## How can you make a random number generator that chooses between the number 2 or 3. (not 1,2,3)

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Hi I am working on a monty hall generator and in part of my code I need it to generate random number 2 or 3. It cannot be 1,2,3 but the computer needs to select between 2 or 3. Thanks!

I have tried `randomCarDoor = ( rand() % 3 ) + 1;` but does not work.

`randomCarDoor = ( rand() % 3 ) + 1;`

It gives me the number `1,2,3` but I just want `2` and `3`

You can use the low order bit of the random value, but it is very risky as some pseudo-random number generators do not provide adequate dispersion on low order bits:

```int two_or_three = 2 + rand() % 2;
```

A much better way is to use the magnitude of the random number which is specified as having a flat distribution:

```int two_or_three = 2 + (rand() >= RAND_MAX / 2);
```

If you want numbers `1` and `3`, here is a simple solution for any pair:

```int random_value = (rand() < RAND_MAX / 2) ? 1 : 3;
```

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This is not trivial using `rand()` since a linear congruential generator typically alternates between odd and even numbers.

So one of the worst things you can do it to use a formula based on `rand() % 2`.

In this particular case, I suggest you draw based on

```n = rand();
```

and call it `1` if `n < RAND_MAX / 2` and `3` otherwise, which you can do with

```rand() < RAND_MAX / 2 ? 1 : 3
```

That might have adequate statistical properties - perhaps some unwanted autocorrelation - but probably no worse than `rand()` itself.

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