## Using insertion sort on a singly linked list

insertion sort doubly linked list

bubble sort linked list

how to sort a linked list in java without using collections

insertion sort linked list time complexity

selection sort linked list

sort linked list ascending order c++

insert into sorted list

So I have an assignment where I'm giving a random list of number and I need to sort them using insertion sort. I must use a singly linked list. I looked around at other posts but none seem to help. I get what insertion sort is but I just don't know how to write it in code.

Node* insertion_sort(Node* head) { Node* temp = head_ptr; while((head->n < temp->n) && (temp != NULL)) temp = temp->next; head->next = temp->next; temp->next = head; head->prev = temp; }

I dont know if this is right or what to do now

struct node { int data; struct node *next; }; void insertion(struct node **head) { if((*head)== NULL || (*head)->next == NULL) { return; } struct node *t1 = (*head)->next; while(t1 != NULL) { int sec_data = t1->data; int found = 0; struct node *t2 = *head; while(t2 != t1) { if(t2->data > t1->data && found == 0) { sec_data = t2->data; t2->data = t1->data; found = 1; t2 = t2->next; } else { if(found == 1) { int temp = sec_data; sec_data = t2->data; t2->data = temp; } t2 = t2->next; } } t2->data = sec_data; t1 = t1->next; } }

**Sort a linked list using Insertion Sort,** struct node { int data; struct node *next; }; void insertion(struct node **head) { if((*head)== NULL || (*head)->next == NULL) { return; } struct node *t1 Either start from the beginning of the list, going forward until you find the correct position. Once you do, you insert the item there and you continue your insertion sort. This is the simplest solution if you have a singly-linked list. You go backwards, until you find the correct spot for the item.

Let's think about how Insertion Sort works: It "splits" (in theory) the list into three groups: the sorted subset (which may be empty), the current item and the unsorted subset (which may be empty). Everything before the current item is sorted. Everything after the current item may or may not be sorted. The algorithm checks the *current* item, comparing it with the next item. Remember that the first item after the current item belongs to the unsorted subset.

Let's assume that you are sorting integers in increasing order (so given "3,1,5,2,4" you want to get "1,2,3,4,5"). You set your current item to the first item in the list. Now you begin sorting:

If the next item is greater than the current item, you don't need to sort that item. Just make it "current item" and continue.

If the next item is less than the current item then you have some work to do. First, save the next item somewhere - let's say in a pointer called temp - and then "remove" the next item from the list, by making current->next = current->next->next. Now, you need to find right place for the removed item. You can do this in two ways:

- Either start from the beginning of the list, going forward until you find the correct position. Once you do, you insert the item there and you continue your insertion sort. This is the simplest solution if you have a singly-linked list.
- You go backwards, until you find the correct spot for the item. Once you do, you insert the item there and you continue your insertion sort. This is a bit more involved but can work well if you have a doubly-linked list.

You continue this process until you reach the end of the list. Once you reach it, you know that you have completed your insertion sort and the list is in the correct sorted order.

I hope this helps.

**Using insertion sort on a singly linked list,** The Code can be found at: https://quinston.com/code-snippets https://github.com/graphoarty Duration: 7:43
Posted: 24 Jan 2015 Algorithm for Insertion Sort for Singly Linked List : Create an empty sorted (or result) list Traverse the given list, do following for every node. Insert current node in sorted way in sorted or result list. Change head of given linked list to head of sorted (or result) list.

Think about this - if the list is empty, `temp`

will initially be `NULL`

, so you get undefined behavior when you do `temp->next = head;`

.

Try some debugging, it will surely help. You'll probably either want to keep the previous node as well, so you can insert afterwards, or look 2 nodes forward.

**Trying to use an Insertion Sort On a Linked List and Failing ,** Below is simple insertion sort algorithm for linked list. 1) Create an empty sorted (or result) list 2) Traverse the given list, do following for every node. a) Insert current node in sorted way in sorted or result list. 3) Change head of given linked list to head of sorted (or result) list. Insertion sort is a comparison based sorting algorithm which can be utilized in sorting a Linked List as well. Insertion Sort is preferred for sorting when the data set is almost sorted. The slow random-access performance of a linked list makes some other algorithms such as Quick Sort perform poorly, and others such as Heap Sort completely impossible.

**Insertion Sort for Singly Linked List,** Add to List Share. Sort a linked list using insertion sort. Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. At each Insert into a Sorted Circular Linked List Definition for singly-linked list. 3. Use the insertionsort method to add (insert) a char and sort the linked list. You'll have to address four different cases in a insertion sort linked list: Case 1. An inserted node is the first one to be added to an empty list. Case 2.

void linked_list::insertion_sort() { node * p = head; node * currentNode = head->next; // The node that is being compared at the moment. node * previousNode = head; // The node previous to the node being compared at the moment. //We can return from the sorting if the length of the linked list is less than 2. if (p == nullptr || p->next == nullptr) { return; } while (currentNode != nullptr) { //If the current node is larger than or equal to the largest element of the sorted linked list on the left, we can move to the next element. //Helpful for an already sorted array. if(previousNode->value<=currentNode->value){ currentNode = currentNode->next; previousNode = previousNode->next; } else{ //If the element is the smaller than the head element we need to take care of the head element. if (head->value > currentNode->value) { previousNode->next = currentNode->next; currentNode->next = head; head = currentNode; }else { p = head; while (p->next != NULL && p->next->value < currentNode->value) { p = p->next; } previousNode->next = currentNode->next; currentNode->next = p->next; p->next = currentNode; } } currentNode = previousNode->next; } }

**Insertion Sort List,** Similarly, insertion sort begins with a single element and iteratively takes in void insertionSort() { // Initialize sorted linked list final Node<E> sorted = null; Selection Sort Algorithm: Iterate the given list N times where N is the number of elements in the list.In every iteration of selection sort, the minimum element (considering ascending order) from the unsorted subarray is picked and moved to the sorted subarray.

**Insertion Sort a Linked List - OpenGenus IQ,** The addtohead method isn't needed. Use the insertionsort method to add (insert) a char and sort the linked list. You'll have to address four different cases in a Given a singly linked list containing n nodes. The problem is to sort the list using recursive selection sort technique. The approach should be such that it involves swapping node links instead of swapping nodes data.

**c++,** This is my accepted answer for LeetCode problem - Sort a linked list using insertion sort in Java. It is a complete program. Before coding for that, here is an If the list is empty, both head and tail will point to a newly added node. If the list is not empty, the new node will be added to end of the list such that tail's next will point to a newly added node. This new node will become the new tail of the list. sortList () will sort the nodes of the list in ascending order.

**LeetCode Solution – Sort a linked list using insertion sort in Java,** Simple implementation of insertion sort on one-way linked list in C. insertion_sort_linked_list.c //List must be ended with next = null;. #include <stdio.h>. C program for Time Complexity plot of Bubble, Insertion and Selection Sort using Gnuplot Comparison among Bubble Sort, Selection Sort and Insertion Sort Sort a linked list of 0s, 1s and 2s

##### Comments

- What is
`head_ptr`

? What if`temp`

is`NULL`

right away? - Man, schools are crazy. It'd take me ages to get this right. I use
`std::sort`

. - Disclaimer: I'll be downvoting answers that post full code.
- @LightnessRacesinOrbit Certainly implementing low level algorithms isn't something you need to do all the time, but I'd argue that as a programmer you'd still have to at least 'get it'.
- Is this algorithm supposed to be sorting the whole list? or just inserting one item in a prior-sorted list? Not that it does
*neither*correctly, but the name implies you want to feed it a list head and get back a sorted list as a result. Is that correct? - This question is tagged C++, not Java.
- Welcome to Stack Overflow. Code-only answers are discouraged as they are not helpful for inexperience programmers. Please include an explanation for how this solves the question and how it improves upon the other upvoted answers to this 5 year old question.