How to create an array from a given array of ranges
scala create array from range
constant time range add operation on an array
scala array of arrays
scala create array of n elements
increment array index
create an array in spark
I have this code:
pg=[(10, 19), (30, 32), (37, 38), (50, 59), (63, 64), (69, 69), (120, 121), (124, 129), (130, 139), (160, 161), (164, 169), (180, 182), (185, 185), (189, 189), (190, 192), (194, 194), (196, 199), (260, 269), (270, 279), (300, 309), (330, 339), (358, 359), (360, 369)]
Those are given ranges, for example,
pg should be 10,
pg be 11,
pg be 12. and so on for the rest of the ranges. So I want the final array to be like this:
pg=[10, 11, 12, 13 ....19, 30, 31,....,32,37, 38,50,51,....,59,63.. and so on]
How can I do this in python? Is it possible to do it without hard coding every range of elements in a new array?
I guess the following might work
pg = [(10, 19), (30, 32), (37, 38), (50, 59), (63, 64), (69, 69), (120, 121), (124, 129), (130, 139), (160, 161), (164, 169), (180, 182), (185, 185), (189, 189), (190, 192), (194, 194), (196, 199), (260, 269), (270, 279), (300, 309), (330, 339), (358, 359), (360, 369)] arr =  for val in pg: arr += list(range(val, val + 1)) print(arr)
Scala, By using range() method to generate an array containing a sequence of increasing integers in a given range. We can use final argument as jump to create the Those are given ranges, for example, pg should be 10, pg be 11, pg be 12. and so on for the rest of the ranges. So I want the final array to be like this
This is one approach using a list comprehension and
itertools.chain(to flatten the list)
from itertools import chain pg=[(10, 19), (30, 32), (37, 38), (50, 59), (63, 64), (69, 69), (120, 121), (124, 129), (130, 139), (160, 161), (164, 169), (180, 182), (185, 185), (189, 189), (190, 192), (194, 194), (196, 199), (260, 269), (270, 279), (300, 309), (330, 339), (358, 359), (360, 369)] result = list(chain.from_iterable([range(*i) for i in pg])) print(result)
Print modified array after multiple array range increment operations , Efficient Approach: Create an array sum of size n and initialize all of its index with the value 0. Now for each (start, end) index pair apply the given operation on For example, to create an array with 10 numbers, you can hard-code a string into INDIRECT like this: = ROW(INDIRECT("1:10")) The INDIRECT function interprets this text to mean the range 1:10 (10 rows) and the ROW function returns the row number for each row in that range inside an array.
sum([list(range(x1, x2+1)) for x1, x2 in pg], )
NumPy - Array From Numerical Ranges, In this chapter, we will see how to create an array from numerical ranges. returns an ndarray object containing evenly spaced values within a given range. Given two arrays of integers nums and index. Your task is to create target array under the following rules: Initially target array is empty. From left to right read nums[i] and index[i], insert at index index[i] the value nums[i] in target array. Repeat the previous step until there are no elements to read in nums and index. Return the target
l =  for r in pg: l.extend(range(r, r+1))
Excel Cells & Ranges - Working With Arrays, It can be more efficient to load the values from a range into an array, process the data and then write it back rather than access each cell individually. Dim First, let’s create a one-dimensional array or an array with a rank 1. arange is a widely used function to quickly create an array. Passing a value 20 to the arange function creates an array with values ranging from 0 to 19. 1 2 3 import Numpy as np array = np.arange(20) array
One more example using list comprehension
a = [(10, 19), (30, 35)] b = [j for i in a for j in range(i, i+1)] print(b) #output [10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 30, 31, 32, 33, 34, 35]
range - Manual, range — Create an array containing a range of elements If a step value is given, it will be used as the increment between elements in the sequence. step In this article we will discuss how to create a Numpy array of evenly spaced numbers over a given interval using numpy.arrange(). numpy.arrange() Python’s numpy module provides a function to create an Numpy Array of evenly space elements within a given interval i.e. numpy.arange([start, ]stop, [step, ]dtype=None) Arguments:
Array and range in Ruby : CodesDope, Imagine that you have to make a software for a firm and they have to store the We access the particular element of an array using its index as given below:. I have a bunch of UI Control, created dynamically, and I want to access a specific control. For now, I have a array which contain these controls, but now I can only use myControlArray[i], I want to make a array with a tag, like myControlArray["nameTe
Array Subscript Ranges, Multidimensional subarrays can be specified using any combination of the above forms. For example, if arr is a 10x10 array, arr const generate_array = (start,end,step) => Array.from( range(start,end,step) ); Now you can generate a static array easily, const array1 = generate_array(1,10,2); const array1 = generate_array(1,7); But when something desires an iterator (or gives you the option to use an iterator) you can easily create one too.
- why when I only wrtie ar = list(range(val,val)), it won't work. I mean it gives me an error
- it should be
arr += list(range(val, val + 1)), did you notice
- yes I did, I'm asking about the above code, I'm just asking if I write the following without the for loop: arr = list(range(pg, pg + 1)) because I want to understand how this is working. if I write this it gives an error. notice I put pg instead of val
- Kindly go through the post, for better understanding.
- great but generator expression must be parenthesized
- After running this wizardry, I still don't understand it.
- @BenoîtPilatte: the comprehension makes a list of lists (each list is a
sumjust applies the
+operator between the lists, starting from an empty list
- thanks for bringing that to my attention. I have edited my code.