Get days of week in Postgresql

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Had been trying to figure out a select query to display days of week such as Monday, Tuesday, Wednesday, etc. I ended up with a select query displaying dates of a week,

select ((date_trunc('week',current_date)::date) + (i+6)) as week_date 
  from generate_Series(0,6) i;

Is there a way to get the result as Monday, Tuesday and so on.

You could do just:

VALUES ('Sunday'), ('Monday'), ('Tuesday'), ('Wednesday'), ('Thursday'), ('Friday'), ('Saturday');

Get days of week in Postgresql, Just use extract: extract(dow from date_column::timestamp) from whatever_table; This returns 0 for Sunday, 1 for Monday,,6 for Saturday. Azure PostgreSQL - A Managed PostgreSQL Database Service for App Developers.

Just use extract:

extract(dow from date_column::timestamp)
from whatever_table;

This returns 0 for Sunday, 1 for Monday,...,6 for Saturday.

Edit: Or, since you apparently don't need anything that actually requires grabbing the day of week from a given date and you just want a single column with the fixed string values representing the names of the days of the week, just create a table...

PostgreSQL DATE_PART Function: Extract Year, Month, Week, etc , Learn how to the PostgreSQL DATE_PART function to extract subfields e.g., the year, allows you to retrieve subfields e.g., year, month, week from a date or time value. To get the month, you pass the month to the DATE_PART() function​:. To extract the day of week and or day of year from a time stamp, you use the following statement: SELECT date_part( 'dow' , TIMESTAMP '2017-03-18 10:20:30' ) dow, date_part( 'doy' , TIMESTAMP '2017-03-18 10:20:30' ) doy; dow | doy -----+----- 6 | 77 (1 row)

In Postgres 9 onwards there's:

to_char(date, 'dy');

which would return your date into the day of the week as a text value

PostgreSQL EXTRACT: Extracting Year, Month, Day, etc., from a Date, DAY, The day of the month (1-31), The number of days. DECADE, The decade that is the year divided by 10, Sames as TIMESTAMP. DOW, The day of week  The number of the week of the year that the day is in. By definition (ISO 8601), the first week of a year contains January 4 of that year. (The ISO-8601 week starts on Monday.) In other words, the first Thursday of a year is in week 1 of that year. (for timestamp values only)

The following query also works

select to_char((date_trunc('week',current_date)::date) + i,'Day') as wkday from generate_series(0,6) i

Making Postgres date_trunc() use a Sunday based week, Postgres provides a function called date_trunc() which rounds a In most cultures, Sunday is regarded as the first day of the week although many day from the result of date_trunc() and get the start of week in your calendar. Get days of week in Postgresql. Ask Question Asked 8 years, 4 months ago. Active 10 months ago. Viewed 36k times 20. 6. Had been trying to figure out a select query

creates a single field array that you unnest

select day_of_week
from unnest(
array
  ['Sunday',
    'Monday',
    'Tuesday',
    'Wednesday',
    'Thursday',
    'Friday',
   'Saturday']
) as day_of_week

Group dates by week in Postgres, The above example returns the first day of the week for the current moment which is a Monday. Postgres truncates dates to Monday rather than  Get day of week from Timestamp in Postgresql Extract get day of week from Timestamp in Postgresql Create the column which extracts day of week from timestamp column

PostgreSQL Date Functions (and 7 Ways to Use Them in Business , PostgreSQL date functions (like DATE_TRUNC, EXTRACT, and AGE) make To find the average weekday order volume, use the previous query as a subquery  To get the date of Monday in a given week, use SELECT TO_DATE (CONCAT (yearcol, weekcol), 'IYYYIW') FROM …. yearcol is a 4-digit year (e.g. 2013), and weekcol is an ISO week number (1-53). Read more about TO_DATE () in the PostgreSQL manual. How to get the number of weeks in a year

PostgreSQL and the calendar, One proposal around is to have 13 months of 28 days (4 weeks) each see how to get a decade of week numbers for the first day of the year. Extracting the day of week from a timestamp: SELECT EXTRACT(DOW FROM TIMESTAMP '2016-12-31 13:30:15'); The result is: 6 Extracting the day of year from a timestamp: SELECT EXTRACT(DOY FROM TIMESTAMP '2016-12-31 13:30:15'); It returned 366: 366 Extracting the epoch from a timestamp: SELECT EXTRACT(EPOCH FROM TIMESTAMP '2016-12-31 13:30:15');

PostgreSQL: date_part Function, The PostgreSQL date_part function extracts parts from a date. Drop User · Find Users · Find Users Logged In · Grant/Revoke Privileges · Indexes dow, Day of the week (0=Sunday, 1=Monday, 2=Tuesday, 6=Saturday). doy, Day of the year (1=first day of year, 365/366=last day of the year, depending if it is a leap year). The day of the week as Monday (1) to Sunday (7) SELECT EXTRACT(ISODOW FROM TIMESTAMP '2001-02-18 20:38:40'); Result: 7. This is identical to dow except for Sunday. This matches the ISO 8601 day of the week numbering. isoyear. The ISO 8601 week-numbering year that the date falls in (not applicable to intervals)

Comments
  • Hi jack, I dont want the number values of days, Instead i need the query to return all seven days as 'Sunday''Monday' etc. Can you suggest other possibilities?
  • @Flourida - As I pointed out in the comment section of Edwin's answer, if you don't need any of this dynamically generated, then why are you trying to do this in SQL? Just print out the strings "Sunday","Monday", etc, and be done with it.
  • That prints the value in different columns. how can i get it in single column?
  • @Flourida - Make a table with one column. These are fixed strings. There's nothing that you need to dynamically generate.
  • note that to_char() will give you a char e.g. select '|' || to_char(current_date, 'Day') || '|'; will give you |Tuesday | - so you probably need/want to trim.
  • note that to_char() will give you a char e.g. select '|' || to_char(current_date, 'Day') || '|'; will give you |Tuesday | - so you probably need/want to trim.