## Python divide a list of ints on every recurring specific int in list

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How can I change a list like

`[30,20,0,48,20,10,20,0,30]`

to:

`[[30,20],[48,20,10,20],]`

by dividing it everytime there is a `0` in the list? I have tried many ways but they all take up too much lines to make sense (10 lines). I have looked at many list-splitting questions on stack overflow and I cant find anything that works.

EDIT:

I was asking if there was any way to do list.split(0) or something like that, but it appears that the answer is that there is no way to do that. I wanted to know if I can do it in one line or if there is any way I can use a common module. I have already tried doing it in multiple lines, it has worked, but I think it is inconvenient.

EDIT 2:

The code I tried was:

```list = [30,20,0,48,20,10,20,0,30]  #1, 1 list
newlist = []                       #2, 2 lists
addinglist = []                    #3, 3 lists
for x in list:                     #4
if x == 0:                     #5
else:                          #8
list = newlist                     #11 lines, 3 lists.
```

The code requires 11 lines and 3 lists (one getting modified and the other two are useless).

This works:

```x=[10,20,30,0,4,5,6,0,1,1,1,1,1,1,0,1]

output=[]
temp=[]
for i in x:
if i==0:
output.append(temp)
temp=[]
else:
temp.append(i)
output.append(temp)
```

Where output is:

```[[10, 20, 30], [4, 5, 6], [1, 1, 1, 1, 1, 1], ]
```

The code quite short, but I'm sure there are solutions that are more succinct.

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I wanted to know if I can do it in one line or if there is any way I can use a common module.

Yes, to both. You're trying to group data so `groupby` in `itertools` is your friend:

```from itertools import groupby

data = [30, 20, 0, 48, 20, 10, 20, 0, 30]

result = [list(group) for non_zero, group in groupby(data, lambda n: n != 0) if non_zero]

print(result)
```

OUTPUT

```> python3 test.py
[[30, 20], [48, 20, 10, 20], ]
>
```

We're using a key function to bundle the data based on whether it's zero or not. The `group` variable contains the bundles; the `non_zero` variable (aka `key`) is a boolean indicating if it's a bundle we want.

How to Use sorted() and sort() in Python – Real Python, In this example, a list of integers is defined, and then sorted() is called with the numbers We will cover the specific order of the output and why it is that way shortly: >>> >>> string_value = 'I like to sort' >>> sorted_string = sorted(​string_value.split()) > Each element in mixed_numbers has int() called on it to convert any str  The python function randint can be used to generate a random integer in a chosen interval [a,b]: >>> import random >>> random.randint(0,10) 7 >>> random.randint(0,10) 0 A list of random numbers can be then created using python list comprehension approach:

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3. An Informal Introduction to Python, 4 >>> (50-5*6)/4 5.0 >>> 8/5 # Fractions aren't lost when dividing integers 1.6 To do integer division and get an integer result, discarding any Strings can be concatenated (glued together) with the + operator, and repeated with *: are immutable, it is possible to change individual elements of a list:. Looking to modify an item within a list in Python? If so, I’ll show you the steps to accomplish this goal using a simple example. Steps to Modify an Item Within a List in Python Step 1: Create a List. To start, create a list in Python. For demonstration purposes, I created a list of names using this syntax:

• This can be shortened to `final = []` and `[final.append([]) if elem == 0 else final[-1].append(elem) for elem in +x]` using a list comprehension, and it will be two lines.