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Consider the pattern %at% where % can have zero or any number of occurrences of an alphabetical character. For example, the string `"BAT, FAT, LATER, HABIT" has three words that match the pattern.

How can this be done in Python?

import re

str_list = ['BAT', 'FAT', 'LATER', 'HABIT']    
counter = 0

for strr in str_list:
    if'at', strr, re.IGNORECASE):
        counter += 1   



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mylist = ['BAT', 'FAT', 'LATER', 'HABIT']

count = 0
for pattern in mylist:
    if 'at' in pattern.lower():
        count = count + 1    

Python String, 8. What is an f-string and how do you use it? New in python 3.6, f-strings make string interpolation really easy. Using� Return a list of the words in the string, using sep as the delimiter string. If maxsplit is given, at most maxsplit splits are done, the rightmost ones. If sep is not specified or None, any whitespace string is a separator. Except for splitting from the right, rsplit() behaves like split() which is described in detail below.

Use Counter to make the codes shorter:

from collections import Counter
str_list = ['BAT', 'FAT', 'LATER', 'HABIT']
my_counter = Counter('at' in word.lower() for word in str_list)
# 3

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  • Still not crystal, so in your example HAT CAT MATTER, we should be able to just print uhm 3? since AT came thrice?
  • @santosh Have you tried to code it?
  • @planet260 i am not able to get the logic
  • @user5173426 yes AT came thrice so i should print 3
  • Okay, does it have to be a pattern or just a searching for a substring?