Reading a text file and splitting it into single words in python

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I have this text file made up of numbers and words, for example like this - 09807754 18 n 03 aristocrat 0 blue_blood 0 patrician and I want to split it so that each word or number will come up as a new line.

A whitespace separator would be ideal as I would like the words with the dashes to stay connected.

This is what I have so far:

f = open('words.txt', 'r')
for word in f:
    print(word)

not really sure how to go from here, I would like this to be the output:

09807754
18
n
3
aristocrat
...

Given this file:

$ cat words.txt
line1 word1 word2
line2 word3 word4
line3 word5 word6

If you just want one word at a time (ignoring the meaning of spaces vs line breaks in the file):

with open('words.txt','r') as f:
    for line in f:
        for word in line.split():
           print(word)    

Prints:

line1
word1
word2
line2
...
word6 

Similarly, if you want to flatten the file into a single flat list of words in the file, you might do something like this:

with open('words.txt') as f:
    flat_list=[word for line in f for word in line.split()]

>>> flat_list
['line1', 'word1', 'word2', 'line2', 'word3', 'word4', 'line3', 'word5', 'word6']

Which can create the same output as the first example with print '\n'.join(flat_list)...

Or, if you want a nested list of the words in each line of the file (for example, to create a matrix of rows and columns from a file):

with open('words.txt') as f:
    matrix=[line.split() for line in f]

>>> matrix
[['line1', 'word1', 'word2'], ['line2', 'word3', 'word4'], ['line3', 'word5', 'word6']]

If you want a regex solution, which would allow you to filter wordN vs lineN type words in the example file:

import re
with open("words.txt") as f:
    for line in f:
        for word in re.findall(r'\bword\d+', line):
            # wordN by wordN with no lineN

Or, if you want that to be a line by line generator with a regex:

 with open("words.txt") as f:
     (word for line in f for word in re.findall(r'\w+', line))

Reading a text file and splitting it into single words in python, Read through the file one line at a time using a for loop. Split the line into an array. This is because in this file each value is separated with a  The following Python program reading a text file and splitting it into single words in python example with open("my_file.txt", "r") as my_file: for line in my_file: str = line.split() print(str)

f = open('words.txt')
for word in f.read().split():
    print(word)

Python: Reading a text file, Splitting String/lines in python Splitting String by space Splitting on first following Python program reading a text file and splitting it into single words in python  To read the content of a text file line by line we are going to use a for loop that will loop through and extract each line of the text file one at a time. It will stop looping only once the it will have reached the last line. Check this animation that explains this process:

As supplementary, if you are reading a vvvvery large file, and you don't want read all of the content into memory at once, you might consider using a buffer, then return each word by yield:

def read_words(inputfile):
    with open(inputfile, 'r') as f:
        while True:
            buf = f.read(10240)
            if not buf:
                break

            # make sure we end on a space (word boundary)
            while not str.isspace(buf[-1]):
                ch = f.read(1)
                if not ch:
                    break
                buf += ch

            words = buf.split()
            for word in words:
                yield word
        yield '' #handle the scene that the file is empty

if __name__ == "__main__":
    for word in read_words('./very_large_file.txt'):
        process(word)

How to use Split in Python, filePath = "input.txt" wordList = [] wordCount = 0 #Read lines into a list file = open(​filePath, 'rU') for line in file: for word in line.split(): wordList.append(word)  Each line can be split into list using single space. Then, you can search the word you want in that list. Code: #open File with open("a.txt") as fh: for line in fh: #Split Paragraph on basis of '.' or ? or !. for l in re.split(r"\.|\?|\!",line): #Split line into list using space.

What you can do is use nltk to tokenize words and then store all of the words in a list, here's what I did. If you don't know nltk; it stands for natural language toolkit and is used to process natural language. Here's some resource if you wanna get started [http://www.nltk.org/book/]

import nltk 
from nltk.tokenize import word_tokenize 
file = open("abc.txt",newline='')
result = file.read()
words = word_tokenize(result)
for i in words:
       print(i)

The output will be this:

09807754
18
n
03
aristocrat
0
blue_blood
0
patrician

Accessing Each Word in a File : read « File « Python Tutorial, Once you've read a line into a string, you can use the split or rsplit functions using a space as a delimiter to return a list of the individual words  The split() method splits a string into a list. You can specify the separator, default separator is any whitespace. Note: When maxsplit is specified, the list will contain the specified number of elements plus one .

with open(filename) as file:
    words = file.read().split()

Its a List of all words in your file.

import re
with open(filename) as file:
    words = re.findall(r"([a-zA-Z\-]+)", file.read())

Reading Text File, Word By Word In Python, The task now is to understand how Python programs can read and write files. To this end, load the file into a text editor or viewer (one can use emacs , vim , more Instead of reading one line at a time, we can load all lines into a list of strings infile = open('data.txt', 'r') numbers = [float(w) for w in infile.read().split()] mean  with open(“hello.text”, “r”) as f: data = f.readlines() for line in data: words = line.split() print words If you wanted to use a colon instead of a space to split your text, you would simply change line.split() to line.split(“:”).

Reading data from file, I pulled out the words into a simple new-line-delimited text file. Then the Scanner will split on its default delimiter (=whitespace). We are going to create read line  In Python 3.5 or later, using pathlib you can copy text file contents into a variable and close the file in one line: from pathlib import Path txt = Path('data.txt').read_text() and then you can use str.replace to remove the newlines: txt = txt.replace(' ', '') share. Share a link to this answer.

Reading a text file and splitting it into single words in java, In this tutorial, we'll be reading a big file line by line in Python with the read, The read method will read in all the data into one text string. The last explicit method, readlines , will read all the lines of a file and return them as a list of strings. fp: print("line {} contents {}".format(cnt, line)) record_word_cnt(line.strip​().split(' ')  Assuming a following text file (dict.txt) is present. 1 aaa 2 bbb 3 ccc. Following Python code reads the file using open() function. Each line as string is split at space character.

Read a File Line-by-Line in Python, Reading a text file and splitting it into single words in java. ArrayIndexOutOfBoundsException: 1' error This is what I have so far In your case there is a line which  A wrapper class is, as usual, the right Pythonic architecture for this (in Python 2.1 and earlier): . class Paragraphs: def _ _init_ _(self, fileobj, separator=' '): # Ensure that we get a line-reading sequence in the best way possible: import xreadlines try: # Check if the file-like object has an xreadlines method self.seq = fileobj.xreadlines( ) except AttributeError: # No, so fall back to

Comments
  • Does that data literally have quotes around it? Is it "09807754 18 n 03 aristocrat 0 blue_blood 0 patrician" or 09807754 18 n 03 aristocrat 0 blue_blood 0 patrician in the file?
  • I follow-up with comment above. Does that data literally have quotes around it
  • How a file object is iterable (for line in f:)?
  • @haccks: It is the suggested idiom for looping line-by-line over a file. See also this SO post
  • I just wanted to know the mechanism behind this; how it works?
  • The open creates a file object. Python file objects support line-by-line iteration for text files (binary files are read in one gulp...) So each loop in the for loop is a line for a text file. At the end of the file, the file object raises StopIteration and we are done with the file. More understanding, of the mechanism is beyond what I can do in a comments.
  • You can also load into main memory and use "re" library like here stackoverflow.com/questions/7633274/…
  • For those interested in performance, this is an order of magnitude faster than the itertools answer.
  • why 10240 ? Im assuming that bytes? So around 10kb? How big can the buffer be and if I am interested in performance is smaller or larger buf better?