ .select( col('arr') [0].alias('0th') , col('arr') [3].alias('3rd') , element_at(col('arr'), -1).alias('1st_from_end') ).show

How to Manipulate Arrays in JavaScript, This method removes the last item of an array and returns it. 'have', 'a', 'meeting' , 'tommorrow']; // removes 4 first elements and replace them� When you need to see the last value in an Excel Table or data range, these formulas will get the job done. This walk-through details the necessary formulas and some VBA code that performs the same

Class: Array (Ruby 2.5.0), Elements in an array can be retrieved using the #[] method. The special methods first and last will return the first and last elements of an array, respectively. Rotates self in place so that the element at count comes first, and returns self . Return the First and Last Values in a Range October 9, 2013 by Mynda Treacy 12 Comments I’ve been asked many times how to find either the cell reference of the first or last value in a range, or even return the values from those cells, and there are many ways to do it.

Comments
  • What do you mean by "better"? "my code is working" see Code Review
  • instead of splice you can use unshift. answers from this post will help you.
  • Your usage of && is confusing. The pop/unshift part is completely unrelated to return, you're just pretending that this is a oneliner at the cost of readability.
  • the logic is simple. also arr.unshift(arr.pop()) it returns the element put in the front. And when we know we have the array at the front , we are returning the array after modification
  • the logic may be simple, but the way you put it is confusing. That's pointless obfuscation. You could put pop/unshift on a separate line and it would become much cleaner. Making oneliners at the cost of readability is not a virtue.
  • Mate you can add your code to code snippet that will make it easier to see running example on the go
  • Sure thing mate.